blocks|key|3034404|text|>>>+import+string
>>>+string.ascii_lowercase[:14]
'abcdefghijklmn'
>>>+string.ascii_lowercase[:14:2]
'acegikm'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3034405|要创建urls，您可以使用如下代码|unstyled|3034406|[i+%2B+j+for+i,+j+in+zip(list_of_urls,+string.ascii_lowercase[:14])]|3034407|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>&gt;&gt;&gt; import string
&gt;&gt;&gt; string.ascii_lowercase[:14]
'abcdefghijklmn'
&gt;&gt;&gt; string.ascii_lowercase[:14:2]
'acegikm'
</code></pre>

<p>To do the urls, you could use something like this</p>

<pre><code>[i + j for i, j in zip(list_of_urls, string.ascii_lowercase[:14])]
</code></pre>


blocks|key|300704|text|假设这是一个家庭作业;-)+-不需要调用库等-它可能希望你使用range()和chr/ord，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|300705|for+i+in+range(ord('a'),+ord('n')%2B1):
++++print+chr(i),|code-block|syntax|javascript|300706|对于其余部分，只需使用range()|300707|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>Assuming this is a homework ;-) - no need to summon libraries etc - it probably expect you to use range() with chr/ord, like so:</p>

<pre><code>for i in range(ord('a'), ord('n')+1):
    print chr(i),
</code></pre>

<p>For the rest, just play a bit more with the range()</p>


blocks|key|303802|text|提示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303803|import+string
print+string.ascii_lowercase|code-block|syntax|javascript|303804|和|303805|for+i+in+xrange(0,+10,+2):
++++print+i|303806|303807|"hello{0},+world!".format('z')|303808|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|K|3|H|5|6|7|T|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

<p>Hints:</p>

<pre><code>import string
print string.ascii_lowercase
</code></pre>

<p>and </p>

<pre><code>for i in xrange(0, 10, 2):
    print i
</code></pre>

<p>and</p>

<pre><code>"hello{0}, world!".format('z')
</code></pre>


blocks|key|3034409|text|for+one+in+range(97,110):
++++print+chr(one)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3034410|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for one in range(97,110):
    print chr(one)
</code></pre>


blocks|key|302988|text|获取包含所需值的列表|type|unstyled|depth|inlineStyleRanges|entityRanges|data|302989|small_letters+=+map(chr,+range(ord('a'),+ord('z')%2B1))
big_letters+=+map(chr,+range(ord('A'),+ord('Z')%2B1))
digits+=+map(chr,+range(ord('0'),+ord('9')%2B1))|code-block|syntax|javascript|302990|或|302991|import+string
string.letters
string.uppercase
string.digits|302992|此解决方案使用ASCII+table。ord从字符获取ASCII值，chr从字符获取ASCII值。|offset|length|style|CODE|302993|应用你对列表的了解|302994|>>>+small_letters+=+map(chr,+range(ord('a'),+ord('z')%2B1))

>>>+an+=+small_letters[0:(ord('n')-ord('a')%2B1)]
>>>+print("+".join(an))
a+b+c+d+e+f+g+h+i+j+k+l+m+n

>>>+print("+".join(small_letters[0::2]))
a+c+e+g+i+k+m+o+q+s+u+w+y

>>>+s+=+small_letters[0:(ord('n')-ord('a')%2B1):2]
>>>+print("+".join(s))
a+c+e+g+i+k+m

>>>+urls+=+["hello.com/",+"hej.com/",+"hallo.com/"]
>>>+print([x+%2B+y+for+x,+y+in+zip(urls,+an)])
['hello.com/a',+'hej.com/b',+'hallo.com/c']|302995|entityMap|0|LINK|mutability|MUTABLE|url|http://www.asciitable.com/|1|https://docs.python.org/2/library/functions.html#ord|2|https://docs.python.org/2/library/functions.html#chr^0|0|0|0|0|J|3|Y|3|7|B|0|J|3|1|Y|3|2|0|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|18|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1A|8|@$M|1B|N|1C|O|P]|$M|1D|N|1E|O|P]]|9|@$M|1F|N|1G|1|1H]|$M|1I|N|1J|1|1K]|$M|1L|N|1M|1|1N]]|A|$]]|$1|Q|3|R|5|6|7|1O|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1P|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]|14|$5|X|Y|Z|A|$10|15]]]]

<h2>Get a list with the desired values</h2>

<pre><code>small_letters = map(chr, range(ord('a'), ord('z')+1))
big_letters = map(chr, range(ord('A'), ord('Z')+1))
digits = map(chr, range(ord('0'), ord('9')+1))
</code></pre>

<p>or</p>

<pre><code>import string
string.letters
string.uppercase
string.digits
</code></pre>

<p>This solution uses the <a href="http://www.asciitable.com/" rel="noreferrer">ASCII table</a>. <a href="https://docs.python.org/2/library/functions.html#ord" rel="noreferrer"><code>ord</code></a> gets the ascii value from a character and <a href="https://docs.python.org/2/library/functions.html#chr" rel="noreferrer"><code>chr</code></a> vice versa.</p>

<h2>Apply what you know about lists</h2>

<pre><code>&gt;&gt;&gt; small_letters = map(chr, range(ord('a'), ord('z')+1))

&gt;&gt;&gt; an = small_letters[0:(ord('n')-ord('a')+1)]
&gt;&gt;&gt; print(" ".join(an))
a b c d e f g h i j k l m n

&gt;&gt;&gt; print(" ".join(small_letters[0::2]))
a c e g i k m o q s u w y

&gt;&gt;&gt; s = small_letters[0:(ord('n')-ord('a')+1):2]
&gt;&gt;&gt; print(" ".join(s))
a c e g i k m

&gt;&gt;&gt; urls = ["hello.com/", "hej.com/", "hallo.com/"]
&gt;&gt;&gt; print([x + y for x, y in zip(urls, an)])
['hello.com/a', 'hej.com/b', 'hallo.com/c']
</code></pre>


blocks|key|3248644|text|import+string
print+list(string.ascii_lowercase)
#+['a',+'b',+'c',+'d',+'e',+'f',+'g',+'h',+'i',+'j',+'k',+'l',+'m',+'n',+'o',+'p',+'q',+'r',+'s',+'t',+'u',+'v',+'w',+'x',+'y',+'z']|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3248645|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import string
print list(string.ascii_lowercase)
# ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
</code></pre>


blocks|key|3248802|text|import+string
print+list(string.ascii_lowercase)
#+['a',+'b',+'c',+'d',+'e',+'f',+'g',+'h',+'i',+'j',+'k',+'l',+'m',+'n',+'o',+'p',+'q',+'r',+'s',+'t',+'u',+'v',+'w',+'x',+'y',+'z']|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3248803|和|unstyled|3248804|for+c+in+list(string.ascii_lowercase)[:5]:
++++...operation+with+the+first+5+characters|3248805|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>import string
print list(string.ascii_lowercase)
# ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
</code></pre>

<p>and</p>

<pre><code>for c in list(string.ascii_lowercase)[:5]:
    ...operation with the first 5 characters
</code></pre>


blocks|key|3034677|text|myList+=+[chr(chNum)+for+chNum+in+list(range(ord('a'),ord('z')%2B1))]
print(myList)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3034678|输出|unstyled|3034679|['a',+'b',+'c',+'d',+'e',+'f',+'g',+'h',+'i',+'j',+'k',+'l',+'m',+'n',+'o',+'p',+'q',+'r',+'s',+'t',+'u',+'v',+'w',+'x',+'y',+'z']|3034680|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>myList = [chr(chNum) for chNum in list(range(ord('a'),ord('z')+1))]
print(myList)
</code></pre>

<p>Output</p>

<pre><code>['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
</code></pre>


blocks|key|3034682|text|import+string

string.printable[10:36]
#+abcdefghijklmnopqrstuvwxyz
++++
string.printable[10:62]
#+abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3034683|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre class="lang-py prettyprint-override"><code>import string

string.printable[10:36]
# abcdefghijklmnopqrstuvwxyz
    
string.printable[10:62]
# abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
</code></pre>


blocks|key|3034456|text|#1)
print+"+".join(map(chr,+range(ord('a'),ord('n')%2B1)))

#2)
print+"+".join(map(chr,+range(ord('a'),ord('n')%2B1,2)))

#3)
urls+=+["hello.com/",+"hej.com/",+"hallo.com/"]
an+=+map(chr,+range(ord('a'),ord('n')%2B1))
print+[+x+%2B+y+for+x,y+in+zip(urls,+an)]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3034457|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#1)
print " ".join(map(chr, range(ord('a'),ord('n')+1)))

#2)
print " ".join(map(chr, range(ord('a'),ord('n')+1,2)))

#3)
urls = ["hello.com/", "hej.com/", "hallo.com/"]
an = map(chr, range(ord('a'),ord('n')+1))
print [ x + y for x,y in zip(urls, an)]
</code></pre>


blocks|key|303855|text|尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303856|strng+=+""
for+i+in+range(97,123):
++++strng+=+strng+%2B+chr(i)
print(strng)|code-block|syntax|javascript|303857|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Try:   </p>

<pre><code>strng = ""
for i in range(97,123):
    strng = strng + chr(i)
print(strng)
</code></pre>


blocks|key|303086|text|这个问题的答案很简单，只需创建一个名为ABC的列表，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303087|ABC+=+['abcdefghijklmnopqrstuvwxyz']|code-block|syntax|javascript|303088|当你需要参考它的时候，只需这样做：|303089|print+ABC[0:9]+#prints+abcdefghij
print+ABC+++++++#prints+abcdefghijklmnopqrstuvwxyz
for+x+in+range(0,25):
++++if+x+%25+2+==+0:
++++++++print+ABC[x]+#prints+acegikmoqsuwy+(all+odd+numbered+letters)|303090|还可以尝试执行以下操作来中断您的设备:D|303091|##Try+this+and+call+it+AlphabetSoup.py:

ABC+=+['abcdefghijklmnopqrstuvwxyz']


try:
++++while+True:
++++++++for+a+in+ABC:
++++++++++++for+b+in+ABC:
++++++++++++++++for+c+in+ABC:
++++++++++++++++++++for+d+in+ABC:
++++++++++++++++++++++++for+e+in+ABC:
++++++++++++++++++++++++++++for+f+in+ABC:
++++++++++++++++++++++++++++++++print+a,+b,+c,+d,+e,+f,+'++++',
except+KeyboardInterrupt:
++++pass|303092|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

<p>The answer to this question is simple, just make a list called ABC like so:</p>

<pre><code>ABC = ['abcdefghijklmnopqrstuvwxyz']
</code></pre>

<p>And whenever you need to refer to it, just do:</p>

<pre><code>print ABC[0:9] #prints abcdefghij
print ABC       #prints abcdefghijklmnopqrstuvwxyz
for x in range(0,25):
    if x % 2 == 0:
        print ABC[x] #prints acegikmoqsuwy (all odd numbered letters)
</code></pre>

<p>Also try this to break ur device :D</p>

<pre><code>##Try this and call it AlphabetSoup.py:

ABC = ['abcdefghijklmnopqrstuvwxyz']


try:
    while True:
        for a in ABC:
            for b in ABC:
                for c in ABC:
                    for d in ABC:
                        for e in ABC:
                            for f in ABC:
                                print a, b, c, d, e, f, '    ',
except KeyboardInterrupt:
    pass
</code></pre>


blocks|key|3034412|text|这是你的第二个问题：string.lowercase[ord('a')-97:ord('n')-97:2]，因为97==ord('a')+--如果你想学一点，你应该自己弄清楚剩下的部分;-)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3034413|entityMap^0|A|17|1K|C|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

<p>This is your 2nd question: <code>string.lowercase[ord('a')-97:ord('n')-97:2]</code> because <code>97==ord('a')</code> -- if you want to learn a bit you should figure out the rest yourself ;-)</p>


blocks|key|3248647|text|list(string.ascii_lowercase)

['a',+'b',+'c',+'d',+'e',+'f',+'g',+'h',+'i',+'j',+'k',+'l',+'m',+'n',+'o',+'p',+'q',+'r',+'s',+'t',+'u',+'v',+'w',+'x',+'y',+'z']|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3248648|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>list(string.ascii_lowercase)

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
</code></pre>


blocks|key|3248823|text|我希望这能有所帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3248824|import+string

alphas+=+list(string.ascii_letters[:26])
for+chr+in+alphas:
+print(chr)|code-block|syntax|javascript|3248825|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>I hope this helps:</p>

<pre><code>import string

alphas = list(string.ascii_letters[:26])
for chr in alphas:
 print(chr)
</code></pre>


blocks|key|305884|text|关于格尼布勒的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|305885|Zip+-function，full+explanation，returns+a+list+of+tuples,+where+the+i-th+tuple+contains+the+i-th+element+from+each+of+the+argument+sequences+or+iterables.+[...]构造叫做list+comprehension，非常酷的特性！|offset|length|style|CODE|305886|entityMap|0|LINK|mutability|MUTABLE|url|http://www.python.org/doc//current/library/functions.html|1|http://docs.python.org/tutorial/datastructures.html#list-comprehensions^0|0|13|36|4A|5|E|G|0|4J|I|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]|$D|V|E|W|F|G]]|9|@$D|X|E|Y|1|Z]|$D|10|E|11|1|12]]|A|$]]|$1|H|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]|P|$5|K|L|M|A|$N|Q]]]]

<p>About gnibbler's answer. </p>

<p>Zip -function, <a href="http://www.python.org/doc//current/library/functions.html" rel="nofollow">full explanation</a>, returns <code>a list of tuples, where the i-th tuple contains the i-th element from each of the argument sequences or iterables.</code> <code>[...]</code> construct is called <a href="http://docs.python.org/tutorial/datastructures.html#list-comprehensions" rel="nofollow">list comprehension</a>, very cool feature!</p>


blocks|key|3248813|text|另一种方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3248814|import+string

aalist+=+list(string.ascii_lowercase)
aaurls+=+['alpha.com','bravo.com','chrly.com','delta.com',]
iilen++=++aaurls.__len__()

ans01+=+"".join(+(aalist[0:14])+)
ans02+=+"".join(+(aalist[0:14:2])+)
ans03+=+"".join(+"{vurl}/{vl}\n".format(vl=vlet,vurl=aaurls[vind+%25+iilen])+for+vind,vlet+in+enumerate(aalist[0:14])+)

print(ans01)
print(ans02)
print(ans03)|code-block|syntax|javascript|3248815|结果|3248816|abcdefghijklmn
acegikm
alpha.com/a
bravo.com/b
chrly.com/c
delta.com/d
alpha.com/e
bravo.com/f
chrly.com/g
delta.com/h
alpha.com/i
bravo.com/j
chrly.com/k
delta.com/l
alpha.com/m
bravo.com/n|3248817|此回复与其他回复有何不同|3248818|3248819|遍历任意数量的基本urls，并使用模块化算法循环遍历这些urls，并且不会停止，直到我们用完了所有字母，并将enumerate与list+cycle|unordered-list-item|offset|length|style|CODE|3248820|+str.format结合使用|3248821|entityMap^0|0|0|0|0|0|0|1I|9|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|13|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|14|8|@$Q|15|R|16|S|T]]|9|@]|A|$]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

<h2>Another way to do it</h2>
<pre><code>import string

aalist = list(string.ascii_lowercase)
aaurls = ['alpha.com','bravo.com','chrly.com','delta.com',]
iilen  =  aaurls.__len__()

ans01 = &quot;&quot;.join( (aalist[0:14]) )
ans02 = &quot;&quot;.join( (aalist[0:14:2]) )
ans03 = &quot;&quot;.join( &quot;{vurl}/{vl}\n&quot;.format(vl=vlet,vurl=aaurls[vind % iilen]) for vind,vlet in enumerate(aalist[0:14]) )

print(ans01)
print(ans02)
print(ans03)
</code></pre>
<h2>Result</h2>
<pre><code>abcdefghijklmn
acegikm
alpha.com/a
bravo.com/b
chrly.com/c
delta.com/d
alpha.com/e
bravo.com/f
chrly.com/g
delta.com/h
alpha.com/i
bravo.com/j
chrly.com/k
delta.com/l
alpha.com/m
bravo.com/n
</code></pre>
<h2>How this differs from the other replies</h2>
<ul>
<li>iterate over an arbitrary number of base urls</li>
<li>cycle through the urls using modular arithmetic, and do not stop until we run out of letters</li>
<li>use <code>enumerate</code> in conjunction with list comprehension and str.format</li>
</ul>


blocks|key|303942|text|#+Assign+the+range+of+characters
first_char_start+=+'a'
last_char+=+'n'

#+Generate+a+list+of+assigned+characters+(here+from+'a'+to+'n')
alpha_list+=+[chr(i)+for+i+in+range(ord(first_char),+ord(last_char)+%2B+1)]

#+Print+a-n+with+spaces:+a+b+c+d+e+f+g+h+i+j+k+l+m+n
print("+".join(alpha_list))

#+Every+second+in+a-n:+a+c+e+g+i+k+m
print("+".join(alpha_list[::2]))

#+Append+a-n+to+index+of+urls{hello.com/,+hej.com/,+...,+hallo.com/}
#+Ex.hello.com/a+hej.com/b+...+hallo.com/n

#urls:+list+of+urls
results+=+[i%2Bj+for+i,+j+in+zip(urls,+alpha_list)]

#print+new+url+list+'results'+(concatenated+two+lists+element-wise)
print(results)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|303943|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre class="lang-py prettyprint-override"><code># Assign the range of characters
first_char_start = 'a'
last_char = 'n'

# Generate a list of assigned characters (here from 'a' to 'n')
alpha_list = [chr(i) for i in range(ord(first_char), ord(last_char) + 1)]

# Print a-n with spaces: a b c d e f g h i j k l m n
print(&quot; &quot;.join(alpha_list))

# Every second in a-n: a c e g i k m
print(&quot; &quot;.join(alpha_list[::2]))

# Append a-n to index of urls{hello.com/, hej.com/, ..., hallo.com/}
# Ex.hello.com/a hej.com/b ... hallo.com/n

#urls: list of urls
results = [i+j for i, j in zip(urls, alpha_list)]

#print new url list 'results' (concatenated two lists element-wise)
print(results)
</code></pre>


<p><strong>1. Print a-n:</strong> a b c d e f g h i j k l m n</p>

<p><strong>2. Every second in a-n:</strong> a c e g i k m</p>

<p><strong>3. Append a-n to index of urls{hello.com/, hej.com/, ..., hallo.com/}:</strong> hello.com/a hej.com/b ... hallo.com/n</p>


Python: how to print range a-z?

1.打印a-n: a b c d e f g h i j k l m n2. a-n中的每秒：a c e g i k m3.将a-n附加到urls的索引{hello.com/，hej.com/，...，hallo.com/}: hello.com/a hej.com/b...hallo.com/n

问Python:如何打印a-z范围？
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