blocks|key|931898|text|只需使用getContentResolver().openInputStream(uri)从URI获取InputStream即可。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|931899|http://developer.android.com/reference/android/content/ContentResolver.html#openInputStream(android.net.Uri)|931900|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.android.com/reference/android/content/ContentResolver.html#openInputStream%2528android.net.Uri%2529^0|4|15|1F|B|0|0|30|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@]|D|@$9|V|A|W|1|X]]|E|$]]|$1|H|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

Just use <code>getContentResolver().openInputStream(uri)</code> to get an <code>InputStream</code> from a URI.

<a href="http://developer.android.com/reference/android/content/ContentResolver.html#openInputStream%28android.net.Uri%29" rel="noreferrer">http://developer.android.com/reference/android/content/ContentResolver.html#openInputStream(android.net.Uri)</a>

blocks|key|931957|text|试图通过调用ContentResolver.query()来处理包含content://方案的URI不是一个好的解决方案。在HTC+Desire运行4.2.2时，您可能会得到NULL作为查询结果。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|931958|为什么不使用ContentResolver呢？https://stackoverflow.com/a/29141800/3205334|931959|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/29141800/3205334^0|6|N|0|N|18|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

Trying to handle the URI with content:// scheme by calling <code>ContentResolver.query()</code>is not a good solution. On HTC Desire running 4.2.2 you could get NULL as a query result.

Why not to use ContentResolver instead?
<a href="https://stackoverflow.com/a/29141800/3205334">https://stackoverflow.com/a/29141800/3205334</a>

blocks|key|931999|text|好吧，我回答有点晚了，但是我的代码已经测试过了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|932000|来自uri的检查方案：|932001|+byte[]+videoBytes;

if+(uri.getScheme().equals("content")){
++++++++InputStream+iStream+=+++context.getContentResolver().openInputStream(uri);
++++++++++++videoBytes+=+getBytes(iStream);
++++++++}else{
++++++++++++File+file+=+new+File(uri.getPath());
++++++++++++FileInputStream+fileInputStream+=+new+FileInputStream(file);+++++
++++++++++++videoBytes+=+getBytes(fileInputStream);
++++++++}|code-block|syntax|javascript|932002|在上面的回答中，我将视频uri转换为字节数组，但这与问题无关，我只是复制了我的完整代码来显示FileInputStream和InputStream的用法，因为它们在我的代码中工作相同。|offset|length|style|CODE|932003|我在片段中使用了变量context，它是getActivity()，而在Activity中，它只是ActivityName.this|932004|片段中的context=getActivity();+//|932005|context=ActivityName.this;//在活动中|932006|entityMap^0|0|0|0|1A|F|1Q|B|0|0|4|M|0|0|Q|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Z|8|@$K|10|L|11|M|N]|$K|12|L|13|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@$K|16|L|17|M|N]]|9|@]|A|$]]|$1|S|3|T|5|6|7|18|8|@$K|19|L|1A|M|N]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|V|$]]

Well I am bit late to answer,but my code is tested 

check scheme from uri:

<pre><code> byte[] videoBytes;

if (uri.getScheme().equals("content")){
 InputStream iStream = context.getContentResolver().openInputStream(uri);
 videoBytes = getBytes(iStream);
 }else{
 File file = new File(uri.getPath());
 FileInputStream fileInputStream = new FileInputStream(file); 
 videoBytes = getBytes(fileInputStream);
 }
</code></pre>

In the above answer I converted the video uri to bytes array , but that's not related to question, 
I just copied my full code to show the usage of <code>FileInputStream</code> and <code>InputStream</code> as both are working same in my code.

I used the variable context which is getActivity() in my Fragment and in Activity it simply be ActivityName.this

<code>context=getActivity();</code> //in Fragment

<code>context=ActivityName.this;</code>// in activity

blocks|key|932040|text|试试这个..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|932041|从内容uri获取文件|932042|fun+fileFromContentUri(context:+Context,+contentUri:+Uri):+File+{
++++//+Preparing+Temp+file+name
++++val+fileExtension+=+getFileExtension(context,+contentUri)
++++val+fileName+=+"temp_file"+%2B+if+(fileExtension+!=+null)+".$fileExtension"+else+""

++++//+Creating+Temp+file
++++val+tempFile+=+File(context.cacheDir,+fileName)
++++tempFile.createNewFile()

++++try+{
++++++++val+oStream+=+FileOutputStream(tempFile)
++++++++val+inputStream+=+context.contentResolver.openInputStream(contentUri)

++++++++inputStream?.let+{
++++++++++++copy(inputStream,+oStream)
++++++++}

++++++++oStream.flush()
++++}+catch+(e:+Exception)+{
++++++++e.printStackTrace()
++++}

++++return+tempFile
}

private+fun+getFileExtension(context:+Context,+uri:+Uri):+String?+{
++++val+fileType:+String?+=+context.contentResolver.getType(uri)
++++return+MimeTypeMap.getSingleton().getExtensionFromMimeType(fileType)
}

@Throws(IOException::class)
private+fun+copy(source:+InputStream,+target:+OutputStream)+{
++++val+buf+=+ByteArray(8192)
++++var+length:+Int
++++while+(source.read(buf).also+{+length+=+it+}+>+0)+{
++++++++target.write(buf,+0,+length)
++++}
}|code-block|syntax|javascript|932043|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try this....
get File from a content uri
<pre><code>fun fileFromContentUri(context: Context, contentUri: Uri): File {
 // Preparing Temp file name
 val fileExtension = getFileExtension(context, contentUri)
 val fileName = &quot;temp_file&quot; + if (fileExtension != null) &quot;.$fileExtension&quot; else &quot;&quot;

 // Creating Temp file
 val tempFile = File(context.cacheDir, fileName)
 tempFile.createNewFile()

 try {
 val oStream = FileOutputStream(tempFile)
 val inputStream = context.contentResolver.openInputStream(contentUri)

 inputStream?.let {
 copy(inputStream, oStream)
 }

 oStream.flush()
 } catch (e: Exception) {
 e.printStackTrace()
 }

 return tempFile
}

private fun getFileExtension(context: Context, uri: Uri): String? {
 val fileType: String? = context.contentResolver.getType(uri)
 return MimeTypeMap.getSingleton().getExtensionFromMimeType(fileType)
}

@Throws(IOException::class)
private fun copy(source: InputStream, target: OutputStream) {
 val buf = ByteArray(8192)
 var length: Int
 while (source.read(buf).also { length = it } &gt; 0) {
 target.write(buf, 0, length)
 }
}
</code></pre>

blocks|key|932093|text|你可以通过简单的方法通过uri来获取文件名。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|932094|Retrieving+file+information|offset|length|932095|fun+get_filename_by_uri(uri+:+Uri)+:+String{
++++contentResolver.query(uri,+null,+null,+null,+null).use+{+cursor+->
++++++++cursor?.let+{
++++++++++++val+nameIndex+=+it.getColumnIndex(OpenableColumns.DISPLAY_NAME)
++++++++++++it.moveToFirst()
++++++++++++return+it.getString(nameIndex)
++++++++}
++++}
++++return+""
}|code-block|syntax|javascript|932096|并且易于阅读，使用|932097|contentResolver.openInputStream(uri)|932098|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.android.com/training/secure-file-sharing/retrieve-info^0|0|0|R|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

you can get filename by uri with simple way
<a href="https://developer.android.com/training/secure-file-sharing/retrieve-info" rel="nofollow noreferrer">Retrieving file information</a>
<pre><code>fun get_filename_by_uri(uri : Uri) : String{
 contentResolver.query(uri, null, null, null, null).use { cursor -&gt;
 cursor?.let {
 val nameIndex = it.getColumnIndex(OpenableColumns.DISPLAY_NAME)
 it.moveToFirst()
 return it.getString(nameIndex)
 }
 }
 return &quot;&quot;
}
</code></pre>
and easy to read it by using
<pre><code>contentResolver.openInputStream(uri)
</code></pre>

blocks|key|716096|text|你可以在新的android和旧版本的uri中使用这个函数来获取文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|716097|fun+getFileFromUri(uri:+Uri):+File?+{
++++if+(uri.path+==+null)+{
++++++++return+null
++++}
++++var+realPath+=+String()
++++val+databaseUri:+Uri
++++val+selection:+String?
++++val+selectionArgs:+Array<String>?
++++if+(uri.path!!.contains("/document/image:"))+{
++++++++databaseUri+=+MediaStore.Images.Media.EXTERNAL_CONTENT_URI
++++++++selection+=+"_id=?"
++++++++selectionArgs+=+arrayOf(DocumentsContract.getDocumentId(uri).split(":")[1])
++++}+else+{
++++++++databaseUri+=+uri
++++++++selection+=+null
++++++++selectionArgs+=+null
++++}
++++try+{
++++++++val+column+=+"_data"
++++++++val+projection+=+arrayOf(column)
++++++++val+cursor+=+context.contentResolver.query(
++++++++++++databaseUri,
++++++++++++projection,
++++++++++++selection,
++++++++++++selectionArgs,
++++++++++++null
++++++++)
++++++++cursor?.let+{
++++++++++++if+(it.moveToFirst())+{
++++++++++++++++val+columnIndex+=+cursor.getColumnIndexOrThrow(column)
++++++++++++++++realPath+=+cursor.getString(columnIndex)
++++++++++++}
++++++++++++cursor.close()
++++++++}
++++}+catch+(e:+Exception)+{
++++++++Log.i("GetFileUri+Exception:",+e.message+?:+"")
++++}
++++val+path+=+if+(realPath.isNotEmpty())+realPath+else+{
++++++++when+{
++++++++++++uri.path!!.contains("/document/raw:")+->+uri.path!!.replace(
++++++++++++++++"/document/raw:",
++++++++++++++++""
++++++++++++)
++++++++++++uri.path!!.contains("/document/primary:")+->+uri.path!!.replace(
++++++++++++++++"/document/primary:",
++++++++++++++++"/storage/emulated/0/"
++++++++++++)
++++++++++++else+->+return+null
++++++++}
++++}
++++return+File(path)
}|code-block|syntax|javascript|716098|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can use this funtion for get file from uri in new android and older
<pre><code>fun getFileFromUri(uri: Uri): File? {
 if (uri.path == null) {
 return null
 }
 var realPath = String()
 val databaseUri: Uri
 val selection: String?
 val selectionArgs: Array&lt;String&gt;?
 if (uri.path!!.contains(&quot;/document/image:&quot;)) {
 databaseUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI
 selection = &quot;_id=?&quot;
 selectionArgs = arrayOf(DocumentsContract.getDocumentId(uri).split(&quot;:&quot;)[1])
 } else {
 databaseUri = uri
 selection = null
 selectionArgs = null
 }
 try {
 val column = &quot;_data&quot;
 val projection = arrayOf(column)
 val cursor = context.contentResolver.query(
 databaseUri,
 projection,
 selection,
 selectionArgs,
 null
 )
 cursor?.let {
 if (it.moveToFirst()) {
 val columnIndex = cursor.getColumnIndexOrThrow(column)
 realPath = cursor.getString(columnIndex)
 }
 cursor.close()
 }
 } catch (e: Exception) {
 Log.i(&quot;GetFileUri Exception:&quot;, e.message ?: &quot;&quot;)
 }
 val path = if (realPath.isNotEmpty()) realPath else {
 when {
 uri.path!!.contains(&quot;/document/raw:&quot;) -&gt; uri.path!!.replace(
 &quot;/document/raw:&quot;,
 &quot;&quot;
 )
 uri.path!!.contains(&quot;/document/primary:&quot;) -&gt; uri.path!!.replace(
 &quot;/document/primary:&quot;,
 &quot;/storage/emulated/0/&quot;
 )
 else -&gt; return null
 }
 }
 return File(path)
}
</code></pre>

In my app the user is to select an audio file which the app then handles. The problem is that in order for the app to do what I want it to do with the audio files, I need the URI to be in file format. When I use Android's native music player to browse for the audio file in the app, the URI is a content URI, which looks like this:

<pre><code>content://media/external/audio/media/710
</code></pre>

However, using the popular file manager application Astro, I get the following:

<pre><code>file:///sdcard/media/audio/ringtones/GetupGetOut.mp3
</code></pre>

The latter is much more accessible for me to work with, but of course I want the app to have functionality with the audio file the user chooses regardless of the program they use to browse their collection. So my question is, is there a way to convert the <code>content://</code> style URI into a <code>file://</code> URI? Otherwise, what would you recommend for me to solve this problem? Here is the code which calls up the chooser, for reference:

<pre><code>Intent ringIntent = new Intent();
ringIntent.setType("audio/mp3");
ringIntent.setAction(Intent.ACTION_GET_CONTENT);
ringIntent.addCategory(Intent.CATEGORY_OPENABLE);
startActivityForResult(Intent.createChooser(ringIntent, "Select Ringtone"), SELECT_RINGTONE);
</code></pre>

I do the following with the content URI:

<pre><code>m_ringerPath = m_ringtoneUri.getPath();
File file = new File(m_ringerPath);
</code></pre>

Then do some FileInputStream stuff with said file.

Android: Getting a file URI from a content URI?

Android

在我的应用程序中，用户选择一个音频文件，然后应用程序进行处理。问题是，为了让应用程序按照我想要的方式处理音频文件，我需要URI为文件格式。当我使用Android的原生音乐播放器在应用程序中浏览音频文件时，URI是一个内容URI，如下所示：content://media/external/audio/media/710但...

问Android:从内容URI获取文件URI？
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