blocks|key|281374|text|您可以使用数组文字：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|281375|array+=+[+'1',+'2',+'3'+]|code-block|syntax|javascript|281376|您还可以使用范围：|281377|array+=+('1'..'3').to_a++#+parentheses+are+required
#+or
array+=+*('1'..'3')++++++#+parentheses+not+required,+but+included+for+clarity|281378|对于以空格分隔的字符串数组，可以使用Percent+String+syntax|offset|length|281379|array+=+%25w[+1+2+3+]|281380|您还可以将一个块传递给Array.new，以确定每个条目的值：|style|CODE|281381|array+=+Array.new(3)+{+%7Ci%7C+(i%2B1).to_s+}|281382|最后，尽管它不会产生与上面其他答案相同的三个字符串数组，但还要注意，您可以在Ruby+1.8.7%2B中使用枚举器来创建数组；例如：|281383|array+=+1.step(17,3).to_a
#=>+[1,+4,+7,+10,+13,+16]|281384|entityMap|0|LINK|mutability|MUTABLE|url|https://ruby-doc.org/core-2.2.0/doc/syntax/literals_rdoc.html#label-Percent%2BStrings^0|0|0|0|0|I|L|0|0|0|B|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1A|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1C|8|@]|9|@$M|1D|N|1E|1|1F]]|A|$]]|$1|O|3|P|5|D|7|1G|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1H|8|@$M|1I|N|1J|S|T]]|9|@]|A|$]]|$1|U|3|V|5|D|7|1K|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1L|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1M|8|@]|9|@]|A|$E|F]]|$1|10|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]]]

You can use an array literal:

<pre><code>array = [ '1', '2', '3' ]
</code></pre>

You can also use a range:

<pre><code>array = ('1'..'3').to_a # parentheses are required
# or
array = *('1'..'3') # parentheses not required, but included for clarity
</code></pre>

For arrays of whitespace-delimited strings, you can use <a href="https://ruby-doc.org/core-2.2.0/doc/syntax/literals_rdoc.html#label-Percent+Strings" rel="noreferrer">Percent String syntax</a>:

<pre><code>array = %w[ 1 2 3 ]
</code></pre>

You can also pass a block to <code>Array.new</code> to determine what the value for each entry will be:

<pre><code>array = Array.new(3) { |i| (i+1).to_s }
</code></pre>

Finally, although it doesn't produce the same array of three strings as the other answers above, note also that you can use enumerators in Ruby 1.8.7+ to create arrays; for example:

<pre><code>array = 1.step(17,3).to_a
#=&gt; [1, 4, 7, 10, 13, 16]
</code></pre>

blocks|key|3205826|text|线条：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3205827|array+=+[]+<<+1+<<+2+<<+3+++#this+is+for+fixnums.|code-block|syntax|javascript|3205828|或|3205829|+a+=+%25w%7C+1+2+3+4+5+%7C|3205830|3205831|+a+=+[*'1'..'3']|3205832|3205833|+a+=+Array.new(3,+'1')|3205834|3205835|+a+=+Array[*'1'..'3']|3205836|entityMap^0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|K|3|H|5|6|7|Z|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|N|3|H|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|H|5|6|7|13|8|@]|9|@]|A|$]]|$1|R|3|S|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|T|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|U|$]]

Oneliner:

<pre><code>array = [] &lt;&lt; 1 &lt;&lt; 2 &lt;&lt; 3 #this is for fixnums.
</code></pre>

or

<pre><code> a = %w| 1 2 3 4 5 |
</code></pre>

or

<pre><code> a = [*'1'..'3']
</code></pre>

or

<pre><code> a = Array.new(3, '1')
</code></pre>

or

<pre><code> a = Array[*'1'..'3']
</code></pre>

blocks|key|279370|text|除了上面的答案，你也可以这样做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|279371|++++=>++[*'1'.."5"]+++#remember+*
++++=>+["1",+"2",+"3",+"4",+"5"]|code-block|syntax|javascript|279372|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Along with the above answers , you can do this too

<pre><code> =&gt; [*'1'.."5"] #remember *
 =&gt; ["1", "2", "3", "4", "5"]
</code></pre>

blocks|key|2992216|text|你可以做到|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2992217|array+=+['1',+'2',+'3']|code-block|syntax|javascript|2992218|正如其他人所指出的，您还可以使用%25w表示法初始化一个数组，如下所示：|2992219|array+=+%25w(1+2+3)|2992220|或|2992221|array+=+%25w[1+2+3]|2992222|请注意，在这两种情况下，每个元素都是字符串，而不是整数。因此，如果您想要一个元素为整数的数组，则不应使用撇号将每个元素括起来：|2992223|array_of_integers+=+[1,+2,+3]|2992224|此外，您不需要在元素之间加逗号(在创建没有%25w表示法的数组时，这是必需的)。如果你这样做(我经常会犯错)，就像下面这样：|2992225|wrong_array+=+%25w(1,+2,+3)|2992226|它的元素是三个字符串-+"1，"，"2，"，"3“。所以，如果你这样做了：|2992227|puts+wrong_array|2992228|输出将为：|2992229|1,
2,
3
=>nil|2992230|这不是我们想要的。|2992231|希望这有助于澄清这一点！|2992232|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1C|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1E|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1I|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1K|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1L|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1M|8|@]|9|@]|A|$]]|$1|12|3|13|5|D|7|1N|8|@]|9|@]|A|$E|F]]|$1|14|3|15|5|6|7|1O|8|@]|9|@]|A|$]]|$1|16|3|17|5|6|7|1P|8|@]|9|@]|A|$]]|$1|18|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]]|19|$]]

You can do

<pre><code>array = ['1', '2', '3']
</code></pre>

As others have noted, you can also initialize an array with %w notation like so:

<pre><code>array = %w(1 2 3)
</code></pre>

or 

<pre><code>array = %w[1 2 3]
</code></pre>

Please note that in both cases each element is a string, rather than an integer.
So if you want an array whose elements are integers, you should not wrap each element with apostrophes:

<pre><code>array_of_integers = [1, 2, 3]
</code></pre>

Also, you don't need to put comma in between the elements (which is necessary when creating an array without this %w notation). If you do this (which I often did by mistake), as in:

<pre><code>wrong_array = %w(1, 2, 3)
</code></pre>

its elements will be three strings ---- "1,", "2,", "3". So if you do:

<pre><code>puts wrong_array
</code></pre>

the output will be: 

<pre><code>1,
2,
3
=&gt;nil
</code></pre>

which is not what we want here.

Hope this helps to clarify the point!

blocks|key|282933|text|要创建这样的数组，您可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|282934|array+=+['1',+'2',+'3']|code-block|syntax|javascript|282935|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To create such an array you could do:

<pre><code>array = ['1', '2', '3']
</code></pre>

blocks|key|281369|text|如果你有一个字符串数组，你也可以像这样初始化它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|281370|array+=+%25w{1+2+3}|offset|length|style|CODE|281371|只需用空格分隔每个元素|281372|entityMap^0|0|0|H|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

If you have an Array of strings, you can also initialize it like this:

<code>array = %w{1 2 3}</code>

just separate each element with any whitespace

blocks|key|2992130|text|您可以通过在[]中编写元素来一步初始化一个数组，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2992131|array+=+['1',+'2',+'3']|code-block|syntax|javascript|2992132|entityMap^0|6|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can initialize an array in one step by writing the elements in <code>[]</code> like this:

<pre><code>array = ['1', '2', '3']
</code></pre>

blocks|key|2992184|text|您可以简单地使用ruby数组中的%25w表示法来做到这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2992185|array+=+%25w(1+2+3)|code-block|syntax|javascript|2992186|它会将数组值1,2,3添加到数组中，并将输出打印为["1",+"2",+"3"]|2992187|entityMap^0|G|2|0|0|P|F|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

You can simply do this with <code>%w</code> notation in ruby arrays.

<pre><code>array = %w(1 2 3)
</code></pre>

It will add the array values 1,2,3 to the arrayand print out the output as <code>["1", "2", "3"]</code>

I initialize an array this way:

<pre><code>array = Array.new
array &lt;&lt; '1' &lt;&lt; '2' &lt;&lt; '3'
</code></pre>

Is it possible to do that in one step? If so, how?

How to initialize an array in one step using Ruby?

我用这种方式初始化一个数组：array = Array.newarray << '1' << '2' << '3'可以一步到位吗？如果是这样，是怎么做到的？

问如何使用Ruby一步初始化一个数组？
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