blocks|key|604284|text|使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|604285|String+str+=+"testString";
char[]+charArray+=+str.toCharArray();
Character[]+charObjectArray+=+ArrayUtils.toObject(charArray);|code-block|syntax|javascript|604286|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use this:

<pre><code>String str = "testString";
char[] charArray = str.toCharArray();
Character[] charObjectArray = ArrayUtils.toObject(charArray);
</code></pre>

blocks|key|604267|text|为什么不自己写一个小方法呢？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|604268|public+Character[]+toCharacterArray(+String+s+)+{

+++if+(+s+==+null+)+{
+++++return+null;
+++}

+++int+len+=+s.length();
+++Character[]+array+=+new+Character[len];
+++for+(int+i+=+0;+i+<+len+;+i%2B%2B)+{
++++++/*+
++++++Character(char)+is+deprecated+since+Java+SE+9+&+JDK+9
++++++Link:+https://docs.oracle.com/javase/9/docs/api/java/lang/Character.html
++++++array[i]+=+new+Character(s.charAt(i));
++++++*/
++++++array[i]+=+s.charAt(i);
+++}

+++return+array;
}|code-block|syntax|javascript|604269|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Why not write a little method yourself

<pre><code>public Character[] toCharacterArray( String s ) {

 if ( s == null ) {
 return null;
 }

 int len = s.length();
 Character[] array = new Character[len];
 for (int i = 0; i &lt; len ; i++) {
 /* 
 Character(char) is deprecated since Java SE 9 &amp; JDK 9
 Link: https://docs.oracle.com/javase/9/docs/api/java/lang/Character.html
 array[i] = new Character(s.charAt(i));
 */
 array[i] = s.charAt(i);
 }

 return array;
}
</code></pre>

blocks|key|388140|text|在这种情况下，您必须编写自己的方法。使用循环并使用charAt(i)获取每个字符，并使用arrayname[i]+=+string.charAt[i]将其设置为您的Character[]数组。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|388141|entityMap^0|P|9|18|V|2A|B|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

You have to write your own method in this case. Use a loop and get each character using <code>charAt(i)</code> and set it to your <code>Character[]</code> array using <code>arrayname[i] = string.charAt[i]</code>.

blocks|key|388227|text|String#toCharArray返回一个char数组，您所拥有的是一个Character数组。在大多数情况下，使用char或Character都无关紧要，因为有autoboxing。在你的例子中，问题是数组没有自动装箱，我建议你使用字符数组(char[])。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|388228|entityMap|0|LINK|mutability|MUTABLE|url|http://www.java2s.com/Tutorial/Java/0040__Data-Type/AutoboxingUnboxingBooleanandCharacterValues.htm^0|0|I|M|4|11|9|1N|4|1S|9|3F|6|2A|A|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@$9|10|A|11|1|12]]|E|$]]|$1|F|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

<code>String#toCharArray</code> returns an array of <code>char</code>, what you have is an array of <code>Character</code>. In most cases it doesn't matter if you use <code>char</code> or <code>Character</code> as there is <a href="http://www.java2s.com/Tutorial/Java/0040__Data-Type/AutoboxingUnboxingBooleanandCharacterValues.htm" rel="nofollow">autoboxing</a>. The problem in your case is that arrays are not autoboxed, I suggest you use an array of char (<code>char[]</code>).

blocks|key|388267|text|我希望下面的代码能对你有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|388268|String+s="Welcome+to+Java+Programming";
char+arr[]=s.toCharArray();
for(int+i=0;i<arr.length;i%2B%2B){
++++System.out.println("Data+at+["%2Bi%2B"]="%2Barr[i]);
}|code-block|syntax|javascript|388269|它正在工作，输出是：|388270|Data+at+[0]=W
Data+at+[1]=e
Data+at+[2]=l
Data+at+[3]=c
Data+at+[4]=o
Data+at+[5]=m
Data+at+[6]=e
Data+at+[7]=+
Data+at+[8]=t
Data+at+[9]=o
Data+at+[10]=+
Data+at+[11]=J
Data+at+[12]=a
Data+at+[13]=v
Data+at+[14]=a
Data+at+[15]=+
Data+at+[16]=P
Data+at+[17]=r
Data+at+[18]=o
Data+at+[19]=g
Data+at+[20]=r
Data+at+[21]=a
Data+at+[22]=m
Data+at+[23]=m
Data+at+[24]=i
Data+at+[25]=n
Data+at+[26]=g|388271|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I hope the code below will help you.

<pre><code>String s="Welcome to Java Programming";
char arr[]=s.toCharArray();
for(int i=0;i&lt;arr.length;i++){
 System.out.println("Data at ["+i+"]="+arr[i]);
}
</code></pre>

It's working and the output is:

<pre><code>Data at [0]=W
Data at [1]=e
Data at [2]=l
Data at [3]=c
Data at [4]=o
Data at [5]=m
Data at [6]=e
Data at [7]= 
Data at [8]=t
Data at [9]=o
Data at [10]= 
Data at [11]=J
Data at [12]=a
Data at [13]=v
Data at [14]=a
Data at [15]= 
Data at [16]=P
Data at [17]=r
Data at [18]=o
Data at [19]=g
Data at [20]=r
Data at [21]=a
Data at [22]=m
Data at [23]=m
Data at [24]=i
Data at [25]=n
Data at [26]=g
</code></pre>

blocks|key|604467|text|此方法将字符串作为参数，并返回字符数组|type|unstyled|depth|inlineStyleRanges|entityRanges|data|604468|/**
+*+@param+sourceString
+*++++++++++++:String+as+argument
+*+@return+CharcterArray
+*/
public+static+Character[]+toCharacterArray(String+sourceString)+{
++++char[]+charArrays+=+new+char[sourceString.length()];
++++charArrays+=+sourceString.toCharArray();
++++Character[]+characterArray+=+new+Character[charArrays.length];
++++for+(int+i+=+0;+i+<+charArrays.length;+i%2B%2B)+{
++++++++characterArray[i]+=+charArrays[i];
++++}
++++return+characterArray;
}|code-block|syntax|javascript|604469|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This method take String as a argument and return the Character Array

<pre><code>/**
 * @param sourceString
 * :String as argument
 * @return CharcterArray
 */
public static Character[] toCharacterArray(String sourceString) {
 char[] charArrays = new char[sourceString.length()];
 charArrays = sourceString.toCharArray();
 Character[] characterArray = new Character[charArrays.length];
 for (int i = 0; i &lt; charArrays.length; i++) {
 characterArray[i] = charArrays[i];
 }
 return characterArray;
}
</code></pre>

blocks|key|388250|text|另一种方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|388251|String+str="I+am+a+good+boy";
++++char[]+chars=str.toCharArray();

++++Character[]+characters=new+Character[chars.length];
++++for+(int+i+=+0;+i+<+chars.length;+i%2B%2B)+{
++++++++characters[i]=chars[i];
++++++++System.out.println(chars[i]);
++++}|code-block|syntax|javascript|388252|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

another way to do it.

<pre><code>String str="I am a good boy";
 char[] chars=str.toCharArray();

 Character[] characters=new Character[chars.length];
 for (int i = 0; i &lt; chars.length; i++) {
 characters[i]=chars[i];
 System.out.println(chars[i]);
 }
</code></pre>

blocks|key|388290|text|如果您正在使用JTextField，那么它可能会很有帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|388291|public+JTextField+display;
String+number=e.getActionCommand();

display.setText(display.getText()%2Bnumber);

ch=number.toCharArray();
for(+int+i=0;+i<ch.length;+i%2B%2B)
++++System.out.println("in+array+a1=+"%2Bch[i]);|code-block|syntax|javascript|388292|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

if you are working with JTextField then it can be helpfull..

<pre><code>public JTextField display;
String number=e.getActionCommand();

display.setText(display.getText()+number);

ch=number.toCharArray();
for( int i=0; i&lt;ch.length; i++)
 System.out.println("in array a1= "+ch[i]);
</code></pre>

blocks|key|388309|text|链接总是最好的:D|type|unstyled|depth|inlineStyleRanges|entityRanges|data|388310|String+str+=+"somethingPutHere";
Character[]+c+=+ArrayUtils.toObject(str.toCharArray());|code-block|syntax|javascript|388311|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

chaining is always best :D

<pre><code>String str = "somethingPutHere";
Character[] c = ArrayUtils.toObject(str.toCharArray());
</code></pre>

blocks|key|604520|text|如果你不想依赖第三方API，这里有一个适用于JDK7或更低版本的有效代码。我没有像上面的其他解决方案那样实例化临时角色对象。foreach循环更具可读性，请看您自己:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|604521|public+static+Character[]+convertStringToCharacterArray(String+str)+{
++++if+(str+==+null+%7C%7C+str.isEmpty())+{
++++++++return+null;
++++}
++++char[]+c+=+str.toCharArray();
++++final+int+len+=+c.length;
++++int+counter+=+0;
++++final+Character[]+result+=+new+Character[len];
++++while+(len+>+counter)+{
++++++++for+(char+ch+:+c)+{
++++++++++++result[counter%2B%2B]+=+ch;
++++++++}
++++}
++++return+result;
}|code-block|syntax|javascript|604522|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you don't want to rely on third party API's, here is a working code for JDK7 or below. I am not instantiating temporary Character Objects as done by other solutions above. foreach loops are more readable, see yourself :)

<pre><code>public static Character[] convertStringToCharacterArray(String str) {
 if (str == null || str.isEmpty()) {
 return null;
 }
 char[] c = str.toCharArray();
 final int len = c.length;
 int counter = 0;
 final Character[] result = new Character[len];
 while (len &gt; counter) {
 for (char ch : c) {
 result[counter++] = ch;
 }
 }
 return result;
}
</code></pre>

blocks|key|604566|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|604567|String[]+arr+=+{+"abc",+"cba",+"dac",+"cda"+};
++++Map<Character,+Integer>+map+=+new+HashMap<>();
++++String+string+=+new+String();
++++for+(String+a+:+arr)+{
++++++++string+=+string.concat(a);

++++}
++++System.out.println(string);

++++for+(int+i+=+0;+i+<+string.length();+i%2B%2B)+{
++++++++if+(map.containsKey(string.charAt(i)))+{
++++++++++++map.put(string.charAt(i),+map.get(string.charAt(i))+%2B+1);

++++++++}+else+{
++++++++++++map.put(string.charAt(i),+1);

++++++++}
++++}
++++System.out.println(map);|code-block|syntax|javascript|604568|//输出put+{a=4，b=2，c=4，d=2}|604569|entityMap^0|0|0|0^^$0|@$1|2|3|-4|4|5|6|J|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|K|7|@]|8|@]|9|$D|E]]|$1|F|3|G|4|5|6|L|7|@]|8|@]|9|$]]|$1|H|3|-4|4|5|6|M|7|@]|8|@]|9|$]]]|I|$]]

<hr />
<pre><code>String[] arr = { &quot;abc&quot;, &quot;cba&quot;, &quot;dac&quot;, &quot;cda&quot; };
 Map&lt;Character, Integer&gt; map = new HashMap&lt;&gt;();
 String string = new String();
 for (String a : arr) {
 string = string.concat(a);

 }
 System.out.println(string);

 for (int i = 0; i &lt; string.length(); i++) {
 if (map.containsKey(string.charAt(i))) {
 map.put(string.charAt(i), map.get(string.charAt(i)) + 1);

 } else {
 map.put(string.charAt(i), 1);

 }
 }
 System.out.println(map);
</code></pre>
//out put {a=4, b=2, c=4, d=2}

I want to convert a <code>String</code> to an array of objects of <a href="http://docs.oracle.com/javase/7/docs/api/java/lang/Character.html" rel="noreferrer">Character</a> class but I am unable to perform the conversion. I know that I can convert a String to an array of primitive datatype type "char" with the <code>toCharArray()</code> method but it doesn't help in converting a String to an array of objects of <a href="http://docs.oracle.com/javase/7/docs/api/java/lang/Character.html" rel="noreferrer">Character</a> type.

How would I go about doing so?

Converting String to "Character" array in Java

我想将String转换为类的对象数组，但无法执行此转换。我知道可以使用toCharArray()方法将字符串转换为原始数据类型"char“的数组，但它对将字符串转换为类型的对象数组没有帮助。我该怎么做呢？

问在Java中将字符串转换为"Character“数组
EN

回答 11

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问在Java中将字符串转换为"Character“数组EN

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问在Java中将字符串转换为"Character“数组
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