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社区首页 >问答首页 >Java泛型+构建器模式

Java泛型+构建器模式
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Stack Overflow用户
提问于 2010-07-08 22:27:53
回答 3查看 41.3K关注 0票数 38

如何调用下面的start()

代码语言:javascript
复制
package com.example.test;

class Bar {}

public class Foo<K>
{
    final private int count;
    final private K key;

    Foo(Builder<K> b)
    {
        this.count = b.count;
        this.key = b.key;
    }

    public static class Builder<K2>
    {
        int count;
        K2 key;

        private Builder() {}
        static public <K3> Builder<K3> start() { return new Builder<K3>(); }
        public Builder<K2> setCount(int count) { this.count = count; return this; }
        public Builder<K2> setKey(K2 key) { this.key = key; return this; }
        public Foo<K2> build() { return new Foo(this); }
    }

    public static void main(String[] args)
    {
        Bar bar = new Bar();
        Foo<Bar> foo1 = Foo.Builder.start().setCount(1).setKey(bar).build();
        // Type mismatch: cannot convert from Foo<Object> to Foo<Bar>

        Foo<Bar> foo2 = Foo.Builder<Bar>.start().setCount(1).setKey(bar).build();
        // Multiple markers at this line
        // - Bar cannot be resolved
        // - Foo.Builder cannot be resolved
        // - Syntax error on token ".", delete this token
        // - The method start() is undefined for the type Foo<K>
        // - Duplicate local variable fooType mismatch: cannot convert from Foo<Object> to Foo<Bar>

        Foo<Bar> foo3 = Foo<Bar>.Builder.start().setCount(1).setKey(bar).build();
        // Multiple markers at this line
        // - Foo cannot be resolved
        // - Syntax error on token ".", delete this token
        // - Bar cannot be resolved     
    }
}
EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2010-07-08 22:33:02

你很接近了:

代码语言:javascript
复制
Foo.Builder.<Bar> start().setCount(1).setKey(bar).build();

干杯!:)

如果编译器不能自己推断出方法的类型参数,你可以通过调用obj.<Type> method(...)来强制它。

附注:您可能想要使用:

代码语言:javascript
复制
public Foo<K2> build() {
    return new Foo<K2>(this);
}

避免使用原始类型。

票数 44
EN

Stack Overflow用户

发布于 2010-07-08 22:40:11

Andrei的方法还可以,但大多数程序员可能会为这种相当未知的语法而苦苦挣扎。使用下面的方法可能更容易:

代码语言:javascript
复制
static public <K3> Builder<K3> start(Class<K3> cls) { return new Builder<K3>(); }

Foo<Bar> foo1 = Foo.Builder.start(Bar.class).setCount(1).setKey(bar).build();

传递该类只是为了帮助处理泛型类型。它并不美观,但至少语法是常识。

另一种选择是立即从泛型类型的对象开始:

代码语言:javascript
复制
Foo<Bar> foo1 = Foo.Builder.startWithKey(bar).setCount(1).build();
票数 28
EN

Stack Overflow用户

发布于 2018-10-13 22:50:04

下面是我会怎么做:

代码语言:javascript
复制
package odmor2018.krit.rtti.builderpattern;

import java.lang.reflect.Field;
import java.util.Arrays;
import java.util.List;
import java.util.logging.Level;
import java.util.logging.Logger;
import java.util.stream.Collectors;

public class Person {

    private String firstName;
    private String middleName;
    private String lastName;
    private boolean sex;

    public Person(String firstName, String middleName, String lastName, boolean sex) {
        this.firstName = firstName;
        this.middleName = middleName;
        this.lastName = lastName;
        this.sex = sex;
    }

    public Person() {
    }

    @Override
    public String toString() {
        return "Person{" + "firstName=" + firstName + ", middleName=" + middleName + ", lastName=" + lastName + ", sex=" + sex + '}';
    }

    public static class Builder {

        private final Field[] fields = Person.class.getDeclaredFields();
        private final List<Field> fieldsList = Arrays.asList(fields);
        private final List<String> fNames = fieldsList.stream().map(f -> f.getName()).collect(Collectors.toList());

        private final Person nP = new Person();

        public Builder with(String fName, Object value) {
            if (fNames.contains(fName)) {
                int fInd = fNames.indexOf(fName);
                try {
                    Field f = fields[fInd];
                    f.setAccessible(true);
                    f.set(nP, value);
                } catch (Exception ex) {
                    Logger.getLogger(Person.class.getName()).log(Level.SEVERE, null, ex);
                }
            }
            return this;
        }

        public Person createPerson2() {
            return nP;
        }
    }

    public static void main(String[] args) {
        Person p3 = new Person.Builder()
                .with("firstName", "doooobri2")
                .with("sex", false)
                .createPerson2();
        System.err.println("p3:" + p3);
    }
}
票数 3
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/3204623

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