问如何从React Native Android模块访问Activity？

EN

import android.app.Activity;
import com.facebook.react.bridge.ReactContextBaseJavaModule;

public class AwesomeModule extends ReactContextBaseJavaModule {

  public AwesomeModule(ReactApplicationContext reactContext) {
    super(reactContext);
  }

  @Override
  public String getName() {
    return "AwesomeAndroid";
  }

  private static final String ERROR_NO_ACTIVITY = "E_NO_ACTIVITY";
  private static final String ERROR_NO_ACTIVITY_MESSAGE = "Tried to do the something while not attached to an Activity";

  @ReactMethod
  public void doSomething(successCallback, errorCallback) {

    final Activity activity = getCurrentActivity();

    if (activity == null) {
      errorCallback(ERROR_NO_ACTIVITY, ERROR_NO_ACTIVITY_MESSAGE);
      return;
    }

  }

}

private static Activity mCurrentActivity = null;

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    mCurrentActivity = this;
    ...
}
...
public static Activity getActivity(){
    Activity activity = new Activity();
    activity = mCurrentActivity;
    return activity;
}

import android.view.WindowManager;
import android.view.Window;
import android.view.View;

private static ReactApplicationContext reactContext;
MyModule(ReactApplicationContext context) {
  super(context);
  reactContext = context;
}

@ReactMethod
public void doSomethingRequiringWindow() {
  // get access to current UI thread first
  reactContext.getCurrentActivity().runOnUiThread(new Runnable() {
    @Override
    public void run() {
      Window window = reactContext
       .getCurrentActivity().getWindow();
      View decorView = reactContext
       .getCurrentActivity().getWindow().getDecorView();
      // you have access to main ui thread so you can effect
      // immediate behavior on window and decorView
    }
  });
}