blocks|key|476864|text|在linq中，多维数组可以作为一维可枚举数组使用。你只需要检查所有维度的长度。这段代码应该足够了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|476865|var+equal+=
++++data1.Rank+==+data2.Rank+&&
++++Enumerable.Range(0,data1.Rank).All(dimension+=>+data1.GetLength(dimension)+==+data2.GetLength(dimension))+&&
++++data1.Cast<double>().SequenceEqual(data2.Cast<double>());|code-block|syntax|javascript|476866|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A multidimensional array can be used in linq as one dimensional enumerable. You just need to check also for the length of all dimensions. This snippet should be enough:

<pre><code>var equal =
 data1.Rank == data2.Rank &amp;&amp;
 Enumerable.Range(0,data1.Rank).All(dimension =&gt; data1.GetLength(dimension) == data2.GetLength(dimension)) &amp;&amp;
 data1.Cast&lt;double&gt;().SequenceEqual(data2.Cast&lt;double&gt;());
</code></pre>

blocks|key|260042|text|你可以做到的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|260043|data1.SequenceEqual(data2);++|code-block|syntax|javascript|260044|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do this 

<pre><code>data1.SequenceEqual(data2); 
</code></pre>

blocks|key|260090|text|您可以使用.Cast<String>展开多维数组|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|260091|Console.WriteLine("2D+Array");
String[,]+array2d+=+new+String[,]+{+{+"A1",+"B1"+},+{+"A2",+"B2"+}+};
foreach(var+s+in+array2d.Cast<String>())
++++Console.Write(s+%2B+",+");

Console.WriteLine("\r\n3D+Array");
String[,]+array3d+=+new+String[,]+{+{+"A1",+"B1",+"C1"+},+{+"A2",+"B2",+"C1"+}+};
foreach+(var+s+in+array3d.Cast<String>())
++++Console.Write(s+%2B+",+");|code-block|syntax|javascript|260092|输出|260093|2D+Array
A1,+B1,+A2,+B2,+
3D+Array
A1,+B1,+C1,+A2,+B2,+C1,+|260094|entityMap^0|5|D|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You can flat a multi-dimension array with <code>.Cast&lt;String&gt;</code>

<pre><code>Console.WriteLine("2D Array");
String[,] array2d = new String[,] { { "A1", "B1" }, { "A2", "B2" } };
foreach(var s in array2d.Cast&lt;String&gt;())
 Console.Write(s + ", ");

Console.WriteLine("\r\n3D Array");
String[,] array3d = new String[,] { { "A1", "B1", "C1" }, { "A2", "B2", "C1" } };
foreach (var s in array3d.Cast&lt;String&gt;())
 Console.Write(s + ", ");
</code></pre>

<h1>Output</h1>

<pre><code>2D Array
A1, B1, A2, B2, 
3D Array
A1, B1, C1, A2, B2, C1, 
</code></pre>

blocks|key|260152|text|你也可以尝试用2个for循环来解决这个问题，并将它们与计数器进行比较。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|260153|也许是这样的？|260154|for(int+counter1+=+0;+counter1+<+data1.GetLength(0);+counter1%2B%2B)
{
+++for(int+counter2+=+0;+counter2+<+data2.GetLength(1);+counter2%2B%2B)
+++{
++++++if(data1[counter1,+counter2]+==+data2[counter1,+counter2])
++++++{
+++++++++bool+isEqual+=+true;
++++++}++++
+++}
}++++++|code-block|syntax|javascript|260155|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

you can also try to solve it with 2 for-loops and comparing them with the counters.

maybe something like this? 

<pre><code>for(int counter1 = 0; counter1 &lt; data1.GetLength(0); counter1++)
{
 for(int counter2 = 0; counter2 &lt; data2.GetLength(1); counter2++)
 {
 if(data1[counter1, counter2] == data2[counter1, counter2])
 {
 bool isEqual = true;
 } 
 }
} 
</code></pre>

blocks|key|260171|text|用于比较2D数组的通用扩展方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|260172|public+static+bool+SequenceEquals<T>(this+T[,]+a,+T[,]+b)+=>+a.Rank+==+b.Rank
++++&&+Enumerable.Range(0,+a.Rank).All(d=>+a.GetLength(d)+==+b.GetLength(d))
++++&&+a.Cast<T>().SequenceEqual(b.Cast<T>());|code-block|syntax|javascript|260173|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A generic extension method to compare 2D arrays:
<pre><code>public static bool SequenceEquals&lt;T&gt;(this T[,] a, T[,] b) =&gt; a.Rank == b.Rank
 &amp;&amp; Enumerable.Range(0, a.Rank).All(d=&gt; a.GetLength(d) == b.GetLength(d))
 &amp;&amp; a.Cast&lt;T&gt;().SequenceEqual(b.Cast&lt;T&gt;());
</code></pre>

How to compare multidimensional arrays? Just true/false.

<pre><code>double[,] data1 = new double[,] { { 1, 2 }, { 3, 4 }, { 5, 6 }, { 7, 8 } }; 
double[,] data2 = new double[,] { { 1, 2 }, { 3, 4 }, { 5, 6 }, { 7, 8 } };

//bool compare = data1.SequenceEqual(data2);
</code></pre>

Is there way to compare 2d arrays like 1d array ? 

<pre><code>data1.SequenceEqual(data2); 
</code></pre>

I have to compare every second, so easiest way will be great. Thanks a lot.

How to compare multidimensional arrays in C# ?

如何比较多维数组？就是真/假。double[,] data1 = new double[,] { { 1, 2 }, { 3, 4 }, { 5, 6 }, { 7, 8 } };    double[,] data2 = new double[,] { { 1, 2 }, { 3, 4 }, { 5, 6 }, { ...

问如何在C#中比较多维数组？
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