blocks|key|273260|text|从片段中调用getActivity()，它将为您提供托管片段的活动。然后调用findViewById(ViewPagerId)获取ViewPager。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273261|ViewPager+vp=(ViewPager)+getActivity().findViewById(ViewPagerId);|code-block|syntax|javascript|273262|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

From fragment, call getActivity() which will gives you the activity in which the fragment is hosted. Then call findViewById(ViewPagerId) to get the ViewPager.

<pre><code>ViewPager vp=(ViewPager) getActivity().findViewById(ViewPagerId);
</code></pre>

blocks|key|273321|text|编辑:我必须补充，即使Eldhose+answer的工作有效，我也会为我的方法辩护。因为片段对包含它的活动了解得越少越好。通过这样做，您可以在不依赖于ID的情况下获得父视图，并且即使它不是ViewPager，也仍然可以从中获取信息。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273322|您可以在片段的onCreateView方法中获取。|offset|length|style|CODE|273323|container参数是父视图，在本例中是一个ViewPager。|273324|在Java中：|273325|++++@Override
++++public+View+onCreateView(LayoutInflater+inflater,+ViewGroup+container,
+++++++++++++++++++++++++++++Bundle+savedInstanceState)+{
++++++++
++++++++ViewPager+pager+=+(ViewPager)+container;
++++++++//....+Rest+of+your+method
++++}|code-block|syntax|javascript|273326|Kotlin版本：|273327|++++override+fun+onCreateView(inflater:+LayoutInflater,+container:+ViewGroup,+
++++savedInstanceState:+Bundle)+{

++++++++val+pager+=+container+as+ViewPager
++++++++//....+Rest+of+your+method
++++}|273328|entityMap^0|0|7|C|0|0|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@$D|11|E|12|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|13|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|14|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|N|7|16|8|@]|9|@]|A|$O|P]]|$1|U|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|V|$]]

Edit: I must add, even though Eldhose answer's works, I would defend my approach. Because the less the fragment knows about the Activity containing it, the better. By doing this, you can get the parent view without depending on IDs, and you can still get information from it even if it isn't a ViewPager.
You can get the in the Fragment's <code>onCreateView</code> method.
The <code>container</code> param is the parent View, in that case, a ViewPager.
In Java:
<pre><code> @Override
 public View onCreateView(LayoutInflater inflater, ViewGroup container,
 Bundle savedInstanceState) {
 
 ViewPager pager = (ViewPager) container;
 //.... Rest of your method
 }
</code></pre>
Kotlin Version:
<pre><code> override fun onCreateView(inflater: LayoutInflater, container: ViewGroup, 
 savedInstanceState: Bundle) {

 val pager = container as ViewPager
 //.... Rest of your method
 }
</code></pre>

blocks|key|490469|text|onCreateView、onViewCreated和onAttach方法调用得太早了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|490470|在片段的onResume方法中，该视图绝对附加到它的父视图。这是一个使用getView().getParent()的好地方|490471|entityMap^0|0|C|D|D|R|8|0|4|8|10|L|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|I|$]]

The methods <code>onCreateView</code> and <code>onViewCreated</code> and <code>onAttach</code> are called too early.

The view is definitely attached to its parent view in the fragment's <code>onResume</code> method. This is a good place to then use <code>getView().getParent()</code>

blocks|key|490530|text|另一种对我有帮助的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|490531|++++++++++++++++List<Fragment>+fragment+=+getActivity().getSupportFragmentManager().getFragments();
++++++++++++++++for+(Fragment+f:fragment)+{
++++++++++++++++++++if+(f+instanceof+CreatCheckInFragment){
++++++++++++++++++++++++((ParentFragment)+f).viewPager.arrowScroll(View.FOCUS_LEFT);
++++++++++++++++++++}
++++++++++++++++}|code-block|syntax|javascript|490532|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another way that helped me :

<pre><code> List&lt;Fragment&gt; fragment = getActivity().getSupportFragmentManager().getFragments();
 for (Fragment f:fragment) {
 if (f instanceof CreatCheckInFragment){
 ((ParentFragment) f).viewPager.arrowScroll(View.FOCUS_LEFT);
 }
 }
</code></pre>

I am trying to access the parent viewpager from inside a fragment, but i have no idea how to do that.
I need to switch the currentItem on the ViewPager after a onClick event inside the fragment.

Any ideas?

EDIT:

I want access to the parent view(ViewPager View) so that i can change the currentItem which is visible, from inside one of my fragments.

Getting Parent ViewPager View from inside Fragment

我试图从一个片段中访问父viewpager，但我不知道如何做到这一点。我需要在片段内的onClick事件之后切换ViewPager上的currentItem。有什么想法吗？编辑：我想要访问父视图(ViewPager视图)，这样我就可以从我的片段中更改可见的currentItem。

问从片段内部获取父ViewPager视图
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问从片段内部获取父ViewPager视图EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问从片段内部获取父ViewPager视图
EN