blocks|key|2011299|text|使用GNU的date，您可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2011300|date+-d+"@$TIMESTAMP"|code-block|syntax|javascript|2011301|#+date+-d+@0
Wed+Dec+31+19:00:00+EST+1969|2011302|(来自：BASH:+Convert+Unix+Timestamp+to+a+Date)|2011303|在OS+X上，使用date+-r。|2011304|date+-r+"$TIMESTAMP"|2011305|或者，使用strftime()。它不能直接从shell获得，但您可以通过gawk访问它。%25c说明符以与区域设置相关的方式显示时间戳。|2011306|echo+"$TIMESTAMP"+%7C+gawk+'{print+strftime("%25c",+$0)}'|2011307|#+echo+0+%7C+gawk+'{print+strftime("%25c",+$0)}'
Wed+31+Dec+1969+07:00:00+PM+EST|2011308|entityMap|0|LINK|mutability|MUTABLE|url|http://www.antonolsen.com/2006/04/06/bash-convert-unix-timestamp-to-a-date/|1|https://en.wikipedia.org/wiki/AWK#Versions_and_implementations^0|6|4|0|0|0|4|12|0|0|9|7|0|0|5|A|18|2|10|4|1|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|M|3|N|5|6|7|1D|8|@]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|O|3|P|5|6|7|1H|8|@$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1K|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1L|8|@$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]]|D|@$9|1Q|A|1R|1|1S]]|E|$]]|$1|U|3|V|5|H|7|1T|8|@]|D|@]|E|$I|J]]|$1|W|3|X|5|H|7|1U|8|@]|D|@]|E|$I|J]]|$1|Y|3|-4|5|6|7|1V|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]|16|$5|11|12|13|E|$14|17]]]]

With GNU's <code>date</code> you can do:

<pre><code>date -d "@$TIMESTAMP"
</code></pre>



<pre><code># date -d @0
Wed Dec 31 19:00:00 EST 1969
</code></pre>

(From: <a href="http://www.antonolsen.com/2006/04/06/bash-convert-unix-timestamp-to-a-date/" rel="noreferrer">BASH: Convert Unix Timestamp to a Date</a>)

On OS X, use <code>date -r</code>.

<pre><code>date -r "$TIMESTAMP"
</code></pre>

Alternatively, use <code>strftime()</code>. It's not available directly from the shell, but you can access it via <a href="https://en.wikipedia.org/wiki/AWK#Versions_and_implementations" rel="noreferrer">gawk</a>. The <code>%c</code> specifier displays the timestamp in a locale-dependent manner.

<pre><code>echo "$TIMESTAMP" | gawk '{print strftime("%c", $0)}'
</code></pre>



<pre><code># echo 0 | gawk '{print strftime("%c", $0)}'
Wed 31 Dec 1969 07:00:00 PM EST
</code></pre>

blocks|key|2011325|text|date+-d+@1278999698+%2B'%25Y-%25m-%25d+%25H:%25M:%25S'，其中@后面的数字是以秒为单位的数字|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2011326|entityMap^0|0|14|17|1|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

<code>date -d @1278999698 +'%Y-%m-%d %H:%M:%S'</code>
Where the number behind <code>@</code> is the number in seconds

blocks|key|1797818|text|此解决方案适用于不支持date+-d+@的date版本。它不需要AWK或其他命令。Unix时间戳是自1970年1月1日UTC以来的秒数，因此指定UTC很重要。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1797819|date+-d+'1970-01-01+1357004952+sec+UTC'
Mon+Dec+31+17:49:12+PST+2012|code-block|syntax|javascript|1797820|如果您使用的是Mac，则使用：|1797821|date+-r+1357004952|1797822|获取纪元的命令：|1797823|date+%2B%25s
1357004952|1797824|功劳归于安东：|1797825|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/AWK^0|B|9|W|3|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@$9|15|A|16|1|17]]|E|$]]|$1|F|3|G|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|19|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1B|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1D|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]]]

This solution works with versions of date which do not support <code>date -d @</code>. It does not require <a href="http://en.wikipedia.org/wiki/AWK" rel="noreferrer">AWK</a> or other commands. A Unix timestamp is the number of seconds since Jan 1, 1970, UTC so it is important to specify UTC.

<pre><code>date -d '1970-01-01 1357004952 sec UTC'
Mon Dec 31 17:49:12 PST 2012
</code></pre>

If you are on a Mac, then use:

<pre><code>date -r 1357004952
</code></pre>

Command for getting epoch:

<pre><code>date +%s
1357004952
</code></pre>

Credit goes to Anton: <a href="http://www.antonolsen.com/2006/04/06/bash-convert-unix-timestamp-to-a-date/" rel="noreferrer">BASH: Convert Unix Timestamp to a Date</a>

blocks|key|2011581|text|正如@TomMcKenzie在对另一个答案的评论中所说的那样，自Unix时代以来，date+-r+123456789可以说是一种更常见(即更广泛地实现)的简单解决方案，时间以秒为单位，但不幸的是，没有通用的保证便携解决方案。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2011582|在许多类型的系统上，-d选项的含义与GNU+Date的--date扩展完全不同。不幸的是，GNU+Date不能像其他实现一样解释-r。因此，不幸的是，您必须知道您使用的是哪个版本的date，而且许多较旧的Unix+date命令都不支持这两个选项。|2011583|更糟糕的是，POSIX+date既不能识别-d，也不能识别-r，并且在任何命令中(据我所知)都没有提供从命令行格式化Unix时间的标准方法(因为POSIX+Awk也没有strftime())。(您不能使用touch+-t和ls，因为前者不接受从Unix时代起以秒为单位的时间。)|2011584|注意:虽然Brian+Kernighan直接提供的一个True+Awk现在有内置的strftime()函数和一个systime()函数来返回Unix时代以来的当前时间(以秒为单位)，因此Awk解决方案可能是最便携的。|2011585|entityMap^0|15|H|0|A|2|R|6|1S|2|2I|4|2Z|4|0|C|4|L|2|T|2|2C|A|2U|8|33|2|0|15|A|1K|9|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|1E|8|@$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|L|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|M|$]]

As @TomMcKenzie says in a comment to another answer, <code>date -r 123456789</code> is arguably a more common (i.e. more widely implemented) simple solution for times given as seconds since the Unix Epoch, but unfortunately there's no universal guaranteed portable solution.

The <code>-d</code> option on many types of systems means something entirely different than GNU Date's <code>--date</code> extension. Sadly GNU Date doesn't interpret <code>-r</code> the same as these other implementations. So unfortunately you have to know which version of <code>date</code> you're using, and many older Unix <code>date</code> commands don't support either option.

Even worse, POSIX <code>date</code> recognizes neither <code>-d</code> nor <code>-r</code> and provides no standard way in any command at all (that I know of) to format a Unix time from the command line (since POSIX Awk also lacks <code>strftime()</code>). (You can't use <code>touch -t</code> and <code>ls</code> because the former does not accept a time given as seconds since the Unix Epoch.)

Note though The One True Awk available direct from Brian Kernighan does now have the <code>strftime()</code> function built-in as well as a <code>systime()</code> function to return the current time in seconds since the Unix Epoch), so perhaps the Awk solution is the most portable.

blocks|key|1797734|text|如果您觉得这种表示法很笨拙，也许-R-option确实有帮助。它以RFC2822格式输出日期。因此，您不需要所有这些标识符：date+-d+@1278999698+-R。另一种可能是在您的语言环境中以秒为单位输出日期：date+-d+@1278999698+%2B%25c。应该很容易记住。:-)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1797735|entityMap^0|G|2|1Q|M|31|N|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

If you find the notation awkward, maybe the <code>-R</code>-option does help. It outpouts the date in RFC 2822 format. So you won't need all those identifiers: <code>date -d @1278999698 -R</code>. Another possibility is to output the date in seconds in your locale: <code>date -d @1278999698 +%c</code>. Should be easy to remember. :-)

blocks|key|1797760|text|标准的Perl解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1797761|echo+$TIMESTAMP+%7C+perl+-nE+'say+scalar+gmtime+$_'|code-block|syntax|javascript|1797762|(如果愿意，也可以使用localtime+)|1797763|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The standard Perl solution is:

<pre><code>echo $TIMESTAMP | perl -nE 'say scalar gmtime $_'
</code></pre>

(or localtime, if preferred)

blocks|key|1797957|text|对上面daest1的答案进行了轻微的更正。将时区指定为UTC，而非GMT：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1797958|$+date+-d+'1970-01-01+1416275583+sec+GMT'
Tue+Nov+18+00:53:03+GMT+2014
$+date+-d+'1970-01-01+1416275583+sec+UTC'
Tue+Nov+18+01:53:03+GMT+2014|code-block|syntax|javascript|1797959|第二个是正确的。我认为原因是在英国，从1968年到1971年一直实行夏令时。|1797960|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Slight correction to dabest1's answer above. Specify the timezone as UTC, not GMT:

<pre><code>$ date -d '1970-01-01 1416275583 sec GMT'
Tue Nov 18 00:53:03 GMT 2014
$ date -d '1970-01-01 1416275583 sec UTC'
Tue Nov 18 01:53:03 GMT 2014
</code></pre>

The second one is correct. I think the reason is that in the UK, daylight saving was in force continually from 1968 to 1971.

blocks|key|2011275|text|awk+'BEGIN+{+print+strftime("%25c",+1271603087);+}'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2011276|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>awk 'BEGIN { print strftime("%c", 1271603087); }'
</code></pre>

blocks|key|1797966|text|这里的其他例子很难记住。最简单的是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1797967|date+-r+1305712800|code-block|syntax|javascript|1797968|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Other examples here are difficult to remember. At its simplest:

<pre><code>date -r 1305712800
</code></pre>

blocks|key|2011634|text|在~/.bashrc中输入以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2011635|function+unixts()+{+date+-d+"@$1";+}|code-block|syntax|javascript|2011636|示例用法：|2011637|$+unixts+1551276383

Wed+Feb+27+14:06:23+GMT+2019|2011638|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Put the following in your ~/.bashrc :

<pre><code>function unixts() { date -d "@$1"; }
</code></pre>

Example usage:

<pre><code>$ unixts 1551276383

Wed Feb 27 14:06:23 GMT 2019
</code></pre>

blocks|key|1797988|text|Python：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1797989|python+-c+"from+datetime+import+datetime;+print(datetime.fromtimestamp($TIMESTAMP))"|code-block|syntax|javascript|1797990|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Python:

<pre><code>python -c "from datetime import datetime; print(datetime.fromtimestamp($TIMESTAMP))"
</code></pre>

Is there a quick, one-liner way to convert a Unix timestamp to a date from the Unix command line?
<code>date</code> might work, except it's rather awkward to specify each element (month, day, year, hour, etc.), and I can't figure out how to get it to work properly. It seems like there might be an easier way — am I missing something?

Convert Unix timestamp to a date string

有没有一种从Unix命令行将Unix时间戳转换为日期的快速、简单的方法？date也许可以工作，只是指定每个元素(月、日、年、小时等)比较笨拙，而且我不知道如何让它正常工作。似乎有一种更简单的方法， - 我错过了什么吗？

问将Unix时间戳转换为日期字符串
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