blocks|key|87031|text|使用format()+function|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|87032|>>>+format(14,+'#010b')
'0b00001110'|code-block|syntax|javascript|87033|format()函数只是根据Format+Specification+mini+language对输入进行格式化。#使格式包含0b前缀，010大小使用0填充格式化输出以适应10个字符的宽度；2个字符用于0b前缀，另外8个字符用于二进制数字。|87034|这是最紧凑、最直接的选择。|87035|如果要将结果放入更大的字符串中，请使用formatted+string+literal+(3.6%2B)或使用str.format()，并将format()函数的第二个参数放在占位符{:..}的冒号后面|87036|>>>+value+=+14
>>>+f'The+produced+output,+in+binary,+is:+{value:#010b}'
'The+produced+output,+in+binary,+is:+0b00001110'
>>>+'The+produced+output,+in+binary,+is:+{:#010b}'.format(value)
'The+produced+output,+in+binary,+is:+0b00001110'|87037|碰巧，即使只是格式化单个值(因此不会将结果放入更大的字符串中)，使用格式化的字符串文字也比使用format()更快|87038|>>>+import+timeit
>>>+timeit.timeit("f_(v,+'#010b')",+"v+=+14;+f_+=+format")++#+use+a+local+for+performance
0.40298633499332936
>>>+timeit.timeit("f'{v:#010b}'",+"v+=+14")
0.2850222919951193|87039|但只有在紧凑循环中的性能很重要的情况下，我才会使用它，因为format(...)可以更好地传达意图。|87040|如果您不需要0b前缀，只需删除#并调整字段长度：|87041|>>>+format(14,+'08b')
'00001110'|87042|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/2/library/functions.html#format|1|http://docs.python.org/2/library/string.html#format-specification-mini-language|2|https://docs.python.org/3/reference/lexical_analysis.html#f-strings|3|https://docs.python.org/2/library/stdtypes.html#str.format^0|2|8|2|H|0|0|0|0|8|1L|1|1R|2|1W|3|23|1|2T|2|E|Y|1|0|0|1H|C|1W|8|2H|5|J|O|2|1H|C|3|0|0|1B|8|0|0|T|B|0|6|2|F|1|0|0^^$0|@$1|2|3|4|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@$9|1J|A|1K|1|1L]]|E|$]]|$1|F|3|G|5|H|7|1M|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1N|8|@$9|1O|A|1P|B|C]|$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]|$9|1W|A|1X|B|C]|$9|1Y|A|1Z|B|C]]|D|@$9|20|A|21|1|22]]|E|$]]|$1|M|3|N|5|6|7|23|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|24|8|@$9|25|A|26|B|C]|$9|27|A|28|B|C]|$9|29|A|2A|B|C]]|D|@$9|2B|A|2C|1|2D]|$9|2E|A|2F|1|2G]]|E|$]]|$1|Q|3|R|5|H|7|2H|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|2I|8|@$9|2J|A|2K|B|C]]|D|@]|E|$]]|$1|U|3|V|5|H|7|2L|8|@]|D|@]|E|$I|J]]|$1|W|3|X|5|6|7|2M|8|@$9|2N|A|2O|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|6|7|2P|8|@$9|2Q|A|2R|B|C]|$9|2S|A|2T|B|C]]|D|@]|E|$]]|$1|10|3|11|5|H|7|2U|8|@]|D|@]|E|$I|J]]|$1|12|3|-4|5|6|7|2V|8|@]|D|@]|E|$]]]|13|$14|$5|15|16|17|E|$18|19]]|1A|$5|15|16|17|E|$18|1B]]|1C|$5|15|16|17|E|$18|1D]]|1E|$5|15|16|17|E|$18|1F]]]]

Use the <a href="http://docs.python.org/2/library/functions.html#format" rel="noreferrer"><code>format()</code> function</a>:

<pre><code>&gt;&gt;&gt; format(14, '#010b')
'0b00001110'
</code></pre>

The <code>format()</code> function simply formats the input following the <a href="http://docs.python.org/2/library/string.html#format-specification-mini-language" rel="noreferrer">Format Specification mini language</a>. The <code>#</code> makes the format include the <code>0b</code> prefix, and the <code>010</code> size formats the output to fit in 10 characters width, with <code>0</code> padding; 2 characters for the <code>0b</code> prefix, the other 8 for the binary digits.

This is the most compact and direct option.

If you are putting the result in a larger string, use an <a href="https://docs.python.org/3/reference/lexical_analysis.html#f-strings" rel="noreferrer">formatted string literal</a> (3.6+) or use <a href="https://docs.python.org/2/library/stdtypes.html#str.format" rel="noreferrer"><code>str.format()</code></a> and put the second argument for the <code>format()</code> function after the colon of the placeholder <code>{:..}</code>:

<pre><code>&gt;&gt;&gt; value = 14
&gt;&gt;&gt; f'The produced output, in binary, is: {value:#010b}'
'The produced output, in binary, is: 0b00001110'
&gt;&gt;&gt; 'The produced output, in binary, is: {:#010b}'.format(value)
'The produced output, in binary, is: 0b00001110'
</code></pre>

As it happens, even for just formatting a single value (so without putting the result in a larger string), using a formatted string literal is faster than using <code>format()</code>:

<pre><code>&gt;&gt;&gt; import timeit
&gt;&gt;&gt; timeit.timeit("f_(v, '#010b')", "v = 14; f_ = format") # use a local for performance
0.40298633499332936
&gt;&gt;&gt; timeit.timeit("f'{v:#010b}'", "v = 14")
0.2850222919951193
</code></pre>

But I'd use that only if performance in a tight loop matters, as <code>format(...)</code> communicates the intent better.

If you did not want the <code>0b</code> prefix, simply drop the <code>#</code> and adjust the length of the field:

<pre><code>&gt;&gt;&gt; format(14, '08b')
'00001110'
</code></pre>

blocks|key|87044|text|您可以使用下面这样的内容|type|unstyled|depth|inlineStyleRanges|entityRanges|data|87045|("{:0%25db}"%25length).format(num)|code-block|syntax|javascript|87046|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use something like this 

<pre><code>("{:0%db}"%length).format(num)
</code></pre>

blocks|key|304308|text|我正在使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|304309|bin(1)[2:].zfill(8)|code-block|syntax|javascript|304310|将打印|304311|'00000001'|304312|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I am using

<pre><code>bin(1)[2:].zfill(8)
</code></pre>

will print 

<pre><code>'00000001'
</code></pre>

blocks|key|304346|text|您可以使用zfill：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|304347|print+str(1).zfill(2)+
print+str(10).zfill(2)+
print+str(100).zfill(2)|code-block|syntax|javascript|304348|打印：|304349|01
10
100|304350|我喜欢这个解决方案，因为它不仅在输出数字时有帮助，而且在需要将其赋给变量时也有帮助。例如，-x=+str(datetime.date.today().month).zfill(2)将返回2月份的x为'02‘。|304351|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can use zfill:

<pre><code>print str(1).zfill(2) 
print str(10).zfill(2) 
print str(100).zfill(2)
</code></pre>

prints:

<pre><code>01
10
100
</code></pre>

I like this solution, as it helps not only when outputting the number, but when you need to assign it to a variable... 
e.g. - 
x = str(datetime.date.today().month).zfill(2) will return x as '02' for the month of feb.

blocks|key|87079|text|有时你只想要一个简单的一行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|87080|binary+=+''.join(['{0:08b}'.format(ord(x))+for+x+in+input])|code-block|syntax|javascript|87081|Python+3|87082|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Sometimes you just want a simple one liner:

<pre><code>binary = ''.join(['{0:08b}'.format(ord(x)) for x in input])
</code></pre>

Python 3

blocks|key|87111|text|你可以使用Python语法中的rjust字符串方法:+string.rjust(length，fillchar)+fillchar是可选的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|87112|对于你的问题，你可以这样写|87113|'0b'%2B+'1'.rjust(8,'0)|code-block|syntax|javascript|87114|所以它将是'0b00000001‘|87115|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

you can use rjust string method of python 
syntax:
string.rjust(length, fillchar)
fillchar is optional 

and for your Question you acn write like this 

<pre><code>'0b'+ '1'.rjust(8,'0)
</code></pre>

so it wil be '0b00000001'

blocks|key|304424|text|我喜欢使用python+f-string格式化来处理一些更复杂的事情，比如在format中使用参数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|304425|>>>+x+=+5
>>>+n+=+8
>>>+print(f"{x:0{n}b}")
00000101|code-block|syntax|javascript|304426|在这里，我使用以下格式输出变量长度:我想让它左填充0，使其具有b+(二进制)格式的x+=+n。有关更多信息，请参阅前面答案中的格式规范迷你语言。|offset|length|style|CODE|304427|entityMap^0|0|0|P|1|V|1|15|1|19|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|N|$]]

I like python f-string formatting for a little more complex things like using a parameter in format:
<pre><code>&gt;&gt;&gt; x = 5
&gt;&gt;&gt; n = 8
&gt;&gt;&gt; print(f&quot;{x:0{n}b}&quot;)
00000101
</code></pre>
Here I print variable <code>x</code> with following formatting: I want it to be left-filled with <code>0</code> to have length = <code>n</code>, in <code>b</code> (binary) format. See Format Specification Mini-Language from previous answers for more.

I'm trying to convert an integer to binary using the bin() function in Python. However, it always removes the leading zeros, which I actually need, such that the result is always 8-bit:

Example:

<pre><code>bin(1) -&gt; 0b1

# What I would like:
bin(1) -&gt; 0b00000001
</code></pre>

Is there a way of doing this?

Convert to binary and keep leading zeros

我正在尝试使用Python中的bin()函数将整数转换为二进制。但是，它总是删除前导零，这是我实际需要的，这样结果总是8位的：示例：bin(1) -> 0b1# What I would like:bin(1) -> 0b00000001有没有办法做到这一点？

问转换为二进制并保留前导零
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