解析node.js中的查询字符串
解析node.js中的查询字符串
提问于 2011-12-21 20:46:32
在这个"Hello World“示例中：
// Load the http module to create an http server.
var http = require('http');
// Configure our HTTP server to respond with Hello World to all requests.
var server = http.createServer(function (request, response) {
response.writeHead(200, {"Content-Type": "text/plain"});
response.end("Hello World\n");
});
// Listen on port 8000, IP defaults to 127.0.0.1
server.listen(8000);
// Put a friendly message on the terminal
console.log("Server running at http://127.0.0.1:8000/");如何从查询字符串中获取参数？
http://127.0.0.1:8000/status?name=ryan在文档中，他们提到：
node> require('url').parse('/status?name=ryan', true)
{ href: '/status?name=ryan'
, search: '?name=ryan'
, query: { name: 'ryan' }
, pathname: '/status'
}但是我不知道如何使用它。有谁能解释一下吗？
回答 4
Stack Overflow用户
回答已采纳
发布于 2011-12-21 21:14:01
您可以在请求回调中使用URL module中的parse方法。
var http = require('http');
var url = require('url');
// Configure our HTTP server to respond with Hello World to all requests.
var server = http.createServer(function (request, response) {
var queryData = url.parse(request.url, true).query;
response.writeHead(200, {"Content-Type": "text/plain"});
if (queryData.name) {
// user told us their name in the GET request, ex: http://host:8000/?name=Tom
response.end('Hello ' + queryData.name + '\n');
} else {
response.end("Hello World\n");
}
});
// Listen on port 8000, IP defaults to 127.0.0.1
server.listen(8000);我建议您阅读HTTP module documentation以了解您在createServer回调中得到了什么。您还应该看看像http://howtonode.org/这样的站点，并查看Express framework，以便更快地开始使用Node。
Stack Overflow用户
发布于 2013-08-14 03:45:06
还有QueryString module的parse()方法：
var http = require('http'),
queryString = require('querystring');
http.createServer(function (oRequest, oResponse) {
var oQueryParams;
// get query params as object
if (oRequest.url.indexOf('?') >= 0) {
oQueryParams = queryString.parse(oRequest.url.replace(/^.*\?/, ''));
// do stuff
console.log(oQueryParams);
}
oResponse.writeHead(200, {'Content-Type': 'text/plain'});
oResponse.end('Hello world.');
}).listen(1337, '127.0.0.1');Stack Overflow用户
发布于 2019-11-22 09:25:28
从Node.js 11开始，url.parse和Legacy URL API的其他方法是deprecated的(最初只在文档中)，支持standardized WHATWG URL API。新的API不提供将查询字符串解析为对象的功能。这可以使用querystring.parse方法来实现：
// Load modules to create an http server, parse a URL and parse a URL query.
const http = require('http');
const { URL } = require('url');
const { parse: parseQuery } = require('querystring');
// Provide the origin for relative URLs sent to Node.js requests.
const serverOrigin = 'http://localhost:8000';
// Configure our HTTP server to respond to all requests with a greeting.
const server = http.createServer((request, response) => {
// Parse the request URL. Relative URLs require an origin explicitly.
const url = new URL(request.url, serverOrigin);
// Parse the URL query. The leading '?' has to be removed before this.
const query = parseQuery(url.search.substr(1));
response.writeHead(200, { 'Content-Type': 'text/plain' });
response.end(`Hello, ${query.name}!\n`);
});
// Listen on port 8000, IP defaults to 127.0.0.1.
server.listen(8000);
// Print a friendly message on the terminal.
console.log(`Server running at ${serverOrigin}/`);如果您运行上面的脚本，您可以像这样测试服务器响应，例如：
curl -q http://localhost:8000/status?name=ryan
Hello, ryan!页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/8590042
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