blocks|key|913105|text|下面是一个正则表达式，用于匹配不是字母或数字的字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913106|[%5EA-Za-z0-9]%2B|code-block|syntax|javascript|913107|下面是执行regex替换的Python命令：|913108|re.sub('[%5EA-Za-z0-9]%2B',+'',+mystring)|913109|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here is a regex to match a string of characters that are not a letters or numbers:

<pre class="lang-none prettyprint-override"><code>[^A-Za-z0-9]+
</code></pre>

Here is the Python command to do a regex substitution:

<pre><code>re.sub('[^A-Za-z0-9]+', '', mystring)
</code></pre>

blocks|key|913280|text|更短的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913281|import+re
cleanString+=+re.sub('\W%2B','',+string+)|code-block|syntax|javascript|913282|如果您希望单词和数字之间有空格，请将'‘替换为’‘|913283|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Shorter way :

<pre><code>import re
cleanString = re.sub('\W+','', string )
</code></pre>

If you want spaces between words and numbers substitute '' with ' '

blocks|key|913247|text|#!/usr/bin/python
import+re

strs+=+"how+much+for+the+maple+syrup?+$20.99?+That's+ricidulous!!!"
print+strs
nstr+=+re.sub(r'[?%7C$%7C.%7C!]',r'',strs)
print+nstr
nestr+=+re.sub(r'[%5Ea-zA-Z0-9+]',r'',nstr)
print+nestr|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|913248|您可以添加更多特殊字符，这些字符将被替换为'‘，即不会删除任何字符。|unstyled|913249|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>#!/usr/bin/python
import re

strs = "how much for the maple syrup? $20.99? That's ricidulous!!!"
print strs
nstr = re.sub(r'[?|$|.|!]',r'',strs)
print nstr
nestr = re.sub(r'[^a-zA-Z0-9 ]',r'',nstr)
print nestr
</code></pre>

you can add more special character and that will be replaced by '' means nothing i.e they will be removed.

blocks|key|913445|text|Python+2.*|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913446|我认为只有filter(str.isalnum,+string)才能工作|offset|length|style|CODE|913447|In+[20]:+filter(str.isalnum,+'string+with+special+chars+like+!,#$%25+etcs.')
Out[20]:+'stringwithspecialcharslikeetcs'|code-block|syntax|javascript|913448|Python+3.*|913449|在Python3中，filter(+)函数将返回一个可迭代的对象(而不是与上面不同的字符串)。必须重新加入才能从itertable中获取字符串：|913450|''.join(filter(str.isalnum,+string))+|913451|或者在连接使用时传递list+(not+sure+but+can+be+fast+a+bit)|913452|''.join([*filter(str.isalnum,+string)])|913453|注意:从Python+>=+3.5解包到[*args]是有效的|913454|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/9061024/1673391|1|https://stackoverflow.com/a/33973612/1673391^0|0|5|R|0|0|0|A|9|0|0|A|4|G|U|0|0|0|K|7|4|D|1|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|1C|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1E|8|@$D|1F|E|1G|F|G]]|9|@]|A|$]]|$1|Q|3|R|5|J|7|1H|8|@]|9|@]|A|$K|L]]|$1|S|3|T|5|6|7|1I|8|@$D|1J|E|1K|F|G]]|9|@$D|1L|E|1M|1|1N]]|A|$]]|$1|U|3|V|5|J|7|1O|8|@]|9|@]|A|$K|L]]|$1|W|3|X|5|6|7|1P|8|@$D|1Q|E|1R|F|G]]|9|@$D|1S|E|1T|1|1U]]|A|$]]|$1|Y|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]]|Z|$10|$5|11|12|13|A|$14|15]]|16|$5|11|12|13|A|$14|17]]]]

<h3>Python 2.*</h3>

I think just <code>filter(str.isalnum, string)</code> works

<pre><code>In [20]: filter(str.isalnum, 'string with special chars like !,#$% etcs.')
Out[20]: 'stringwithspecialcharslikeetcs'
</code></pre>

<h3>Python 3.*</h3>

In Python3, <code>filter( )</code> function would return an itertable object (instead of string unlike in above). One has to join back to get a string from itertable:

<pre><code>''.join(filter(str.isalnum, string)) 
</code></pre>

or to pass <code>list</code> in join use (<a href="https://stackoverflow.com/a/9061024/1673391">not sure but can be fast a bit</a>) 

<pre><code>''.join([*filter(str.isalnum, string)])
</code></pre>

note: unpacking in <code>[*args]</code> valid from <a href="https://stackoverflow.com/a/33973612/1673391">Python >= 3.5</a>

blocks|key|913473|text|s+=+re.sub(r"[-()\"#/@;:<>{}`%2B=~%7C.!?,]",+"",+s)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|913474|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|913198|text|假设您想要使用正则表达式，并且想要/需要支持Unicode的、支持2to3的2.x代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913199|>>>+import+re
>>>+rx+=+re.compile(u'[\W_]%2B',+re.UNICODE)
>>>+data+=+u''.join(unichr(i)+for+i+in+range(256))
>>>+rx.sub(u'',+data)
u'0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz\xaa\xb2+[snip]+\xfe\xff'
>>>|code-block|syntax|javascript|913200|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Assuming you want to use a regex and you want/need Unicode-cognisant 2.x code that is 2to3-ready:

<pre><code>&gt;&gt;&gt; import re
&gt;&gt;&gt; rx = re.compile(u'[\W_]+', re.UNICODE)
&gt;&gt;&gt; data = u''.join(unichr(i) for i in range(256))
&gt;&gt;&gt; rx.sub(u'', data)
u'0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz\xaa\xb2 [snip] \xfe\xff'
&gt;&gt;&gt;
</code></pre>

blocks|key|697116|text|最通用的方法是使用unicodedata表的“类别”，它对每个字符进行分类。例如，以下代码仅根据可打印字符的类别过滤可打印字符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|697117|import+unicodedata
#+strip+of+crap+characters+(based+on+the+Unicode+database
#+categorization:
#+http://www.sql-und-xml.de/unicode-database/#kategorien

PRINTABLE+=+set(('Lu',+'Ll',+'Nd',+'Zs'))

def+filter_non_printable(s):
++++result+=+[]
++++ws_last+=+False
++++for+c+in+s:
++++++++c+=+unicodedata.category(c)+in+PRINTABLE+and+c+or+u'#'
++++++++result.append(c)
++++return+u''.join(result).replace(u'#',+u'+')|code-block|syntax|javascript|697118|查看上面给出的所有相关类别的URL。当然，您也可以按标点符号类别进行过滤。|697119|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The most generic approach is using the 'categories' of the unicodedata table which classifies every single character. E.g. the following code filters only printable characters based on their category:

<pre><code>import unicodedata
# strip of crap characters (based on the Unicode database
# categorization:
# http://www.sql-und-xml.de/unicode-database/#kategorien

PRINTABLE = set(('Lu', 'Ll', 'Nd', 'Zs'))

def filter_non_printable(s):
 result = []
 ws_last = False
 for c in s:
 c = unicodedata.category(c) in PRINTABLE and c or u'#'
 result.append(c)
 return u''.join(result).replace(u'#', u' ')
</code></pre>

Look at the given URL above for all related categories. You also can of course filter
by the punctuation categories.

blocks|key|697298|text|使用翻译：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|697299|import+string

def+clean(instr):
++++return+instr.translate(None,+string.punctuation+%2B+'+')|code-block|syntax|javascript|697300|注意:仅适用于ascii字符串。|697301|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use translate:

<pre><code>import string

def clean(instr):
 return instr.translate(None, string.punctuation + ' ')
</code></pre>

Caveat: Only works on ascii strings.

blocks|key|697490|text|对于其他语言，如德语、西班牙语、丹麦语、法语等包含特殊字符的语言(如德语"Umlaute“如ü、ä、ö)，只需将以下内容添加到正则表达式搜索字符串：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|697491|德语示例：|697492|re.sub('[%5EA-ZÜÖÄa-z0-9]%2B',+'',+mystring)|code-block|syntax|javascript|697493|entityMap^0|1A|1|1C|1|1E|1|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

For other languages like German, Spanish, Danish, French etc that contain special characters (like German &quot;Umlaute&quot; as <code>ü</code>, <code>ä</code>, <code>ö</code>) simply add these to the regex search string:
Example for German:
<pre><code>re.sub('[^A-ZÜÖÄa-z0-9]+', '', mystring)
</code></pre>

blocks|key|913645|text|这将删除字符串中的所有特殊字符、标点符号和空格，只包含数字和字母。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913646|import+re

sample_str+=+"Hel&&lo+%25%25+Wo$#rl@d"

#+using+isalnum()
print("".join(k+for+k+in+sample_str+if+k.isalnum()))


#+using+regex
op2+=+re.sub("[%5EA-Za-z]",+"",+sample_str)
print(f"op2+=+",+op2)


special_char_list+=+["$",+"@",+"#",+"&",+"%25"]

#+using+list+comprehension
op1+=+"".join([k+for+k+in+sample_str+if+k+not+in+special_char_list])
print(f"op1+=+",+op1)


#+using+lambda+function
op3+=+"".join(filter(lambda+x:+x+not+in+special_char_list,+sample_str))
print(f"op3+=+",+op3)|code-block|syntax|javascript|913647|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This will remove all special characters, punctuation, and spaces from a string and only have numbers and letters.
<pre><code>import re

sample_str = &quot;Hel&amp;&amp;lo %% Wo$#rl@d&quot;

# using isalnum()
print(&quot;&quot;.join(k for k in sample_str if k.isalnum()))


# using regex
op2 = re.sub(&quot;[^A-Za-z]&quot;, &quot;&quot;, sample_str)
print(f&quot;op2 = &quot;, op2)


special_char_list = [&quot;$&quot;, &quot;@&quot;, &quot;#&quot;, &quot;&amp;&quot;, &quot;%&quot;]

# using list comprehension
op1 = &quot;&quot;.join([k for k in sample_str if k not in special_char_list])
print(f&quot;op1 = &quot;, op1)


# using lambda function
op3 = &quot;&quot;.join(filter(lambda x: x not in special_char_list, sample_str))
print(f&quot;op3 = &quot;, op3)
</code></pre>

blocks|key|913524|text|import+re
my_string+=+"""Strings+are+amongst+the+most+popular+data+types+in+Python.+We+can+create+the+strings+by+enclosing+characters+in+quotes.+Python+treats+single+quotes+the+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|913525|与双引号相同。“|unstyled|913526|#+if+we+need+to+count+the+word+python+that+ends+with+or+without+','+or+'.'+at+end

count+=+0
for+i+in+text:
++++if+i.endswith("."):
++++++++text[count]+=+re.sub("%5E([a-z]%2B)(.)?$",+r"\1",+i)
++++count+%2B=+1
print("The+count+of+Python+:+",+text.count("python"))|913527|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>import re
my_string = """Strings are amongst the most popular data types in Python. We can create the strings by enclosing characters in quotes. Python treats single quotes the 
</code></pre>

same as double quotes."""

<pre><code># if we need to count the word python that ends with or without ',' or '.' at end

count = 0
for i in text:
 if i.endswith("."):
 text[count] = re.sub("^([a-z]+)(.)?$", r"\1", i)
 count += 1
print("The count of Python : ", text.count("python"))
</code></pre>

blocks|key|913706|text|10年后，我在下面写道，这是最好的解决方案。您可以删除/清除字符串中的所有特殊字符、标点符号、ASCII字符和空格。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|913707|from+clean_text+import+clean

string+=+'Special+$#!+characters+++spaces+888323'
new+=+clean(string,lower=False,no_currency_symbols=True,+no_punct+=+True,replace_with_currency_symbol='')
print(new)
Output+==>+'Special+characters+spaces+888323'
you+can+replace+space+if+you+want.
update+=+new.replace('+','')
print(update)
Output+==>+'Specialcharactersspaces888323'|code-block|syntax|javascript|913708|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

After 10 Years, below I wrote there is the best solution.
You can remove/clean all special characters, punctuation, ASCII characters and spaces from the string.
<pre><code>from clean_text import clean

string = 'Special $#! characters spaces 888323'
new = clean(string,lower=False,no_currency_symbols=True, no_punct = True,replace_with_currency_symbol='')
print(new)
Output ==&gt; 'Special characters spaces 888323'
you can replace space if you want.
update = new.replace(' ','')
print(update)
Output ==&gt; 'Specialcharactersspaces888323'
</code></pre>

blocks|key|913319|text|import+re
abc+=+"askhnl#$%25askdjalsdk"
ddd+=+abc.replace("#$%25","")
print+(ddd)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|913320|你会看到你的结果是|unstyled|913321|‘'askhnlaskdjalsdk|913322|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>import re
abc = "askhnl#$%askdjalsdk"
ddd = abc.replace("#$%","")
print (ddd)
</code></pre>

and you shall see your result as 

'askhnlaskdjalsdk

I need to remove all special characters, punctuation and spaces from a string so that I only have letters and numbers.

Remove all special characters, punctuation and spaces from string

我需要删除字符串中的所有特殊字符、标点符号和空格，以便只有字母和数字。

问删除字符串中的所有特殊字符、标点符号和空格
EN

回答 13

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