我有一组构成闭合多段线形状()的点。现在我想复制/裁剪这个shape中某个图像中的所有像素,剩下的则是黑色/透明的。我该怎么做呢?
例如,我有这样的例子:
我想要得到的是:
发布于 2013-03-12 00:00:39
*编辑-已更新以处理具有alpha通道的图像。
这对我很有效:
对于接受掩码的函数,您可能只想将图像和掩码分开。然而,我相信这做了您特别要求的:
import cv2
import numpy as np
# original image
# -1 loads as-is so if it will be 3 or 4 channel as the original
image = cv2.imread('image.png', -1)
# mask defaulting to black for 3-channel and transparent for 4-channel
# (of course replace corners with yours)
mask = np.zeros(image.shape, dtype=np.uint8)
roi_corners = np.array([[(10,10), (300,300), (10,300)]], dtype=np.int32)
# fill the ROI so it doesn't get wiped out when the mask is applied
channel_count = image.shape[2] # i.e. 3 or 4 depending on your image
ignore_mask_color = (255,)*channel_count
cv2.fillPoly(mask, roi_corners, ignore_mask_color)
# from Masterfool: use cv2.fillConvexPoly if you know it's convex
# apply the mask
masked_image = cv2.bitwise_and(image, mask)
# save the result
cv2.imwrite('image_masked.png', masked_image)
发布于 2019-03-04 14:39:17
以下代码将有助于裁剪图像并将其置于白色背景中。
import cv2
import numpy as np
# load the image
image_path = 'input image path'
image = cv2.imread(image_path)
# create a mask with white pixels
mask = np.ones(image.shape, dtype=np.uint8)
mask.fill(255)
# points to be cropped
roi_corners = np.array([[(0, 300), (1880, 300), (1880, 400), (0, 400)]], dtype=np.int32)
# fill the ROI into the mask
cv2.fillPoly(mask, roi_corners, 0)
# The mask image
cv2.imwrite('image_masked.png', mask)
# applying th mask to original image
masked_image = cv2.bitwise_or(image, mask)
# The resultant image
cv2.imwrite('new_masked_image.png', masked_image)
输入图像:
遮罩图像:
结果输出图像:
https://stackoverflow.com/questions/15341538
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