blocks|key|991493|text|JVM的一个(可选)参数是堆栈大小。我是-Xss。我不知道默认值是什么，但是如果堆栈上的东西总数超过了这个值，你就会得到那个错误。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|991494|一般来说，无限递归是导致这种情况的原因，但如果你看到了这种情况，你的堆栈跟踪应该有5个以上的帧。|991495|尝试添加一个-Xss参数(或增加一个参数的值)，看看这种情况是否会消失。|991496|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

One of the (optional) arguments to the JVM is the stack size. It's -Xss. I don't know what the default value is, but if the total amount of stuff on the stack exceeds that value, you'll get that error.

Generally, infinite recursion is the cause of this, but if you were seeing that, your stack trace would have more than 5 frames.

Try adding a -Xss argument (or increasing the value of one) to see if this goes away.

blocks|key|991553|text|实际导致java.lang.StackOverflowError的原因通常是无意的递归。对我来说，这通常是当我打算调用覆盖方法的超级方法时。例如在本例中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|991554|public+class+Vehicle+{
++++public+void+accelerate(float+acceleration,+float+maxVelocity)+{
++++++++//+set+the+acceleration
++++}
}

public+class+SpaceShip+extends+Vehicle+{
++++@Override
++++public+void+accelerate(float+acceleration,+float+maxVelocity)+{
++++++++//+update+the+flux+capacitor+and+call+super.accelerate
++++++++//+oops+meant+to+call+super.accelerate(acceleration,+maxVelocity);
++++++++//+but+accidentally+wrote+this+instead.+A+StackOverflow+is+in+our+future.
++++++++this.accelerate(acceleration,+maxVelocity);+
++++}
}|code-block|syntax|javascript|991555|首先，当我们调用一个函数时，知道幕后发生了什么是很有用的。参数和调用方法的地址被推送到堆栈上(请参见http://en.wikipedia.org/wiki/Stack_(abstract_data_type)#Runtime_memory_management，以便被调用的方法可以访问参数，并且当被调用的方法完成时，可以在调用后继续执行。但是因为我们是递归地调用this.accelerate(acceleration，maxVelocity)+(当一个方法调用自己时，递归是松散的。有关更多信息，请参见http://en.wikipedia.org/wiki/Recursion_(computer_science)，我们处于一种称为无限递归的情况下，我们不断地在调用堆栈上堆积参数和返回地址。由于调用堆栈的大小有限，我们最终会耗尽空间。调用堆栈上的空间耗尽称为溢出。这是因为我们试图使用比我们拥有的更多的堆栈空间，而数据从字面上溢出堆栈。在Java语言中，这会导致运行时异常java.lang.StackOverflow，并会立即停止程序。|offset|length|991556|上面的例子稍微简化了一些(尽管它发生在我身上的次数比我愿意承认的要多)。同样的事情可能会以一种更间接的方式发生，使其更难追踪。但是，通常情况下，一旦发生StackOverflow，它通常很容易解决。|991557|从理论上讲，没有递归的堆栈溢出也是可能的，但在实践中，这似乎是相当罕见的事件。|991558|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Stack_(abstract_data_type%2529#Runtime_memory_management)|1|http://en.wikipedia.org/wiki/Recursion_(computer_science%2529)^0|0|0|1E|29|0|72|1L|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@$I|11|J|12|1|13]|$I|14|J|15|1|16]]|A|$]]|$1|K|3|L|5|6|7|17|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|18|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

What actually causes a java.lang.StackOverflowError is typically unintentional recursion. For me it's often when I intended to call a super method for the overidden method. Such as in this case:

<pre><code>public class Vehicle {
 public void accelerate(float acceleration, float maxVelocity) {
 // set the acceleration
 }
}

public class SpaceShip extends Vehicle {
 @Override
 public void accelerate(float acceleration, float maxVelocity) {
 // update the flux capacitor and call super.accelerate
 // oops meant to call super.accelerate(acceleration, maxVelocity);
 // but accidentally wrote this instead. A StackOverflow is in our future.
 this.accelerate(acceleration, maxVelocity); 
 }
}
</code></pre>

First, it's useful to know what happens behind the scenes when we call a function. The arguments and the address of where the method was called is pushed on the stack (see <a href="http://en.wikipedia.org/wiki/Stack_(abstract_data_type)#Runtime_memory_management">http://en.wikipedia.org/wiki/Stack_(abstract_data_type)#Runtime_memory_management</a>) so that the called method can access the arguments and so that when the called method is completed, execution can continue after the call. But since we are calling this.accelerate(acceleration, maxVelocity) recursively (recursion is loosely when a method calls itself. For more info see <a href="http://en.wikipedia.org/wiki/Recursion_(computer_science)">http://en.wikipedia.org/wiki/Recursion_(computer_science)</a>) we are in a situation known as infinite recursion and we keep piling the arguments and return address on the call stack. Since the call stack is finite in size, we eventually run out of space. The running out of space on the call stack is known as overflow. This is because we are trying to use more stack space than we have and the data literally overflows the stack. In the Java programming language, this results in the runtime exception java.lang.StackOverflow and will immediately halt the program. 

The above example is somewhat simplified (although it happens to me more than I'd like to admit.) The same thing can happen in a more round about way making it a bit harder to track down. However, in general, the StackOverflow is usually pretty easy to resolve, once it occurs.

In theory, it is also possible to have a stack overflow without recursion, but in practice, it would appear to be a fairly rare event.

blocks|key|1206013|text|检查方法的任何递归调用。这主要是由方法的递归调用引起的。一个简单的例子是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1206014|public+static+void+main(String...+args)+{
++++Main+main+=+new+Main();

++++main.testMethod(1);
}

public+void+testMethod(int+i)+{
++++testMethod(i);

++++System.out.println(i);
}|code-block|syntax|javascript|1206015|在这里，当调用testMethod时，System.out.println(i)；将被反复推送到堆栈。|1206016|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Check for any recusive calls for methods. Mainly it is caused when there is recursive call for a method. A simple example is

<pre><code>public static void main(String... args) {
 Main main = new Main();

 main.testMethod(1);
}

public void testMethod(int i) {
 testMethod(i);

 System.out.println(i);
}
</code></pre>

Here the System.out.println(i); will be repeatedly pushed to stack when the testMethod is called.

blocks|key|1206103|text|我用hibernate创建了一个程序，在其中我创建了两个POJO类，每个类都有一个对象作为数据成员。在main方法中，当我试图将它们保存在数据库中时，我也得到了这个错误。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1206104|之所以会发生这种情况，是因为两个类都相互引用，从而创建了一个导致此错误的循环。|1206105|所以，检查一下你的程序中是否存在这样的关系。|1206106|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

I created a program with hibernate, in which I created two POJO classes, both with an object of each other as data members. When in the main method I tried to save them in the database I also got this error.

This happens because both of the classes are referring each other, hence creating a loop which causes this error.

So, check whether any such kind of relationships exist in your program.

blocks|key|1206176|text|在我的例子中，我有两个活动。在第二个活动中，我忘记了在onCreate方法上加上SUPER键。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1206177|super.onCreate(savedInstanceState);|code-block|syntax|javascript|1206178|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In my case I have two activities. In the second activity I forgot to put super on the onCreate method.

<pre><code>super.onCreate(savedInstanceState);
</code></pre>

blocks|key|991778|text|当线程堆栈的大小不断增长直到达到最大限制时，可能会发生堆栈溢出异常。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|991779|正在调整堆栈大小(Xss和Xmso)选项...|991780|我建议你看看这个链接：http://www-01.ibm.com/support/docview.wss?uid=swg21162896有很多可能导致StackOverflowError的原因，正如你在链接中看到的……|offset|length|991781|entityMap|0|LINK|mutability|MUTABLE|url|http://www-01.ibm.com/support/docview.wss?uid=swg21162896^0|0|0|B|1L|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

Stack Overflow exceptions can occur when a thread stack continues to grow in size until reaching the maximum limit. 

Adjusting the Stack Sizes (Xss and Xmso) options...

I suggest you see this link:
<a href="http://www-01.ibm.com/support/docview.wss?uid=swg21162896" rel="nofollow noreferrer">http://www-01.ibm.com/support/docview.wss?uid=swg21162896</a>
There are many possible causes to a StackOverflowError, as you can see in the link....

blocks|key|1206310|text|我也有同样的问题|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1206311|Role.java|1206312|+@ManyToMany(mappedBy+=+"roles",+fetch+=+FetchType.LAZY,cascade+=+CascadeType.ALL)
+Set<BusinessUnitMaster>+businessUnits+=new+HashSet<>();|code-block|syntax|javascript|1206313|BusinessUnitMaster.java|1206314|@ManyToMany(cascade+=+CascadeType.ALL,+fetch+=+FetchType.LAZY)
@JoinTable(
++++++++name+=+"BusinessUnitRoles",
++++++++joinColumns+=+{@JoinColumn(name+=+"unit_id",+referencedColumnName+=+"record_id")},
++++++++inverseJoinColumns+=+{@JoinColumn(name+=+"role_id",+referencedColumnName+=+"record_id")}
)
private+Set<Role>+roles=new+HashSet<>();|1206315|问题是，在创建BusinessUnitMaster和角色时，必须为RoleService.java保存两端的对象|1206316|roleRepository.save(role);|1206317|对于BusinessUnitMasterService.java|1206318|businessUnitMasterRepository.save(businessUnitMaster);|1206319|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|F|7|14|8|@]|9|@]|A|$G|H]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

I was having the same issue
Role.java
<pre><code> @ManyToMany(mappedBy = &quot;roles&quot;, fetch = FetchType.LAZY,cascade = CascadeType.ALL)
 Set&lt;BusinessUnitMaster&gt; businessUnits =new HashSet&lt;&gt;();
</code></pre>
BusinessUnitMaster.java
<pre><code>@ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JoinTable(
 name = &quot;BusinessUnitRoles&quot;,
 joinColumns = {@JoinColumn(name = &quot;unit_id&quot;, referencedColumnName = &quot;record_id&quot;)},
 inverseJoinColumns = {@JoinColumn(name = &quot;role_id&quot;, referencedColumnName = &quot;record_id&quot;)}
)
private Set&lt;Role&gt; roles=new HashSet&lt;&gt;();
</code></pre>
the problem is that when you create BusinessUnitMaster and Role
you have to save the object for both sides
for RoleService.java
<pre><code>roleRepository.save(role);
</code></pre>
for BusinessUnitMasterService.java
<pre><code>businessUnitMasterRepository.save(businessUnitMaster);
</code></pre>

blocks|key|1206377|text|在我的例子中，l必须覆盖子类中的equals和hashcode类方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1206378|++++@Override
public+boolean+equals(Object+o)+{
++++if+(this+==+o)+return+true;
++++if+(!(o+instanceof+MyClass))+return+false;
++++return+id+!=+null+&&+id.equals(((MyClass)+o).getId());
}

@Override
public+int+hashCode()+{
++++return+getClass().hashCode();
}|code-block|syntax|javascript|1206379|参考地址：vladmihalcea+article|offset|length|1206380|entityMap|0|LINK|mutability|MUTABLE|url|https://vladmihalcea.com/the-best-way-to-map-a-onetomany-association-with-jpa-and-hibernate/^0|0|0|5|K|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

in my case l had to override the equals and hashcode class methods in the child class
<pre><code> @Override
public boolean equals(Object o) {
 if (this == o) return true;
 if (!(o instanceof MyClass)) return false;
 return id != null &amp;&amp; id.equals(((MyClass) o).getId());
}

@Override
public int hashCode() {
 return getClass().hashCode();
}
</code></pre>
reference here: <a href="https://vladmihalcea.com/the-best-way-to-map-a-onetomany-association-with-jpa-and-hibernate/" rel="nofollow noreferrer">vladmihalcea article</a>

What can cause a <code>java.lang.StackOverflowError</code>? The stack printout that I get is not very deep at all (only 5 methods).

What causes a java.lang.StackOverflowError

什么会导致java.lang.StackOverflowError？我得到的堆栈打印输出根本不是很深(只有5个方法)。

问是什么导致了java.lang.StackOverflowError
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问是什么导致了java.lang.StackOverflowErrorEN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问是什么导致了java.lang.StackOverflowError
EN