我正在用spring security开发我的第一个应用程序。我的applicationContext-security.xml文件如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<!--
- Namespace-based OpenID configuration
-->
<b:beans xmlns="http://www.springframework.org/schema/security"
xmlns:b="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<http>
<intercept-url pattern="/**" access="ROLE_USER"/>
<intercept-url pattern="/index.xhtml*" filters="none"/>
<logout/>
<openid-login login-page="/index.xhtml" authentication-failure-url="/index.xhtml?login_error=true">
<attribute-exchange>
<openid-attribute name="email" type="http://schema.openid.net/contact/email" required="true" count="2"/>
<openid-attribute name="name" type="http://schema.openid.net/namePerson/friendly" />
</attribute-exchange>
</openid-login>
<remember-me token-repository-ref="tokenRepo"/>
</http>
<b:bean id="tokenRepo"
class="org.springframework.security.web.authentication.rememberme.InMemoryTokenRepositoryImpl" />
<authentication-manager alias="authenticationManager"/>
<user-service id="userService">
<user name="http://user.myopenid.com/" authorities="ROLE_SUPERVISOR,ROLE_USER" />
</user-service>
</b:beans>
Web.xml文件为:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<display-name>Spring Security OpenID Demo Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/applicationContext-security.xml
</param-value>
</context-param>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>openid.root</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>faces/index.xhtml</welcome-file>
</welcome-file-list>
</web-app>
清理和构建应用程序是成功的,但当我尝试部署应用程序时,jetty 7给出了以下错误:
严重:上下文初始化失败
Spring问题:找不到org.springframework.beans.factory.parsing.BeanDefinitionParsingException: NamespaceHandler for XML schema命名空间[http://www.springframework.org/schema/security]
违规资源: ServletContext资源/WEB-INF/applicationContext Security.xml
在org.springframework.beans.factory.parsing.FailFastProblemReporter.error(FailFastProblemReporter.java:68)
在org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:85)
在org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:80)
尝试了所有方法,但无法解决此错误。任何帮助都将不胜感激。
编辑我尝试添加了3.0.2版本的Spring-Security,得到的结果是:
上下文初始化失败
来自ServletContext资源/WEB-INF/applicationContext Security.xml的org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException:文档中的第13行无效;
嵌套异常为org.xml.sax.SAXParseException;lineNumber: 13;columnNumber: 11;cvc-complex-type.2.4.c:匹配的通配符是严格的,但找不到元素'http‘的声明。在org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:396)
在org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:334
https://stackoverflow.com/questions/7188719
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