blocks|key|1412131|text|抱歉，没有提到我在Solaris系统上。因此，-date开关在Solaris+bash上不可用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1412132|我发现我可以通过时区的小技巧得到之前的日期。|1412133|DATE=`TZ=MYT%2B16+date+%2B%25Y-%25m-%25d_%25r`
echo+$DATE|code-block|syntax|javascript|1412134|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Sorry not mentioning I on Solaris system.
As such, the -date switch is not available on Solaris bash.

I find out I can get the previous date with little trick on timezone.

<pre><code>DATE=`TZ=MYT+16 date +%Y-%m-%d_%r`
echo $DATE
</code></pre>

blocks|key|1196566|text|如果你有GNU日期并且我正确地理解了你|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1196567|$+date+%2B%25Y:%25m:%25d+-d+"yesterday"
2009:11:09|code-block|syntax|javascript|1196568|或|1196569|$+date+%2B%25Y:%25m:%25d+-d+"1+day+ago"
2009:11:09|1196570|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

if you have GNU date and i understood you correctly

<pre><code>$ date +%Y:%m:%d -d "yesterday"
2009:11:09
</code></pre>

or 

<pre><code>$ date +%Y:%m:%d -d "1 day ago"
2009:11:09
</code></pre>

blocks|key|1412200|text|如果你有BSD+(OSX)+date你可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1412201|date+-j+-v-1d
Wed+Dec+14+15:34:14+CET+2011|code-block|syntax|javascript|1412202|或者，如果您想在任意日期进行日期计算：|1412203|date+-j+-v-1d+-f+"%25Y-%25m-%25d"+"2011-09-01"+"%2B%25Y-%25m-%25d"
2011-08-31|1412204|entityMap^0|E|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

If you have BSD (OSX) <code>date</code> you can do it like this:

<pre><code>date -j -v-1d
Wed Dec 14 15:34:14 CET 2011
</code></pre>

Or if you want to do date calculations on an arbitrary date:

<pre><code>date -j -v-1d -f "%Y-%m-%d" "2011-09-01" "+%Y-%m-%d"
2011-08-31
</code></pre>

blocks|key|1196597|text|date+--date='-1+day'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1196598|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|1412264|text|好吧，这是一个迟来的答案，但这似乎是有效的！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1412265|+++++YESTERDAY=`TZ=GMT%2B24+date+%2B%25d-%25m-%25Y`;
+++++echo+$YESTERDAY;|code-block|syntax|javascript|1412266|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Well this is a late answer,but this seems to work!!

<pre><code> YESTERDAY=`TZ=GMT+24 date +%d-%m-%Y`;
 echo $YESTERDAY;
</code></pre>

blocks|key|1196724|text|Advanced+Bash-scripting+Guide|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1196725|date+%2B%25Y:%25m:%25d+-d+"yesterday"|code-block|syntax|javascript|1196726|有关日期格式的详细信息，请参见date手册页|1196727|date+--date='-1+day'|1196728|entityMap|0|LINK|mutability|MUTABLE|url|http://tldp.org/LDP/abs/html/timedate.html|1|http://ss64.com/bash/date.html^0|0|T|0|0|0|F|4|1|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|K|3|L|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

<a href="http://tldp.org/LDP/abs/html/timedate.html" rel="noreferrer">Advanced Bash-scripting Guide</a>

<pre><code>date +%Y:%m:%d -d "yesterday"
</code></pre>

For details about the date format see the man page for <a href="http://ss64.com/bash/date.html" rel="noreferrer">date</a>

<pre><code>date --date='-1 day'
</code></pre>

blocks|key|1196837|text|可以使用Perl来代替吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1196838|perl+-e+'print+scalar+localtime(+time+-+86400+)+.+"\n";'|code-block|syntax|javascript|1196839|或者，使用nawk和(Ab)使用/usr/bin/adb：|1196840|nawk+'BEGIN{printf+"0t%25d=Y\n",+srand()-86400}'+%7C+adb|1196841|也遇到了this。疯了！|offset|length|1196842|/usr/bin/truss+/usr/bin/date+2>&1+%7C+nawk+-F=+'/%5Etime/+{gsub(/+/,"",$2);printf+"0t%25d=Y\n",+$2-86400}'+%7C+adb|1196843|entityMap|0|LINK|mutability|MUTABLE|url|http://solarisjedi.blogspot.com/2006/06/solaris-date-command-and-epoch-time.html^0|0|0|0|0|4|4|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@$M|13|N|14|1|15]]|A|$]]|$1|O|3|P|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

Use Perl instead perhaps?

<pre><code>perl -e 'print scalar localtime( time - 86400 ) . "\n";'
</code></pre>

Or, use nawk and (ab)use /usr/bin/adb:

<pre><code>nawk 'BEGIN{printf "0t%d=Y\n", srand()-86400}' | adb
</code></pre>

Came across <a href="http://solarisjedi.blogspot.com/2006/06/solaris-date-command-and-epoch-time.html" rel="nofollow noreferrer">this</a> too ... insane!

<pre><code>/usr/bin/truss /usr/bin/date 2&gt;&amp;1 | nawk -F= '/^time/ {gsub(/ /,"",$2);printf "0t%d=Y\n", $2-86400}' | adb
</code></pre>

blocks|key|1197259|text|date+-d+"yesterday"+'%2B%25Y-%25m-%25d'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1197260|或|unstyled|1197261|date=$(date+-d+"yesterday"+'%2B%25Y-%25m-%25d')
echo+$date|1197262|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>date -d "yesterday" '+%Y-%m-%d'
</code></pre>

or

<pre><code>date=$(date -d "yesterday" '+%Y-%m-%d')
echo $date
</code></pre>

blocks|key|1412007|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1412008|date+--date='-1+day'|code-block|syntax|javascript|1412009|1412010|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

blocks|key|1196614|text|#!/bin/bash
OFFSET=1;
eval+`date+"%2Bday=%25d;+month=%25m;+year=%25Y"`
#+Subtract+offset+from+day,+if+it+goes+below+one+use+'cal'
#+to+determine+the+number+of+days+in+the+previous+month.
day=`expr+$day+-+$OFFSET`
if+[+$day+-le+0+]+;then
month=`expr+$month+-+1`
if+[+$month+-eq+0+]+;then
year=`expr+$year+-+1`
month=12
fi
set+`cal+$month+$year`
xday=${$#}
day=`expr+$xday+%2B+$day`
fi
echo+$year-$month-$day|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1196615|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#!/bin/bash
OFFSET=1;
eval `date "+day=%d; month=%m; year=%Y"`
# Subtract offset from day, if it goes below one use 'cal'
# to determine the number of days in the previous month.
day=`expr $day - $OFFSET`
if [ $day -le 0 ] ;then
month=`expr $month - 1`
if [ $month -eq 0 ] ;then
year=`expr $year - 1`
month=12
fi
set `cal $month $year`
xday=${$#}
day=`expr $xday + $day`
fi
echo $year-$month-$day
</code></pre>

blocks|key|1196684|text|yesterday=`date+-d+"-1+day"+%25F`|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1196685|将YYYY-MM-DD格式的昨天日期放入变量$yesterday中。|unstyled|offset|length|style|CODE|1196686|entityMap^0|0|M|A|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>yesterday=`date -d "-1 day" %F`
</code></pre>

Puts yesterday's date in YYYY-MM-DD format into variable <code>$yesterday</code>.

blocks|key|1197205|text|不是很性感，但可能会做这份工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1197206|perl+-e+'my+($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)+=+localtime(time+-+86400);$year+%2B=+1900;+$mon%2B=+1;+printf+("YESTERDAY:+%2504d%2502d%2502d+\n",+$year,+$mon,+$mday)'|code-block|syntax|javascript|1197207|是由"martin+clayton“的答案构成的。|1197208|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Not very sexy but might do the job:

<pre><code>perl -e 'my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time - 86400);$year += 1900; $mon+= 1; printf ("YESTERDAY: %04d%02d%02d \n", $year, $mon, $mday)'
</code></pre>

Formated from "martin clayton" answer.

blocks|key|1197247|text|如果选择的日期格式为‘YYYYMM’，则可以使用正则表达式进行简单的计算：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1197248|echo+$(($(date+%2B"%25Y%25m")+-+1))+%7C+sed+-e+'s/99$/12/'|code-block|syntax|javascript|1197249|在2020年1月，它将返回201912+;-)但是，这只是一种变通方法，当date没有计算选项时，其他date解释器选项(例如使用perl)不可用;-)|1197250|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could do a simple calculation, pimped with an regex, if the chosen date format is 'YYYYMM':

<pre><code>echo $(($(date +"%Y%m") - 1)) | sed -e 's/99$/12/'
</code></pre>

In January of 2020 it will return 201912 ;-)
But, it's only a workaround, when date does not have calculation options and other dateinterpreter options (e.g. using perl) not available ;-)

blocks|key|1412303|text|试试下面的代码，它也负责DST部分。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1412304|if+[+$(date+%2B%25w)+-eq+$(date+-u+%2B%25w)+];+then
++tz=$((+10#$gmthour+-+10#$localhour+))
else
++tz=$((+24+-+10#$gmthour+%2B+10#$localhour+))
fi
echo+$tz
myTime=`TZ=GMT%2B$tz+date+%2B'%25Y%25m%25d'`|code-block|syntax|javascript|1412305|Courtsey+Ansgar+Wiechers|offset|length|1412306|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/17414842/392233^0|0|0|9|F|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Try the below code , which takes care of the DST part as well.

<pre><code>if [ $(date +%w) -eq $(date -u +%w) ]; then
 tz=$(( 10#$gmthour - 10#$localhour ))
else
 tz=$(( 24 - 10#$gmthour + 10#$localhour ))
fi
echo $tz
myTime=`TZ=GMT+$tz date +'%Y%m%d'`
</code></pre>

Courtsey <a href="https://stackoverflow.com/a/17414842/392233">Ansgar Wiechers</a>

blocks|key|1197122|text|支持DST的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1197123|可以通过操作时区来更改几个小时的时钟。由于夏令时的原因，24小时前可以是今天也可以是前天。|1197124|你确定昨天已经是20或30个小时前了。哪个？好吧，最近的一个不是今天的。|1197125|echo+-e+"$(TZ=GMT%2B30+date+%2B%25Y-%25m-%25d)\n$(TZ=GMT%2B20+date+%2B%25Y-%25m-%25d)"+%7C+grep+-v+$(date+%2B%25Y-%25m-%25d)+%7C+tail+-1|code-block|syntax|javascript|1197126|回显命令中使用的-e参数是bash所必需的，但不适用于ksh。在ksh中，您可以使用不带-e标志的相同命令。|1197127|当您的脚本将在不同的环境中使用时，您可以使用#!/bin/ksh或#!/bin/bash启动脚本。您还可以将\n替换为换行符：|1197128|echo+"$(TZ=GMT%2B30+date+%2B%25Y-%25m-%25d)
$(TZ=GMT%2B20+date+%2B%25Y-%25m-%25d)"+%7C+grep+-v+$(date+%2B%25Y-%25m-%25d)+%7C+tail+-1|1197129|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|V|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|H|7|Y|8|@]|9|@]|A|$I|J]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

DST aware solution: 

Manipulating the Timezone is possible for changing the clock some hours. Due to the daylight saving time, 24 hours ago can be today or the day before yesterday. 

You are sure that yesterday is 20 or 30 hours ago. Which one? Well, the most recent one that is not today. 

<pre><code>echo -e "$(TZ=GMT+30 date +%Y-%m-%d)\n$(TZ=GMT+20 date +%Y-%m-%d)" | grep -v $(date +%Y-%m-%d) | tail -1
</code></pre>

The -e parameter used in the echo command is needed with bash, but will not work with ksh. In ksh you can use the same command without the -e flag. 

When your script will be used in different environments, you can start the script with #!/bin/ksh or #!/bin/bash. You could also replace the \n by a newline: 

<pre><code>echo "$(TZ=GMT+30 date +%Y-%m-%d)
$(TZ=GMT+20 date +%Y-%m-%d)" | grep -v $(date +%Y-%m-%d) | tail -1
</code></pre>

blocks|key|1196745|text|date+%2B%25Y:%25m:%25d%7Cawk+-vFS=":"+-vOFS=":"+'{$3=$3-1;print}'
2009:11:9|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1196746|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>date +%Y:%m:%d|awk -vFS=":" -vOFS=":" '{$3=$3-1;print}'
2009:11:9
</code></pre>

How can I print the date which is a day before current time in Bash?

Get the date (a day before current time) in Bash

如何在Bash中打印比当前时间早一天的日期？

问在Bash中获取日期(当前时间前一天)
EN

回答 16

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问在Bash中获取日期(当前时间前一天)
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