Servlet过滤器:如何从servletRequest获取所有头文件？
Servlet过滤器:如何从servletRequest获取所有头文件？
提问于 2014-08-11 23:44:19
下面是我的WebFilter的样子
@WebFilter("/rest/*")
public class AuthTokenValidatorFilter implements Filter {
@Override
public void init(final FilterConfig filterConfig) throws ServletException {
}
@Override
public void doFilter(final ServletRequest servletRequest, final ServletResponse servletResponse, final FilterChain filterChain) throws IOException, ServletException {
final Enumeration<String> attributeNames = servletRequest.getAttributeNames();
while (attributeNames.hasMoreElements()) {
System.out.println("{attribute} " + servletRequest.getParameter(attributeNames.nextElement()));
}
final Enumeration<String> parameterNames = servletRequest.getParameterNames();
while (parameterNames.hasMoreElements()) {
System.out.println("{parameter} " + servletRequest.getParameter(parameterNames.nextElement()));
}
filterChain.doFilter(servletRequest, servletResponse);
}
@Override
public void destroy() {
}
}我尝试在网上查找如何从request获取HTTP headers的值。
我没有找到任何东西，所以我尝试在不知道任何东西的情况下在servletRequest.getAttributeNames()和servletRequest.getParameterNames()上枚举，但我没有得到任何头部。
问题
如何获取来自请求的所有标头？
回答 3
Stack Overflow用户
回答已采纳
发布于 2014-08-11 23:45:49
将ServletRequest类型转换为HttpServletRequest (仅当ServletRequest request是instanceof HttpServletRequest时)。
然后，您可以使用HttpServletRequest.getHeader()和HttpServletRequest.getHeaderNames()方法。
如下所示：
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
HttpServletRequest httpRequest = (HttpServletRequest) request;
Enumeration<String> headerNames = httpRequest.getHeaderNames();
if (headerNames != null) {
while (headerNames.hasMoreElements()) {
System.out.println("Header: " + httpRequest.getHeader(headerNames.nextElement()));
}
}
//doFilter
chain.doFilter(httpRequest, response);
}Stack Overflow用户
发布于 2018-04-11 17:39:13
使用Java 8+，您可以使用流来收集请求头：
HttpServletRequest httpRequest = (HttpServletRequest) request;
Map<String, String> headers = Collections.list(httpRequest.getHeaderNames())
.stream()
.collect(Collectors.toMap(h -> h, httpRequest::getHeader));已更新
@Matthias提醒我，headers可以有多个值：
Map<String, List<String>>
Map<String, List<String>> headersMap = Collections.list(httpRequest.getHeaderNames())
.stream()
.collect(Collectors.toMap(
Function.identity(),
h -> Collections.list(httpRequest.getHeaders(h))
));org.springframework.http.HttpHeaders
HttpHeaders httpHeaders = Collections.list(httpRequest.getHeaderNames())
.stream()
.collect(Collectors.toMap(
Function.identity(),
h -> Collections.list(httpRequest.getHeaders(h)),
(oldValue, newValue) -> newValue,
HttpHeaders::new
));https://gist.github.com/Cepr0/fd5d9459f17da13b29126cf313328fe3
Stack Overflow用户
发布于 2019-07-09 18:54:26
您应该考虑到，相同的HTTP报头可能会多次出现，但具有不同的值：
Map<String, Serializable> headers = Collections.list(request.getHeaderNames()).stream().collect(Collectors.toMap(h -> h, h -> {
ArrayList<String> headerValues = Collections.list(request.getHeaders(h));
return headerValues.size() == 1 ? headerValues.get(0) : headerValues;
}));页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/25247218
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