blocks|key|296225|text|您可以使用此函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|296226|function+str_lreplace($search,+$replace,+$subject)
{
++++$pos+=+strrpos($subject,+$search);

++++if($pos+!==+false)
++++{
++++++++$subject+=+substr_replace($subject,+$replace,+$pos,+strlen($search));
++++}

++++return+$subject;
}|code-block|syntax|javascript|296227|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this function:

<pre><code>function str_lreplace($search, $replace, $subject)
{
 $pos = strrpos($subject, $search);

 if($pos !== false)
 {
 $subject = substr_replace($subject, $replace, $pos, strlen($search));
 }

 return $subject;
}
</code></pre>

blocks|key|3233654|text|这也是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3233655|function+str_lreplace($search,+$replace,+$subject)
{
++++return+preg_replace('~(.*)'+.+preg_quote($search,+'~')+.+'(.*?)~',+'$1'+.+$replace+.+'$2',+$subject,+1);
}|code-block|syntax|javascript|3233656|更新更简明一点(http://ideone.com/B8i4o)：|offset|length|style|BOLD|3233657|function+str_lreplace($search,+$replace,+$subject)
{
++++return+preg_replace('~(.*)'+.+preg_quote($search,+'~')+.+'~',+'$1'+.+$replace,+$subject,+1);
}|3233658|entityMap|0|LINK|mutability|MUTABLE|url|http://ideone.com/B8i4o^0|0|0|0|2|8|N|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@$I|11|J|12|1|13]]|A|$]]|$1|M|3|N|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

This will also work:

<pre><code>function str_lreplace($search, $replace, $subject)
{
 return preg_replace('~(.*)' . preg_quote($search, '~') . '(.*?)~', '$1' . $replace . '$2', $subject, 1);
}
</code></pre>

UPDATE Slightly more concise version (<a href="http://ideone.com/B8i4o" rel="noreferrer">http://ideone.com/B8i4o</a>):

<pre><code>function str_lreplace($search, $replace, $subject)
{
 return preg_replace('~(.*)' . preg_quote($search, '~') . '~', '$1' . $replace, $subject, 1);
}
</code></pre>

blocks|key|295544|text|$string+=+'this+is+my+world,+not+my+world';
$find+=+'world';
$replace+=+'farm';
$result+=+preg_replace(strrev("/$find/"),strrev($replace),strrev($string),1);
echo+strrev($result);+//output:+this+is+my+world,+not+my+farm|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|295545|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$string = 'this is my world, not my world';
$find = 'world';
$replace = 'farm';
$result = preg_replace(strrev("/$find/"),strrev($replace),strrev($string),1);
echo strrev($result); //output: this is my world, not my farm
</code></pre>

blocks|key|3019386|text|另一个1行代码，但不含preg：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3019387|$subject+=+'bourbon,+scotch,+beer';
$search+=+',';
$replace+=+',+and';

echo+strrev(implode(strrev($replace),+explode(strrev($search),+strrev($subject),+2)));+//output:+bourbon,+scotch,+and+beer|code-block|syntax|javascript|3019388|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another 1-liner but without preg:

<pre><code>$subject = 'bourbon, scotch, beer';
$search = ',';
$replace = ', and';

echo strrev(implode(strrev($replace), explode(strrev($search), strrev($subject), 2))); //output: bourbon, scotch, and beer
</code></pre>

blocks|key|3233704|text|在reg表达式上使用"$“以匹配字符串的结尾|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3233705|$string+=+'The+quick+brown+fox+jumps+over+the+lazy+fox';
echo+preg_replace('/fox$/',+'dog',+$string);

//output
'The+quick+brown+fox+jumps+over+the+lazy+dog'|code-block|syntax|javascript|3233706|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the "$" on a reg expression to match the end of the string

<pre><code>$string = 'The quick brown fox jumps over the lazy fox';
echo preg_replace('/fox$/', 'dog', $string);

//output
'The quick brown fox jumps over the lazy dog'
</code></pre>

blocks|key|298224|text|下面的相当紧凑的解决方案使用PCRE+positive+lookahead+assertion来匹配感兴趣的子串的最后一个匹配项，也就是说，子串的匹配项后面没有跟在同一子字符串的任何其他匹配项。因此，该示例将last+'fox'替换为'dog'。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|298225|$string+=+'The+quick+brown+fox,+fox,+fox+jumps+over+the+lazy+fox!!!';
echo+preg_replace('/(fox(?!.*fox))/',+'dog',+$string);|code-block|syntax|javascript|298226|输出:1|298227|The+quick+brown+fox,+fox,+fox+jumps+over+the+lazy+dog!!!|298228|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/regexp.reference.assertions.php^0|2W|A|39|5|E|X|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

The following rather compact solution uses the <a href="http://php.net/manual/en/regexp.reference.assertions.php" rel="noreferrer">PCRE positive lookahead assertion</a> to match the last occurrence of the substring of interest, that is, an occurrence of the substring which is not followed by any other occurrences of the same substring. Thus the example replaces the <code>last 'fox'</code> with <code>'dog'</code>.

<pre><code>$string = 'The quick brown fox, fox, fox jumps over the lazy fox!!!';
echo preg_replace('/(fox(?!.*fox))/', 'dog', $string);
</code></pre>

OUTPUT:&nbsp;

<pre><code>The quick brown fox, fox, fox jumps over the lazy dog!!!
</code></pre>

blocks|key|298230|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|298231|$str+=+'Hello+world';
$str+=+rtrim($str,+'world')+.+'John';|code-block|syntax|javascript|298232|结果是'Hello+John'；|298233|问候|298234|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You could do this:

<pre><code>$str = 'Hello world';
$str = rtrim($str, 'world') . 'John';
</code></pre>

Result is 'Hello John';

Regards

blocks|key|296287|text|您可以使用strrpos()查找最后一个匹配项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|296288|$string+=+"picture_0007_value";
$findChar+=strrpos($string,"_");

$string[$findChar]=".";

echo+$string;|code-block|syntax|javascript|296289|输出:+picture_0007.value|296290|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use strrpos() to find last match.

<pre><code>$string = "picture_0007_value";
$findChar =strrpos($string,"_");

$string[$findChar]=".";

echo $string;
</code></pre>

Output : picture_0007.value

blocks|key|3233769|text|$string+=+"picture_0007_value";
$findChar+=strrpos($string,"_");
if($findChar+!==+FALSE)+{
++$string[$findChar]=".";
}

echo+$string;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3233770|除了代码中的错误，Faruk+Unal有最好的答案。一个函数就可以做到这一点。|unstyled|3233771|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$string = "picture_0007_value";
$findChar =strrpos($string,"_");
if($findChar !== FALSE) {
 $string[$findChar]=".";
}

echo $string;
</code></pre>

Apart from the mistakes in the code, Faruk Unal has the best anwser. One function does the trick.

blocks|key|3019474|text|接受答案的速记|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3019475|function+str_lreplace($search,+$replace,+$subject){+
++++return+is_numeric($pos=strrpos($subject,$search))?
++++substr_replace($subject,$replace,$pos,strlen($search)):$subject;
}|code-block|syntax|javascript|3019476|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Shorthand for accepted answer

<pre><code>function str_lreplace($search, $replace, $subject){ 
 return is_numeric($pos=strrpos($subject,$search))?
 substr_replace($subject,$replace,$pos,strlen($search)):$subject;
}
</code></pre>

blocks|key|3019499|text|对于感兴趣的人:我已经编写了一个利用preg_match的函数，这样您就可以使用正则表达式从右侧进行替换。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3019500|function+preg_rreplace($search,+$replace,+$subject)+{
++++preg_match_all($search,+$subject,+$matches,+PREG_SET_ORDER);
++++$lastMatch+=+end($matches);

++++if+($lastMatch+&&+false+!==+$pos+=+strrpos($subject,+$lastMatchedStr+=+$lastMatch[0]))+{
++++++++$subject+=+substr_replace($subject,+$replace,+$pos,+strlen($lastMatchedStr));
++++}

++++return+$subject;
}|code-block|syntax|javascript|3019501|或者作为这两个选项的简写组合/实现：|3019502|function+str_rreplace($search,+$replace,+$subject)+{
++++return+(false+!==+$pos+=+strrpos($subject,+$search))+?
++++++++substr_replace($subject,+$replace,+$pos,+strlen($search))+:+$subject;
}
function+preg_rreplace($search,+$replace,+$subject)+{
++++preg_match_all($search,+$subject,+$matches,+PREG_SET_ORDER);
++++return+($lastMatch+=+end($matches))+?+str_rreplace($lastMatch[0],+$replace,+$subject)+:+$subject;
}|3019503|基于https://stackoverflow.com/a/3835653/3017716和https://stackoverflow.com/a/23343396/3017716|offset|length|3019504|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/3835653/3017716|1|https://stackoverflow.com/a/23343396/3017716^0|0|0|0|0|2|17|0|1A|18|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@$M|13|N|14|1|15]|$M|16|N|17|1|18]]|A|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

For the interested: I've written a function that utilises preg_match so that you're able to replace from right hand side using regex.

<pre><code>function preg_rreplace($search, $replace, $subject) {
 preg_match_all($search, $subject, $matches, PREG_SET_ORDER);
 $lastMatch = end($matches);

 if ($lastMatch &amp;&amp; false !== $pos = strrpos($subject, $lastMatchedStr = $lastMatch[0])) {
 $subject = substr_replace($subject, $replace, $pos, strlen($lastMatchedStr));
 }

 return $subject;
}
</code></pre>

Or as a shorthand combination/implementation of both options:

<pre><code>function str_rreplace($search, $replace, $subject) {
 return (false !== $pos = strrpos($subject, $search)) ?
 substr_replace($subject, $replace, $pos, strlen($search)) : $subject;
}
function preg_rreplace($search, $replace, $subject) {
 preg_match_all($search, $subject, $matches, PREG_SET_ORDER);
 return ($lastMatch = end($matches)) ? str_rreplace($lastMatch[0], $replace, $subject) : $subject;
}
</code></pre>

based on <a href="https://stackoverflow.com/a/3835653/3017716">https://stackoverflow.com/a/3835653/3017716</a> and <a href="https://stackoverflow.com/a/23343396/3017716">https://stackoverflow.com/a/23343396/3017716</a>

blocks|key|296321|text|这是一个古老的问题，但是为什么每个人都忽略了最简单的基于regexp的解决方案呢？正常的regexp量词是贪婪的，伙计们！如果你想找到一个模式的最后一个实例，只需把.*放在它前面。下面是操作步骤：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|296322|$text+=+"The+quick+brown+fox,+fox,+fox,+fox,+jumps+over+etc.";
$fixed+=+preg_replace("((.*)fox)",+"$1DUCK",+$text);
print($fixed);|code-block|syntax|javascript|296323|这将把"fox“的最后一个实例替换为”and“，就像它应该那样，并打印：|296324|The+quick+brown+fox,+fox,+fox,+DUCK,+jumps+over+etc.|296325|entityMap^0|2A|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

This is an ancient question, but why is everyone overlooking the simplest regexp-based solution? Normal regexp quantifiers are greedy, people! If you want to find the last instance of a pattern, just stick <code>.*</code> in front of it. Here's how:

<pre><code>$text = "The quick brown fox, fox, fox, fox, jumps over etc.";
$fixed = preg_replace("((.*)fox)", "$1DUCK", $text);
print($fixed);
</code></pre>

This will replace the last instance of "fox" to "DUCK", like it's supposed to, and print:

<pre class="lang-none prettyprint-override"><code>The quick brown fox, fox, fox, DUCK, jumps over etc.
</code></pre>

blocks|key|3233826|text|一个简短的版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3233827|$NewString+=+substr_replace($String,$Replacement,strrpos($String,$Replace),strlen($Replace));|code-block|syntax|javascript|3233828|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A short version:

<pre><code>$NewString = substr_replace($String,$Replacement,strrpos($String,$Replace),strlen($Replace));
</code></pre>

blocks|key|296342|text|虽然使用正则表达式的性能通常不如非正则表达式技术，但我确实欣赏它提供的控制和灵活性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|296343|在我的代码片段中，我将模式设置为不区分大小写(\i，尽管我的示例输入不会挑战此规则)，并包括单词边界(\b，尽管没有显式调用它们)。|offset|length|style|CODE|296344|我还将使用\K元字符来重置全字符串匹配，这样就不需要捕获组/反向引用。|296345|代码：(Demo)|296346|$search+=+'The';
$replace+=+'A';
$subject+=+"The+Quick+Brown+Fox+Jumps+Over+The+Lazy+Dog's+Thermos!";

echo+preg_replace(
+++++++++'/.*\K\b'+.+preg_quote($search,+'/')+.+'\b/i',
+++++++++$replace,
+++++++++$subject
+++++);|code-block|syntax|javascript|296347|输出：|296348|++The+Quick+Brown+Fox+Jumps+Over+A+Lazy+Dog's+Thermos!
#+%5E%5E%5E++++++++++++++++++++++++++++%5E++++++++++++%5E%5E%5E
#+not+replaced++++++++++++++++replaced++++++++not+replaced|296349|296350|无字词边界：(Demo)|296351|echo+preg_replace(
+++++++++'/.*\K'+.+preg_quote($search,+'/')+.+'/i',
+++++++++$replace,
+++++++++$subject
+++++);|296352|296353|++The+Quick+Brown+Fox+Jumps+Over+The+Lazy+Dog's+Armos!
#+%5E%5E%5E++++++++++++++++++++++++++++%5E%5E%5E++++++++++++%5E
#+not+replaced++++++++++++++not+replaced++++++++replaced|296354|entityMap|0|LINK|mutability|MUTABLE|url|https://3v4l.org/P5dCb|1|https://3v4l.org/Q8InS^0|0|N|2|1F|2|0|5|2|0|4|4|0|0|0|0|0|0|7|4|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1D|8|@$D|1E|E|1F|F|G]|$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|1I|8|@$D|1J|E|1K|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1L|8|@]|9|@$D|1M|E|1N|1|1O]]|A|$]]|$1|L|3|M|5|N|7|1P|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|S|3|T|5|N|7|1R|8|@]|9|@]|A|$O|P]]|$1|U|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]|$1|V|3|W|5|6|7|1T|8|@]|9|@$D|1U|E|1V|1|1W]]|A|$]]|$1|X|3|Y|5|N|7|1X|8|@]|9|@]|A|$O|P]]|$1|Z|3|R|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|10|3|11|5|N|7|1Z|8|@]|9|@]|A|$O|P]]|$1|12|3|-4|5|6|7|20|8|@]|9|@]|A|$]]]|13|$14|$5|15|16|17|A|$18|19]]|1A|$5|15|16|17|A|$18|1B]]]]

While using regex is typically less performant than non-regex techniques, I do appreciate the control and flexibility that it affords.
In my snippet, I will set the pattern to be case-insensitive (<code>\i</code>, although my sample input will not challenge this rule) and include word boundaries (<code>\b</code>, although they were not explicitly called for).
I am also going to use the <code>\K</code> metacharacter to reset the fullstring match so that no capture groups / backreferences are needed.
Code: (<a href="https://3v4l.org/P5dCb" rel="nofollow noreferrer">Demo</a>)
<pre><code>$search = 'The';
$replace = 'A';
$subject = &quot;The Quick Brown Fox Jumps Over The Lazy Dog's Thermos!&quot;;

echo preg_replace(
 '/.*\K\b' . preg_quote($search, '/') . '\b/i',
 $replace,
 $subject
 );
</code></pre>
Output:
<pre><code> The Quick Brown Fox Jumps Over A Lazy Dog's Thermos!
# ^^^ ^ ^^^
# not replaced replaced not replaced
</code></pre>
<hr />
Without word boundaries: (<a href="https://3v4l.org/Q8InS" rel="nofollow noreferrer">Demo</a>)
<pre><code>echo preg_replace(
 '/.*\K' . preg_quote($search, '/') . '/i',
 $replace,
 $subject
 );
</code></pre>
Output:
<pre><code> The Quick Brown Fox Jumps Over The Lazy Dog's Armos!
# ^^^ ^^^ ^
# not replaced not replaced replaced
</code></pre>

blocks|key|296362|text|下面修正了扎克的代码(https://stackoverflow.com/a/11144999/9996503)。小心使用正则表达式！请考虑以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|296363|$string+=+'Round+brackets+(parentheses)+"()",+square+brackets+"()"';
$find+=+'()';
$replace+=+'[]';
//+Zack's+code:
$result+=+preg_replace(strrev("/$find/"),strrev($replace),strrev($string),1);
var_dump($result);+//+Output:+NULL
//+Correct+code:
$result+=+strrev(preg_replace('/'.preg_quote(strrev($find)).'/',+strrev($replace),+strrev($string),+1));
echo+$result;+//Output:+Round+brackets+(parentheses)+"()",+square+brackets+"[]"|code-block|syntax|javascript|296364|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/11144999/9996503^0|B|18|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Below corrected zack's code (<a href="https://stackoverflow.com/a/11144999/9996503">https://stackoverflow.com/a/11144999/9996503</a>).
Be careful with regular expressions! Consider this:
<pre><code>$string = 'Round brackets (parentheses) &quot;()&quot;, square brackets &quot;()&quot;';
$find = '()';
$replace = '[]';
// Zack's code:
$result = preg_replace(strrev(&quot;/$find/&quot;),strrev($replace),strrev($string),1);
var_dump($result); // Output: NULL
// Correct code:
$result = strrev(preg_replace('/'.preg_quote(strrev($find)).'/', strrev($replace), strrev($string), 1));
echo $result; //Output: Round brackets (parentheses) &quot;()&quot;, square brackets &quot;[]&quot;
</code></pre>

Anyone know of a very fast way to replace the last occurrence of a string with another string in a string?
Note, the last occurrence of the string might not be the last characters in the string.
Example:
<pre><code>$search = 'The';
$replace = 'A';
$subject = 'The Quick Brown Fox Jumps Over The Lazy Dog';
</code></pre>
Expected Output:
<pre><code>The Quick Brown Fox Jumps Over A Lazy Dog
</code></pre>

Replace last occurrence of a string in a string

有没有人知道一种非常快速的方法，可以用字符串中的另一个字符串替换最后一个字符串？注意，字符串的最后一个匹配项可能不是字符串中的最后一个字符。示例：$search = 'The';$replace = 'A';$subject = 'The Quick Brown Fox Jumps Over The Lazy Dog'...

问替换字符串中最后一次出现的字符串
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