blocks|key|1324204|text|你可以试一试dateutil+--尤其是它的relativedelta和rrule+fetures。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1324205|entityMap|0|LINK|mutability|MUTABLE|url|http://labix.org/python-dateutil^0|6|8|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

You can give <a href="http://labix.org/python-dateutil" rel="nofollow noreferrer">dateutil</a> a try - especially its relativedelta and rrule fetures.

blocks|key|1324297|text|你可以尝试自己写这篇文章。您首先需要一个迭代器，该迭代器生成由给定间隔分隔的日期：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1324298|import+datetime

def+dateiter(start,+resolution):
++++date+=+start
++++while+True:
++++++++++++yield+date
++++++++++++date+%2B=+resolution|code-block|syntax|javascript|1324299|现在，您可以生成日期并对其进行过滤：|1324300|#+generate+a+list+of+every+tuesday+of+february
#+this+iterates+over+every+day+from+now,+and+filtered+according+to+the+rules
#+warning:+infinite+generator+below,+there+is+nothing+to+end+the+iteration
tuesdays_of_february+=+(date+for+date+in+dateiter(datetime.datetime.now(),+datetime.timedelta(days=1))+if+date.weekday()+==+4+and+date.month+==+2)|1324301|您可以自己调用迭代器，直到您有足够的日期：|1324302|>>>+next(tuesdays_of_february)
datetime.datetime(2010,+2,+19,+14,+25,+46,+171000)|1324303|现在，您需要限制结果：|1324304|>>>+from+itertools+import+*
>>>+
>>>+#+get+the+five+next+valid+dates:
>>>+list(islice(tuesdays_of_february),5)
[datetime.datetime(2010,+2,26,+14,+25,+46,+171000),+datetime.datetime(2011,+2,+4
,+14,+25,+46,+171000),+datetime.datetime(2011,+2,+11,+14,+25,+46,+171000),+datet
ime.datetime(2011,+2,+18,+1++++4,+25,+46,+171000),+datetime.datetime(2011,+2,+25
,+14,+25,+46,+171000)]
>>>+
>>>+#+or+until+a+condition+is+met:
>>>+list(takewhile(+lambda+date:+date.year+<+2014,+tuesdays_of_february+))
[datetime.datetime(2012,+2,+3,+14,+25,+46,+171000),+datetime.datetime(2012,+2,+1
0,+14,+25,+46,+171000),+datetime.datetime(2012,+2,+17,+14,+25,+46,+171000),+date
time.datetime(2012,+2,+24,+14,+25,+46,+171000),+datetime.datetime(2013,+2,+1,+14
,+25,+46,+171000),+datetime.datetime(2013,+2,+8,+14,+25,+46,+171000),+datetime.d
atetime(2013,+2,+15,+14,+25,+46,+171000),+datetime.datetime(2013,+2,+22,+14,+25,
+46,+171000)]|1324305|不要忘记查看datetime模块的文档。|offset|length|style|CODE|1324306|entityMap^0|0|0|0|0|0|0|0|0|6|8|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|18|8|@$U|19|V|1A|W|X]]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

you may try to write this yourself. you will first need an iterator which generates dates separated by a given interval: 

<pre><code>import datetime

def dateiter(start, resolution):
 date = start
 while True:
 yield date
 date += resolution
</code></pre>

now, you can generate dates and filter them:

<pre><code># generate a list of every tuesday of february
# this iterates over every day from now, and filtered according to the rules
# warning: infinite generator below, there is nothing to end the iteration
tuesdays_of_february = (date for date in dateiter(datetime.datetime.now(), datetime.timedelta(days=1)) if date.weekday() == 4 and date.month == 2)
</code></pre>

you can call the iterator yourself until you have enough dates:

<pre><code>&gt;&gt;&gt; next(tuesdays_of_february)
datetime.datetime(2010, 2, 19, 14, 25, 46, 171000)
</code></pre>

now, you need to limit the results:

<pre><code>&gt;&gt;&gt; from itertools import *
&gt;&gt;&gt; 
&gt;&gt;&gt; # get the five next valid dates:
&gt;&gt;&gt; list(islice(tuesdays_of_february),5)
[datetime.datetime(2010, 2,26, 14, 25, 46, 171000), datetime.datetime(2011, 2, 4
, 14, 25, 46, 171000), datetime.datetime(2011, 2, 11, 14, 25, 46, 171000), datet
ime.datetime(2011, 2, 18, 1 4, 25, 46, 171000), datetime.datetime(2011, 2, 25
, 14, 25, 46, 171000)]
&gt;&gt;&gt; 
&gt;&gt;&gt; # or until a condition is met:
&gt;&gt;&gt; list(takewhile( lambda date: date.year &lt; 2014, tuesdays_of_february ))
[datetime.datetime(2012, 2, 3, 14, 25, 46, 171000), datetime.datetime(2012, 2, 1
0, 14, 25, 46, 171000), datetime.datetime(2012, 2, 17, 14, 25, 46, 171000), date
time.datetime(2012, 2, 24, 14, 25, 46, 171000), datetime.datetime(2013, 2, 1, 14
, 25, 46, 171000), datetime.datetime(2013, 2, 8, 14, 25, 46, 171000), datetime.d
atetime(2013, 2, 15, 14, 25, 46, 171000), datetime.datetime(2013, 2, 22, 14, 25,
 46, 171000)]
</code></pre>

don't forget to have a look at the documentation for the <code>datetime</code> module.

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