我有一个C函数,它需要一个list \0结尾的字符串作为输入:
void external_C( int length , const char ** string_list) {
// Inspect the content of string_list - but not modify it.
}
在python (带有ctype)中,我想根据python字符串的列表调用此函数:
def call_c( string_list ):
lib.external_C( ?? )
call_c( ["String1" , "String2" , "The last string"])
关于如何在python端构建数据结构,有什么建议吗?注意,我保证C函数不会改变string_list中字符串的内容。
问候
joakim
发布于 2010-08-16 23:50:40
def call_c(L):
arr = (ctypes.c_char_p * len(L))()
arr[:] = L
lib.external_C(len(L), arr)
发布于 2010-08-17 01:48:27
非常感谢你,这真是太棒了。我还做了另一种变种,像这样:
def call_c( L ):
arr = (ctypes.c_char_p * (len(L) + 1))()
arr[:-1] = L
arr[ len(L) ] = None
lib.external_C( arr )
然后在C-function中,我遍历(char **)列表,直到找到NULL。
发布于 2018-12-08 23:50:11
使用ctype
创建过期列表(字符串)
expiries = ["1M", "2M", "3M", "6M","9M", "1Y", "2Y", "3Y","4Y", "5Y", "6Y", "7Y","8Y", "9Y", "10Y", "11Y","12Y", "15Y", "20Y", "25Y", "30Y"]
发送字符串数组的逻辑
通过在数组中循环将字符串数组转换为字节数组
expiries_bytes = []
for i in range(len(expiries)):
expiries_bytes.append(bytes(expiries[i], 'utf-8'))
用于初始化长度为数组的指针的逻辑ctype
expiries_array = (ctypes.c_char_p * (len(expiries_bytes)+1))()
将字节数组赋值给指针
expiries_array[:-1] = expiries_bytes
https://stackoverflow.com/questions/3494598
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