有没有办法在Java应用程序中运行这个命令行?
java -jar map.jar time.rel test.txt debug
我可以用命令来运行它,但不能在Java中运行它。
发布于 2011-12-14 05:38:51
Runtime rt = Runtime.getRuntime();
Process pr = rt.exec("java -jar map.jar time.rel test.txt debug");
http://docs.oracle.com/javase/7/docs/api/java/lang/Runtime.html
发布于 2014-09-09 10:00:43
您还可以像这样查看输出:
final Process p = Runtime.getRuntime().exec("java -jar map.jar time.rel test.txt debug");
new Thread(new Runnable() {
public void run() {
BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream()));
String line = null;
try {
while ((line = input.readLine()) != null)
System.out.println(line);
} catch (IOException e) {
e.printStackTrace();
}
}
}).start();
p.waitFor();
别忘了,如果你正在运行一个windows命令,你需要把cmd /c
放在你的命令前面。
编辑:对于奖励积分,您还可以使用ProcessBuilder
将输入传递给程序:
String[] command = new String[] {
"choice",
"/C",
"YN",
"/M",
"\"Press Y if you're cool\""
};
String inputLine = "Y";
ProcessBuilder pb = new ProcessBuilder(command);
pb.redirectErrorStream(true);
Process p = pb.start();
BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream()));
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(p.getOutputStream()));
writer.write(inputLine);
writer.newLine();
writer.close();
String line;
while ((line = reader.readLine()) != null) {
System.out.println(line);
}
这将运行windows命令choice /C YN /M "Press Y if you're cool"
并以Y
响应。因此,输出将是:
Press Y if you're cool [Y,N]?Y
发布于 2015-06-19 06:25:48
为了避免被调用的进程在标准输出和/或错误上输出大量数据时被阻塞,您必须使用Craigo提供的解决方案。还要注意,ProcessBuilder比Runtime.getRuntime().exec()更好。这有几个原因:它对参数进行了更好的标记化,并且还处理了错误标准输出(也可以检查here)。
ProcessBuilder builder = new ProcessBuilder("cmd", "arg1", ...);
builder.redirectErrorStream(true);
final Process process = builder.start();
// Watch the process
watch(process);
我使用一个新函数"watch“在一个新线程中收集这些数据。当被调用的进程结束时,此线程将在调用进程中结束。
private static void watch(final Process process) {
new Thread() {
public void run() {
BufferedReader input = new BufferedReader(new InputStreamReader(process.getInputStream()));
String line = null;
try {
while ((line = input.readLine()) != null) {
System.out.println(line);
}
} catch (IOException e) {
e.printStackTrace();
}
}
}.start();
}
https://stackoverflow.com/questions/8496494
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