blocks|key|162565|text|要在立即子目录中查找文件，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|162566|configfiles+=+glob.glob(r'C:\Users\sam\Desktop\*\*.txt')|code-block|syntax|javascript|162567|对于遍历所有子目录的递归版本，可以使用**并传递recursive=True+since+Python+3.5|offset|length|style|CODE|162568|configfiles+=+glob.glob(r'C:\Users\sam\Desktop\**\*.txt',+recursive=True)|162569|两个函数调用都返回列表。您可以使用glob.iglob()逐个返回路径。或use+pathlib|162570|from+pathlib+import+Path

path+=+Path(r'C:\Users\sam\Desktop')
txt_files_only_subdirs+=+path.glob('*/*.txt')
txt_files_all_recursively+=+path.rglob('*.txt')+#+including+the+current+dir|162571|这两种方法都返回迭代器(您可以逐个获取路径)。|162572|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/glob.html#glob.glob|1|https://docs.python.org/3/library/pathlib.html#pathlib.Path.rglob^0|0|0|J|2|O|E|13|G|0|0|0|H|C|15|7|11|B|1|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]|$I|19|J|1A|K|L]]|9|@$I|1B|J|1C|1|1D]]|A|$]]|$1|M|3|N|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1F|8|@$I|1G|J|1H|K|L]|$I|1I|J|1J|K|L]]|9|@$I|1K|J|1L|1|1M]]|A|$]]|$1|Q|3|R|5|D|7|1N|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1O|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1P|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

To find files in immediate subdirectories:

<pre><code>configfiles = glob.glob(r'C:\Users\sam\Desktop\*\*.txt')
</code></pre>

For a recursive version that traverse all subdirectories, you could use <code>**</code> and pass <code>recursive=True</code> <a href="https://docs.python.org/3/library/glob.html#glob.glob" rel="noreferrer">since Python 3.5</a>:

<pre><code>configfiles = glob.glob(r'C:\Users\sam\Desktop\**\*.txt', recursive=True)
</code></pre>

Both function calls return lists. You could use <code>glob.iglob()</code> to return paths one by one. Or <a href="https://docs.python.org/3/library/pathlib.html#pathlib.Path.rglob" rel="noreferrer">use <code>pathlib</code></a>:

<pre><code>from pathlib import Path

path = Path(r'C:\Users\sam\Desktop')
txt_files_only_subdirs = path.glob('*/*.txt')
txt_files_all_recursively = path.rglob('*.txt') # including the current dir
</code></pre>

Both methods return iterators (you can get paths one by one).

blocks|key|380560|text|glob2包支持通配符，并且速度相当快|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|380561|code+=+'''
import+glob2
glob2.glob("files/*/**")
'''
timeit.timeit(code,+number=1)|code-block|syntax|javascript|380562|在我的笔记本电脑上，匹配>60,000+file+paths大约需要2秒。|380563|entityMap|0|LINK|mutability|MUTABLE|url|https://pypi.python.org/pypi/glob2|1|https://github.com/jsdelivr/jsdelivr/tree/master/files^0|0|5|0|0|0|C|I|1|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|K|3|-4|5|6|7|13|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

The <a href="https://pypi.python.org/pypi/glob2" rel="noreferrer">glob2</a> package supports wild cards and is reasonably fast

<pre><code>code = '''
import glob2
glob2.glob("files/*/**")
'''
timeit.timeit(code, number=1)
</code></pre>

On my laptop it takes approximately 2 seconds to match <a href="https://github.com/jsdelivr/jsdelivr/tree/master/files" rel="noreferrer">>60,000 file paths</a>.

blocks|key|380512|text|您可以在Python2.6中使用Formic|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|380513|import+formic
fileset+=+formic.FileSet(include="**/*.txt",+directory="C:/Users/sam/Desktop/")|code-block|syntax|javascript|380514|披露-我是这个包的作者。|380515|entityMap|0|LINK|mutability|MUTABLE|url|http://pypi.python.org/pypi/formic^0|G|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

You can use <a href="http://pypi.python.org/pypi/formic" rel="noreferrer">Formic</a> with Python 2.6

<pre><code>import formic
fileset = formic.FileSet(include="**/*.txt", directory="C:/Users/sam/Desktop/")
</code></pre>

Disclosure - I am the author of this package.

blocks|key|162691|text|这是一个经过调整的版本，可以在不使用glob2的情况下实现类似glob.glob的功能。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|162692|def+find_files(directory,+pattern='*'):
++++if+not+os.path.exists(directory):
++++++++raise+ValueError("Directory+not+found+{}".format(directory))

++++matches+=+[]
++++for+root,+dirnames,+filenames+in+os.walk(directory):
++++++++for+filename+in+filenames:
++++++++++++full_path+=+os.path.join(root,+filename)
++++++++++++if+fnmatch.filter([full_path],+pattern):
++++++++++++++++matches.append(os.path.join(root,+filename))
++++return+matches|code-block|syntax|javascript|162693|因此，如果您有以下dir结构|162694|tests/files
├──+a0
│  +├──+a0.txt
│  +├──+a0.yaml
│  +└──+b0
│  +++++├──+b0.yaml
│  +++++└──+b00.yaml
└──+a1|162695|你可以这样做|162696|files+=+utils.find_files('tests/files','**/b0/b*.yaml')
>+['tests/files/a0/b0/b0.yaml',+'tests/files/a0/b0/b00.yaml']|162697|几乎所有的fnmatch模式都匹配整个文件名本身，而不仅仅是文件名。|162698|entityMap^0|I|5|V|9|0|0|0|0|0|0|5|7|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|14|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|U|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|V|$]]

Here is a adapted version that enables <code>glob.glob</code> like functionality without using <code>glob2</code>. 

<pre><code>def find_files(directory, pattern='*'):
 if not os.path.exists(directory):
 raise ValueError("Directory not found {}".format(directory))

 matches = []
 for root, dirnames, filenames in os.walk(directory):
 for filename in filenames:
 full_path = os.path.join(root, filename)
 if fnmatch.filter([full_path], pattern):
 matches.append(os.path.join(root, filename))
 return matches
</code></pre>

So if you have the following dir structure

<pre><code>tests/files
├── a0
│   ├── a0.txt
│   ├── a0.yaml
│   └── b0
│   ├── b0.yaml
│   └── b00.yaml
└── a1
</code></pre>

You can do something like this

<pre><code>files = utils.find_files('tests/files','**/b0/b*.yaml')
&gt; ['tests/files/a0/b0/b0.yaml', 'tests/files/a0/b0/b00.yaml']
</code></pre>

Pretty much <code>fnmatch</code> pattern match on the whole filename itself, rather than the filename only.

blocks|key|162789|text|configfiles+=+glob.glob('C:/Users/sam/Desktop/**/*.txt")|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|162790|并不是所有情况都适用，而是使用glob2|162791|configfiles+=+glob2.glob('C:/Users/sam/Desktop/**/*.txt")|code-block|syntax|javascript|162792|entityMap^0|0|1K|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

<code>configfiles = glob.glob('C:/Users/sam/Desktop/**/*.txt")</code> 

Doesn't works for all cases, instead use glob2 

<pre><code>configfiles = glob2.glob('C:/Users/sam/Desktop/**/*.txt")
</code></pre>

blocks|key|380741|text|如果你能安装glob2包...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|380742|import+glob2
filenames+=+glob2.glob("C:\\top_directory\\**\\*.ext")++#+Where+ext+is+a+specific+file+extension
folders+=+glob2.glob("C:\\top_directory\\**\\")|code-block|syntax|javascript|380743|所有文件名和文件夹：|380744|all_ff+=+glob2.glob("C:\\top_directory\\**\\**")++|380745|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you can install glob2 package... 

<pre><code>import glob2
filenames = glob2.glob("C:\\top_directory\\**\\*.ext") # Where ext is a specific file extension
folders = glob2.glob("C:\\top_directory\\**\\")
</code></pre>

All filenames and folders: 

<pre><code>all_ff = glob2.glob("C:\\top_directory\\**\\**") 
</code></pre>

blocks|key|380777|text|如果您运行的是Python+3.4%2B，则可以使用pathlib模块。Path.glob()方法支持**模式，这意味着“这个目录和所有子目录递归地”。它返回一个生成器，为所有匹配的文件生成Path对象。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|380778|from+pathlib+import+Path
configfiles+=+Path("C:/Users/sam/Desktop/file1/").glob("**/*.txt")|code-block|syntax|javascript|380779|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3.6/library/pathlib.html|1|https://docs.python.org/3.6/library/pathlib.html#pathlib.Path.glob|2|https://docs.python.org/3.6/library/pathlib.html#pathlib.Path^0|O|7|Y|B|1D|2|2L|4|O|7|0|Y|B|1|2L|4|2|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@$9|15|A|16|1|17]|$9|18|A|19|1|1A]|$9|1B|A|1C|1|1D]]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]|U|$5|N|O|P|E|$Q|V]]]]

If you're running Python 3.4+, you can use the <a href="https://docs.python.org/3.6/library/pathlib.html" rel="nofollow noreferrer"><code>pathlib</code></a> module. The <a href="https://docs.python.org/3.6/library/pathlib.html#pathlib.Path.glob" rel="nofollow noreferrer"><code>Path.glob()</code></a> method supports the <code>**</code> pattern, which means “this directory and all subdirectories, recursively”. It returns a generator yielding <a href="https://docs.python.org/3.6/library/pathlib.html#pathlib.Path" rel="nofollow noreferrer"><code>Path</code></a> objects for all matching files.

<pre><code>from pathlib import Path
configfiles = Path("C:/Users/sam/Desktop/file1/").glob("**/*.txt")
</code></pre>

blocks|key|162747|text|正如Martijn所指出的，glob只能通过Python3.5中引入的**操作符来实现这一点。由于OP显式地请求glob模块，下面的代码将返回一个行为类似的惰性求值迭代器|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|162748|import+os,+glob,+itertools

configfiles+=+itertools.chain.from_iterable(glob.iglob(os.path.join(root,'*.txt'))
+++++++++++++++++++++++++for+root,+dirs,+files+in+os.walk('C:/Users/sam/Desktop/file1/'))|code-block|syntax|javascript|162749|注意，在这种方法中，您只能在configfiles上迭代一次。如果您需要可在多个操作中使用的配置文件的真实列表，则必须使用list(configfiles)显式创建该列表。|162750|entityMap^0|Z|2|0|0|E|B|1P|H|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

As pointed out by Martijn, glob can only do this through the <code>**</code>operator introduced in Python 3.5. Since the OP explicitly asked for the glob module, the following will return a lazy evaluation iterator that behaves similarly

<pre><code>import os, glob, itertools

configfiles = itertools.chain.from_iterable(glob.iglob(os.path.join(root,'*.txt'))
 for root, dirs, files in os.walk('C:/Users/sam/Desktop/file1/'))
</code></pre>

Note that you can only iterate once over <code>configfiles</code> in this approach though. If you require a real list of configfiles that can be used in multiple operations you would have to create this explicitly by using <code>list(configfiles)</code>.

blocks|key|162950|text|命令rglob将在目录结构的最深层执行一次无限递归。但是，如果您只想要一个级别的深度，那么就不要使用它。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|162951|我知道特工说的是使用glob.glob。然而，我相信这满足了递归搜索所有子文件夹的意图。|162952|rglob函数最近将数据处理算法的速度提高了100倍，该算法使用文件夹结构作为数据读取顺序的固定假设。但是，使用rglob，我们可以对指定父目录下或以下的所有文件执行一次扫描，将它们的名称保存到列表(超过一百万个文件)中，然后使用该列表根据文件命名约定(仅与它们所在的文件夹)确定未来任何时候需要打开的文件。|162953|entityMap^0|2|5|0|0|0|5|1K|5|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|K|$]]

The command <code>rglob</code> will do an infinite recursion down the deepest sub-level of your directory structure. If you only want one level deep, then do not use it, however.

I realize the OP was talking about using glob.glob. I believe this answers the intent, however, which is to search all subfolders recursively.

The <code>rglob</code> function recently produced a 100x increase in speed for a data processing algorithm which was using the folder structure as a fixed assumption for the order of data reading. However, with <code>rglob</code> we were able to do a single scan once through all files at or below a specified parent directory, save their names to a list (over a million files), then use that list to determine which files we needed to open at any point in the future based on the file naming conventions only vs. which folder they were in.

blocks|key|380911|text|您可以直接从glob模块使用函数glob.glob()或glob.iglob()来递归地从目录/文件和子目录/子文件中检索路径。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|380912|语法：|380913|glob.glob(pathname,+*,+recursive=False)+#+pathname+=+'/path/to/the/directory'+or+subdirectory
glob.iglob(pathname,+*,+recursive=False)|code-block|syntax|javascript|380914|在您的示例中，可以这样编写：|380915|import+glob
import+os

configfiles+=+[f+for+f+in+glob.glob("C:/Users/sam/Desktop/*.txt")]

for+f+in+configfiles:
++++print(f'Filename+with+path:+{f}')
++++print(f'Only+filename:+{os.path.basename(f)}')
++++print(f'Filename+without+extensions:+{os.path.splitext(os.path.basename(f))[0]}')|380916|输出：|380917|Filename+with+path:+C:/Users/sam/Desktop/test_file.txt
Only+filename:+test_file.txt
Filename+without+extensions:+test_file|380918|帮助:用于os.path.splitext的Documentation和用于os.path.basename的documentation。|380919|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/os.path.html#os.path.splitext|1|https://docs.python.org/3/library/os.path.html#os.path.basename^0|G|B|S|C|0|0|0|0|0|0|0|5|G|12|G|M|D|0|1J|D|1|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@$9|1M|A|1N|1|1O]|$9|1P|A|1Q|1|1R]]|E|$]]|$1|W|3|-4|5|6|7|1S|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]|14|$5|Z|10|11|E|$12|15]]]]

You can use the function <code>glob.glob()</code> or <code>glob.iglob()</code> directly from glob module to retrieve paths recursively from inside the directories/files and subdirectories/subfiles.
Syntax:
<pre><code>glob.glob(pathname, *, recursive=False) # pathname = '/path/to/the/directory' or subdirectory
glob.iglob(pathname, *, recursive=False)
</code></pre>
In your example, it is possible to write like this:
<pre class="lang-py prettyprint-override"><code>
import glob
import os

configfiles = [f for f in glob.glob(&quot;C:/Users/sam/Desktop/*.txt&quot;)]

for f in configfiles:
 print(f'Filename with path: {f}')
 print(f'Only filename: {os.path.basename(f)}')
 print(f'Filename without extensions: {os.path.splitext(os.path.basename(f))[0]}')
</code></pre>
Output:
<pre class="lang-sh prettyprint-override"><code>Filename with path: C:/Users/sam/Desktop/test_file.txt
Only filename: test_file.txt
Filename without extensions: test_file
</code></pre>
Help:
<a href="https://docs.python.org/3/library/os.path.html#os.path.splitext" rel="nofollow noreferrer">Documentation</a> for <code>os.path.splitext</code> and <a href="https://docs.python.org/3/library/os.path.html#os.path.basename" rel="nofollow noreferrer">documentation</a> for <code>os.path.basename</code>.

blocks|key|163056|text|(第一个选项当然是在其他答案中提到的，这里的目标是展示glob在内部使用os.scandir，并提供一个直接的答案)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|163057|163058|使用glob|163059|正如前面所解释的，使用Python+3.5%2B很容易：|163060|import+glob
for+f+in+glob.glob('d:/temp/**/*',+recursive=True):
++++print(f)

#d:\temp\New+folder
#d:\temp\New+Text+Document+-+Copy.txt
#d:\temp\New+folder\New+Text+Document+-+Copy.txt
#d:\temp\New+folder\New+Text+Document.txt|code-block|syntax|javascript|163061|使用pathlib|163062|from+pathlib+import+Path
for+f+in+Path('d:/temp').glob('**/*'):
++++print(f)|163063|使用os.scandir|163064|os.scandir是glob在内部执行的操作。下面是如何使用yield直接做这件事|163065|def+listpath(path):
++++for+f+in+os.scandir(path):
++++++++f2+=+os.path.join(path,+f)
++++++++if+os.path.isdir(f):
++++++++++++yield+f2
++++++++++++yield+from+listpath(f2)
++++++++else:
++++++++++++yield+f2

for+f+in+listpath('d:\\temp'):
++++print(f)|163066|entityMap^0|10|A|0|0|0|0|0|0|0|0|0|A|B|4|V|5|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|14|8|@]|D|@]|E|$]]|$1|G|3|H|5|6|7|15|8|@]|D|@]|E|$]]|$1|I|3|J|5|6|7|16|8|@]|D|@]|E|$]]|$1|K|3|L|5|M|7|17|8|@]|D|@]|E|$N|O]]|$1|P|3|Q|5|6|7|18|8|@]|D|@]|E|$]]|$1|R|3|S|5|M|7|19|8|@]|D|@]|E|$N|O]]|$1|T|3|U|5|6|7|1A|8|@]|D|@]|E|$]]|$1|V|3|W|5|6|7|1B|8|@$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]]|D|@]|E|$]]|$1|X|3|Y|5|M|7|1I|8|@]|D|@]|E|$N|O]]|$1|Z|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|10|$]]

(The first options are of course mentioned in other answers, here the goal is to show that glob uses <code>os.scandir</code> internally, and provide a direct answer with this).
<hr />
<h2>Using glob</h2>
As explained before, with Python 3.5+, it's easy:
<pre><code>import glob
for f in glob.glob('d:/temp/**/*', recursive=True):
 print(f)

#d:\temp\New folder
#d:\temp\New Text Document - Copy.txt
#d:\temp\New folder\New Text Document - Copy.txt
#d:\temp\New folder\New Text Document.txt
</code></pre>
<h2>Using pathlib</h2>
<pre><code>from pathlib import Path
for f in Path('d:/temp').glob('**/*'):
 print(f)
</code></pre>
<h2>Using os.scandir</h2>
<code>os.scandir</code> is what <code>glob</code> does internally. So here is how to do it directly, with a use of <code>yield</code>:
<pre><code>def listpath(path):
 for f in os.scandir(path):
 f2 = os.path.join(path, f)
 if os.path.isdir(f):
 yield f2
 yield from listpath(f2)
 else:
 yield f2

for f in listpath('d:\\temp'):
 print(f)
</code></pre>

I want to open a series of subfolders in a folder and find some text files and print some lines of the text files. I am using this:

<pre><code>configfiles = glob.glob('C:/Users/sam/Desktop/file1/*.txt')
</code></pre>

But this cannot access the subfolders as well. Does anyone know how I can use the same command to access subfolders as well?

How can I search sub-folders using glob.glob module?

我想打开文件夹中的一系列子文件夹，找到一些文本文件并打印其中的几行。我使用的是：configfiles = glob.glob('C:/Users/sam/Desktop/file1/*.txt')但是这也不能访问子文件夹。有人知道如何使用相同的命令来访问子文件夹吗？

问如何使用glob.glob模块搜索子文件夹？
EN

回答 11

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问如何使用glob.glob模块搜索子文件夹？
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