如何在Java中压缩文件而不包括文件路径?

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方法:

public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){
  // Create a buffer for reading the files 
  byte[] buf = new byte[1024]; 

  try {
   // VER SI HAY QUE CREAR EL ROOT PATH
         boolean result = (new File(destinationDir)).mkdirs();

         String zipFullFilename = destinationDir + "/" + zipFilename ;

         System.out.println(result);

   // Create the ZIP file  
   ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); 
   // Compress the files 
   for (String filename: sourcesFilenames) { 
    FileInputStream in = new FileInputStream(filename); 
    // Add ZIP entry to output stream. 
    out.putNextEntry(new ZipEntry(filename)); 
    // Transfer bytes from the file to the ZIP file 
    int len; 
    while ((len = in.read(buf)) > 0) { 
     out.write(buf, 0, len); 
    } 
    // Complete the entry 
    out.closeEntry(); 
    in.close(); 
   } // Complete the ZIP file 
   out.close();

   return true;
  } catch (IOException e) { 
   return false;
  }  
 }
提问于
用户回答回答于

在此:

// Add ZIP entry to output stream. 
out.putNextEntry(new ZipEntry(filename)); 

如果只使用名称(没有路径):

// Add ZIP entry to output stream. 
File file = new File(filename); //"Users/you/image.jpg"
out.putNextEntry(new ZipEntry(file.getName())); //"image.jpg"
用户回答回答于

正在使用文件的相对路径查找源数据,然后将条目设置为相同的内容。相反,应该将源转换为File对象,然后使用

putNextEntry(新ZipEntry(SourceFile.getName()))

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