我正在学习Python。希望有人能给我指出正确的方向。
这就是我想做的事情:
def decorate(function):
def wrap_function(*args, **kwargs):
str = 'Hello!' # This is what I want
return function(*args, **kwargs)
return wrap_function
@decorate
def print_message():
# I'd like to pass 'str' as mentioned above
# to any functions' argument like below:
print(str) # 'str' is same as above
有什么想法吗?提前谢谢。
发布于 2009-12-27 17:50:58
您不能将其作为自己的名称传递,但可以将其添加到关键字中。
def decorate(function):
def wrap_function(*args, **kwargs):
kwargs['str'] = 'Hello!'
return function(*args, **kwargs)
return wrap_function
@decorate
def print_message(*args, **kwargs):
print(kwargs['str'])
或者,您可以命名它自己的参数:
def decorate(function):
def wrap_function(*args, **kwargs):
str = 'Hello!'
return function(str, *args, **kwargs)
return wrap_function
@decorate
def print_message(str, *args, **kwargs):
print(str)
类方法:
def decorate(function):
def wrap_function(*args, **kwargs):
str = 'Hello!'
args.insert(1, str)
return function(*args, **kwargs)
return wrap_function
class Printer:
@decorate
def print_message(self, str, *args, **kwargs):
print(str)
发布于 2015-03-07 18:52:43
如果你希望参数是“可选注入的”,只在函数实际接受它的情况下,使用类似这样的东西:
import inspect
def decorate(func):
def wrap_and_call(*args, **kwargs):
if 'str' in inspect.getargspec(func).args:
kwargs['str'] = 'Hello!'
return func(*args, **kwargs)
return wrap_and_call
@decorate
def func1(str):
print "Works! - " + str
@decorate
def func2():
print "Should work, also."
https://stackoverflow.com/questions/1965607
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