假设我有一个包含以下内容的.csv
文件:
"text, with commas","another text",123,"text",5;
"some without commas","another text",123,"text";
"some text with commas or no",,123,"text";
如何通过PHP解析内容?
发布于 2012-02-04 15:30:49
只需使用函数解析CSV文件即可
http://php.net/manual/en/function.fgetcsv.php
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
发布于 2014-02-26 18:24:52
从PHP >= 5.3.0开始,答案稍微短了一点
$csvFile = file('../somefile.csv');
$data = [];
foreach ($csvFile as $line) {
$data[] = str_getcsv($line);
}
发布于 2015-06-19 14:40:21
使用方便的一行程序将CSV文件解析为数组
$csv = array_map('str_getcsv', file('data.csv'));
https://stackoverflow.com/questions/9139202
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