我有一个函数将字符串转换为十六进制,如下所示,
public static string ConvertToHex(string asciiString)
{
string hex = "";
foreach (char c in asciiString)
{
int tmp = c;
hex += String.Format("{0:x2}", (uint)System.Convert.ToUInt32(tmp.ToString()));
}
return hex;
}
你能帮我写另一个字符串到基于我的示例函数的二进制函数吗?
public static string ConvertToBin(string asciiString)
{
string bin = "";
foreach (char c in asciiString)
{
int tmp = c;
bin += String.Format("{0:x2}", (uint)System.Convert.????(tmp.ToString()));
}
return bin;
}
发布于 2011-04-14 22:00:37
这就是了:
public static byte[] ConvertToByteArray(string str, Encoding encoding)
{
return encoding.GetBytes(str);
}
public static String ToBinary(Byte[] data)
{
return string.Join(" ", data.Select(byt => Convert.ToString(byt, 2).PadLeft(8, '0')));
}
// Use any sort of encoding you like.
var binaryString = ToBinary(ConvertToByteArray("Welcome, World!", Encoding.ASCII));
发布于 2012-05-25 17:49:56
听起来您基本上想要将一个ASCII字符串,或者更好地说,将一个字节的as you can encode your string to a byte[] using your preferred encoding mode转换成一个由1和0组成的字符串?即101010010010100100100101001010010100101001010010101000010111101101010
这个可以帮你做到这一点。
//Formats a byte[] into a binary string (010010010010100101010)
public string Format(byte[] data)
{
//storage for the resulting string
string result = string.Empty;
//iterate through the byte[]
foreach(byte value in data)
{
//storage for the individual byte
string binarybyte = Convert.ToString(value, 2);
//if the binarybyte is not 8 characters long, its not a proper result
while(binarybyte.Length < 8)
{
//prepend the value with a 0
binarybyte = "0" + binarybyte;
}
//append the binarybyte to the result
result += binarybyte;
}
//return the result
return result;
}
发布于 2011-04-14 22:47:25
下面将为您提供每个字符低位字节的十六进制编码,这看起来就像您所要求的:
StringBuilder sb = new StringBuilder();
foreach (char c in asciiString)
{
uint i = (uint)c;
sb.AppendFormat("{0:X2}", (i & 0xff));
}
return sb.ToString();
https://stackoverflow.com/questions/5664345
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