blocks|key|1537576|text|函数strip将删除字符串开头和结尾的空格。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1537577|my_str+=+"+++text+"
my_str+=+my_str.strip()|code-block|syntax|javascript|1537578|将my_str设置为"text"。|1537579|entityMap^0|2|5|0|0|1|6|A|6|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

The function <code>strip</code> will remove whitespace from the beginning and end of a string.

<pre><code>my_str = " text "
my_str = my_str.strip()
</code></pre>

will set <code>my_str</code> to <code>"text"</code>.

blocks|key|1322345|text|要删除某个字符之前的所有内容，请使用正则表达式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1322346|re.sub(r'%5E[%5Ea]*',+'')|code-block|syntax|javascript|1322347|删除第一个'a‘之前的所有内容。[%5Ea]可以替换为您喜欢的任何字符类，例如word字符。|offset|length|style|CODE|1322348|entityMap^0|0|0|G|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

To remove everything before a certain character, use a regular expression:

<pre><code>re.sub(r'^[^a]*', '')
</code></pre>

to remove everything up to the first 'a'. <code>[^a]</code> can be replaced with any character class you like, such as word characters.

blocks|key|1537708|text|如果你想去掉单词前后的空格，但保留中间的空格。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1537709|您可以使用：|1537710|word+=+'++Hello+World++'
stripped+=+word.strip()
print(stripped)|code-block|syntax|javascript|1537711|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you want to cut the whitespaces before and behind the word, but keep the middle ones. 
You could use: 

<pre><code>word = ' Hello World '
stripped = word.strip()
print(stripped)
</code></pre>

blocks|key|1537748|text|这个问题不涉及多行字符串，但这里是如何使用python's+standard+library+textwrap+module从多行字符串中去掉前导空格的方法。如果我们有一个这样的字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1537749|s+=+"""
++++line+1+has+4+leading+spaces
++++line+2+has+4+leading+spaces
++++line+3+has+4+leading+spaces
"""|code-block|syntax|javascript|1537750|如果我们使用print(s)，我们将得到如下输出：|style|CODE|1537751|>>>+print(s)
++++this+has+4+leading+spaces+1
++++this+has+4+leading+spaces+2
++++this+has+4+leading+spaces+3|1537752|如果我们使用textwrap.dedent|1537753|>>>+import+textwrap
>>>+print(textwrap.dedent(s))
this+has+4+leading+spaces+1
this+has+4+leading+spaces+2
this+has+4+leading+spaces+3|1537754|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/textwrap.html#textwrap.dedent^0|L|15|0|0|0|6|8|0|0|6|F|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|15|8|@$A|16|B|17|K|L]]|9|@]|C|$]]|$1|M|3|N|5|F|7|18|8|@]|9|@]|C|$G|H]]|$1|O|3|P|5|6|7|19|8|@$A|1A|B|1B|K|L]]|9|@]|C|$]]|$1|Q|3|R|5|F|7|1C|8|@]|9|@]|C|$G|H]]|$1|S|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]]]

The question doesn't address multiline strings, but here is how you would strip leading whitespace from a multiline string using <a href="https://docs.python.org/3/library/textwrap.html#textwrap.dedent" rel="noreferrer">python's standard library textwrap module</a>. If we had a string like:

<pre><code>s = """
 line 1 has 4 leading spaces
 line 2 has 4 leading spaces
 line 3 has 4 leading spaces
"""
</code></pre>

if we <code>print(s)</code> we would get output like:

<pre><code>&gt;&gt;&gt; print(s)
 this has 4 leading spaces 1
 this has 4 leading spaces 2
 this has 4 leading spaces 3
</code></pre>

and if we used <code>textwrap.dedent</code>:

<pre><code>&gt;&gt;&gt; import textwrap
&gt;&gt;&gt; print(textwrap.dedent(s))
this has 4 leading spaces 1
this has 4 leading spaces 2
this has 4 leading spaces 3
</code></pre>

blocks|key|1322478|text|清理文本时使用正则表达式是最佳实践|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1322479|def+removing_leading_whitespaces(text):
+++++return+re.sub(r"%5E\s%2B","",text)|code-block|syntax|javascript|1322480|应用上面的函数|1322481|removing_leading_whitespaces("++Example")
"++Example"+++->+"Example"

removing_leading_whitespaces("++Example++")
"++Example++"+->+"Example++"

removing_leading_whitespaces("++++Example")
"++++Example"+->+"Example"|1322482|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Using regular expressions when cleaning the text is the best practice
<pre><code>def removing_leading_whitespaces(text):
 return re.sub(r&quot;^\s+&quot;,&quot;&quot;,text)

</code></pre>
Apply the above function
<pre><code>removing_leading_whitespaces(&quot; Example&quot;)
&quot; Example&quot; -&gt; &quot;Example&quot;

removing_leading_whitespaces(&quot; Example &quot;)
&quot; Example &quot; -&gt; &quot;Example &quot;

removing_leading_whitespaces(&quot; Example&quot;)
&quot; Example&quot; -&gt; &quot;Example&quot;
</code></pre>

I have a text string that starts with a number of spaces, varying between 2 &amp; 4.

What is the simplest way to remove the leading whitespace? (ie. remove everything before a certain character?)

<pre><code>" Example" -&gt; "Example"
" Example " -&gt; "Example "
" Example" -&gt; "Example"
</code></pre>

How do I remove leading whitespace in Python?

我有一个文本字符串，它以一些空格开头，在2和4之间变化。删除前导空格的最简单方法是什么？(即是否删除某个字符之前的所有内容？)"  Example"   -> "Example""  Example  " -> "Example  ""    Example" -> "Example"

问如何删除Python中的前导空格？
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