blocks|key|1270766|text|我用下面的方法编写了一个类。好好享受吧。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1270767|public+static+function+getQuarterByMonth($monthNumber)+{
++return+floor(($monthNumber+-+1)+/+3)+%2B+1;
}

public+static+function+getQuarterDay($monthNumber,+$dayNumber,+$yearNumber)+{
++$quarterDayNumber+=+0;
++$dayCountByMonth+=+array();

++$startMonthNumber+=+((self::getQuarterByMonth($monthNumber)+-+1)+*+3)+%2B+1;

++//+Calculate+the+number+of+days+in+each+month.
++for+($i=1;+$i<=12;+$i%2B%2B)+{
++++$dayCountByMonth[$i]+=+date("t",+strtotime($yearNumber+.+"-"+.+$i+.+"-01"));
++}

++for+($i=$startMonthNumber;+$i<=$monthNumber-1;+$i%2B%2B)+{
++++$quarterDayNumber+%2B=+$dayCountByMonth[$i];
++}

++$quarterDayNumber+%2B=+$dayNumber;

++return+$quarterDayNumber;
}

public+static+function+getCurrentQuarterDay()+{
++return+self::getQuarterDay(date('n'),+date('j'),+date('Y'));
}|code-block|syntax|javascript|1270768|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I wrote a class with the following methods. Enjoy.

<pre><code>public static function getQuarterByMonth($monthNumber) {
 return floor(($monthNumber - 1) / 3) + 1;
}

public static function getQuarterDay($monthNumber, $dayNumber, $yearNumber) {
 $quarterDayNumber = 0;
 $dayCountByMonth = array();

 $startMonthNumber = ((self::getQuarterByMonth($monthNumber) - 1) * 3) + 1;

 // Calculate the number of days in each month.
 for ($i=1; $i&lt;=12; $i++) {
 $dayCountByMonth[$i] = date("t", strtotime($yearNumber . "-" . $i . "-01"));
 }

 for ($i=$startMonthNumber; $i&lt;=$monthNumber-1; $i++) {
 $quarterDayNumber += $dayCountByMonth[$i];
 }

 $quarterDayNumber += $dayNumber;

 return $quarterDayNumber;
}

public static function getCurrentQuarterDay() {
 return self::getQuarterDay(date('n'), date('j'), date('Y'));
}
</code></pre>

blocks|key|1485393|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1485394|$curMonth+=+date("m",+time());
$curQuarter+=+ceil($curMonth/3);|code-block|syntax|javascript|1485395|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about:

<pre><code>$curMonth = date("m", time());
$curQuarter = ceil($curMonth/3);
</code></pre>

blocks|key|1270796|text|function+date_quarter()
{
++++return+ceil(date('n',+time())+/+3);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1270797|或|unstyled|1270798|function+date_quarter()
{
++++$month+=+date('n');

++++if+($month+<=+3)+return+1;
++++if+($month+<=+6)+return+2;
++++if+($month+<=+9)+return+3;

++++return+4;
}|1270799|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>function date_quarter()
{
 return ceil(date('n', time()) / 3);
}
</code></pre>

or

<pre><code>function date_quarter()
{
 $month = date('n');

 if ($month &lt;= 3) return 1;
 if ($month &lt;= 6) return 2;
 if ($month &lt;= 9) return 3;

 return 4;
}
</code></pre>

blocks|key|1485429|text|你可以使用Carbon，它有简单的getFirstOf{月，年，季度}修饰符()|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1485430|<?php
//take+current+date
$now+=+Carbon\Carbon::now();

//modify+a+copy+of+it+to+the+first+day+of+the+current+quarter
$firstOfQuarter+=+$now->copy()->firstOfQuarter();

//calculate+the+difference+in+days+and+add+1+to+correct+the+index
$dayOfQuarter+=+$now->diffInDays($firstOfQuarter)+%2B+1;|code-block|syntax|javascript|1485431|entityMap|0|LINK|mutability|MUTABLE|url|http://carbon.nesbot.com/^0|5|6|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can use <a href="http://carbon.nesbot.com/" rel="nofollow noreferrer">Carbon</a> it has easy modifiers for getFirstOf{Month,Year,Quarter}()

<pre><code>&lt;?php
//take current date
$now = Carbon\Carbon::now();

//modify a copy of it to the first day of the current quarter
$firstOfQuarter = $now-&gt;copy()-&gt;firstOfQuarter();

//calculate the difference in days and add 1 to correct the index
$dayOfQuarter = $now-&gt;diffInDays($firstOfQuarter) + 1;
</code></pre>

blocks|key|1485367|text|假设您指的是日历季度(因为公司会计年度可以在一年中的任何月份开始)，您可以依靠日期(‘z’)来确定一年中的哪一天，然后保存每个季度开始的日期的简单数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1485368|$quarterStartDays+=+array(+1+/*+Jan+1+*/,+90+/*+Mar+1,+non+leap-year+*/,+...+);|code-block|syntax|javascript|1485369|然后，使用当前日期，您可以首先找到小于或等于一年中日期的最大起始日期，然后减去。|1485370|请注意，根据闰年的不同，您需要不同的数字。|1485371|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Assuming you mean a calendar-quarter (because a company fiscal year can start in any month of the year), you could rely on the date('z') to determine the day-of-year, and then keep a simple array of the day each quarter starts on:

<pre><code>$quarterStartDays = array( 1 /* Jan 1 */, 90 /* Mar 1, non leap-year */, ... );
</code></pre>

Then with the current day-of-year you can first locate the largest start-day that's less than or equal to the day-of-year, then subtract.

Note that you need different numbers depending on the leap year.

blocks|key|1485384|text|<?php
function+day_of_quarter($ts=null)+{
++++if(+is_null($ts)+)+$ts=time();
++++$d=date('d',+$ts);
++++$m=date('m',+$ts)-1;
++++while($m%253!=0)+{
++++++++$lastmonth=mktime(0,+0,+0,+$m,+date("d",+$ts),+++date("Y",$ts));
++++++++$d+%2B=+date('t',+$lastmonth);
++++++++$m--;
++++}
++++return+$d;
}
echo+day_of_quarter(mktime(0,+0,+0,+1,+1,2009));
echo+"\n";
echo+day_of_quarter(time());
echo+"\n";
?>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1485385|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&lt;?php
function day_of_quarter($ts=null) {
 if( is_null($ts) ) $ts=time();
 $d=date('d', $ts);
 $m=date('m', $ts)-1;
 while($m%3!=0) {
 $lastmonth=mktime(0, 0, 0, $m, date("d", $ts), date("Y",$ts));
 $d += date('t', $lastmonth);
 $m--;
 }
 return $d;
}
echo day_of_quarter(mktime(0, 0, 0, 1, 1,2009));
echo "\n";
echo day_of_quarter(time());
echo "\n";
?&gt;
</code></pre>

blocks|key|1485433|text|<?php

function+quarter_day($time+=+"")+{

++++$time+=+$time+?+strtotime($time)+:+time();
++++$date+=+intval(date("j",+$time));
++++$month+=+intval(date("n",+$time));
++++$year+=+intval(date("Y",+$time));

++++//+get+selected+quarter+as+number+between+1+and+4
++++$quarter+=+ceil($month+/+3);

++++//+get+first+month+of+current+quarter+as+number+between+1+and+12
++++$fmonth+=+$quarter+%2B+(($quarter+-+1)+*+2);

++++//+map+days+in+a+year+by+month
++++$map+=+[31,28,31,30,31,30,31,31,30,31,30,31];

++++//+check+if+year+is+leap
++++if+(((($year+%25+4)+==+0)+&&+((($year+%25+100)+!=+0)+%7C%7C+(($year+%25+400)+==+0))))+$map[1]+=+29;

++++//+get+total+number+of+days+in+selected+quarter,+by+summing+the+relative+portion+of+$map+array
++++$total+=+array_sum(array_slice($map,+($fmonth+-+1),+3));

++++//+get+number+of+days+passed+in+selected+quarter,+by+summing+the+relative+portion+of+$map+array
++++$map[$month-1]+=+$date;
++++$day+=+array_sum(array_slice($map,+($fmonth+-+1),+($month+-+$fmonth+%2B+1)));

++++return+"Day+$day+on+$total+of+quarter+$quarter,+$year.";

}

print(quarter_day("2017-01-01"))+.+"\n";+//+prints+Day+1+on+90+of+quarter+1,+2017.
print(quarter_day("2017-04-01"))+.+"\n";+//+prints+Day+1+on+91+of+quarter+2,+2017.
print(quarter_day("2017-08-15"))+.+"\n";+//+prints+Day+46+on+92+of+quarter+3,+2017.
print(quarter_day("2017-12-31"))+.+"\n";+//+prints+Day+92+on+92+of+quarter+4,+2017.|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1485434|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&lt;?php

function quarter_day($time = "") {

 $time = $time ? strtotime($time) : time();
 $date = intval(date("j", $time));
 $month = intval(date("n", $time));
 $year = intval(date("Y", $time));

 // get selected quarter as number between 1 and 4
 $quarter = ceil($month / 3);

 // get first month of current quarter as number between 1 and 12
 $fmonth = $quarter + (($quarter - 1) * 2);

 // map days in a year by month
 $map = [31,28,31,30,31,30,31,31,30,31,30,31];

 // check if year is leap
 if (((($year % 4) == 0) &amp;&amp; ((($year % 100) != 0) || (($year % 400) == 0)))) $map[1] = 29;

 // get total number of days in selected quarter, by summing the relative portion of $map array
 $total = array_sum(array_slice($map, ($fmonth - 1), 3));

 // get number of days passed in selected quarter, by summing the relative portion of $map array
 $map[$month-1] = $date;
 $day = array_sum(array_slice($map, ($fmonth - 1), ($month - $fmonth + 1)));

 return "Day $day on $total of quarter $quarter, $year.";

}

print(quarter_day("2017-01-01")) . "\n"; // prints Day 1 on 90 of quarter 1, 2017.
print(quarter_day("2017-04-01")) . "\n"; // prints Day 1 on 91 of quarter 2, 2017.
print(quarter_day("2017-08-15")) . "\n"; // prints Day 46 on 92 of quarter 3, 2017.
print(quarter_day("2017-12-31")) . "\n"; // prints Day 92 on 92 of quarter 4, 2017.
</code></pre>

blocks|key|1485486|text|我们需要先计算一下第一季度的日期|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1485487|$current_month+=+date('m');

//+Get+first+month+of+quarter
$new_month+=+(3+*+floor(($current_month+-+1+)+/+3))+%2B+1;

//+Add+prefix+zero+if+needed
$new_month+=+substr('0'+.+$new_month,+-2);

$first_quarter_day_date+=+date('Y')+.+'-'+.+$new_month+.+'-01';|code-block|syntax|javascript|1485488|接下来，我们计算http://php.net/manual/en/datetime.diff.php|offset|length|1485489|$datetime1+=+new+DateTime($first_quarter_day_date);
$datetime2+=+new+DateTime();

$interval+=+$datetime1->diff($datetime2);
echo+$interval->format('%25a+days');|1485490|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/datetime.diff.php^0|0|0|8|16|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

We need to calculate the date of the first quarter first

<pre><code>$current_month = date('m');

// Get first month of quarter
$new_month = (3 * floor(($current_month - 1 ) / 3)) + 1;

// Add prefix zero if needed
$new_month = substr('0' . $new_month, -2);

$first_quarter_day_date = date('Y') . '-' . $new_month . '-01';
</code></pre>

next we calculate the <a href="http://php.net/manual/en/datetime.diff.php" rel="nofollow noreferrer">http://php.net/manual/en/datetime.diff.php</a>

<pre><code>$datetime1 = new DateTime($first_quarter_day_date);
$datetime2 = new DateTime();

$interval = $datetime1-&gt;diff($datetime2);
echo $interval-&gt;format('%a days');
</code></pre>

blocks|key|1270970|text|我注意到这个帖子有点超出了问题的范围，这是对许多谷歌搜索的第一个响应，其中包含"Quarter“和"PHP”。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1270971|如果你正在使用ISO组织标准，如果你正在做一个商业应用程序，那么|1270972|$curMonth+=+date("m",+time());
$curQuarter+=+ceil($curMonth/3);|code-block|syntax|javascript|1270973|是不正确的，因为在ISO标准中，一年的第一天可以是30，或12月31日。|1270974|相反，您应该使用以下代码：|1270975|++$current_yearly_cycle_year_number+=+2019;
++$current_yearly_cycle_start->setISODate(+$current_yearly_cycle_year_number,+1,+1+);
++$current_yearly_cycle_end->setISODate(+$current_yearly_cycle_year_number,+53,+1+);

++if(+$current_yearly_cycle_end->format("W")+!==+"53"+)
++++$current_yearly_cycle_end->setISODate(+$current_yearly_cycle_year_number,+52,+1+);

++$week_number_start+=+intval(+$current_yearly_cycle_start->format(+"W"+)+);
++$timestamp_start_quarter+=+(+$week_number_start+===+1+?+1+:+intval(+ceil(+$current_yearly_cycle_start->format(+"m"+)+/+3+)+)+);

++var_dump(+$timestamp_start_quarter+);|1270976|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|V|8|@]|9|@]|A|$G|H]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I've noticed that this thread went a bit beyond the question, and it's the first response to many google searches with "Quarter" &amp; "PHP" in them.

If you're working with the ISO standards of organization, which you should if you're doing a business app, then 

<pre><code>$curMonth = date("m", time());
$curQuarter = ceil($curMonth/3);
</code></pre>

Is NOT correct, because the first day of a year in the ISO standards, can be 30, or 31 December.

Instead, you should use this :

<pre><code> $current_yearly_cycle_year_number = 2019;
 $current_yearly_cycle_start-&gt;setISODate( $current_yearly_cycle_year_number, 1, 1 );
 $current_yearly_cycle_end-&gt;setISODate( $current_yearly_cycle_year_number, 53, 1 );

 if( $current_yearly_cycle_end-&gt;format("W") !== "53" )
 $current_yearly_cycle_end-&gt;setISODate( $current_yearly_cycle_year_number, 52, 1 );

 $week_number_start = intval( $current_yearly_cycle_start-&gt;format( "W" ) );
 $timestamp_start_quarter = ( $week_number_start === 1 ? 1 : intval( ceil( $current_yearly_cycle_start-&gt;format( "m" ) / 3 ) ) );

 var_dump( $timestamp_start_quarter );
</code></pre>

PHP provides ways to get the number of the current day of the month (date('j')) as well as the number of the current day of the year (date('z')). Is there a way to get the number of the current day of the current quarter?

So right now, August 5, it is day 36 of the third quarter.

If there is no standard way of calculating this, does anyone have a (prefereably PHP-based) algorithm handy?

Easy way to get day number of current quarter?

PHP提供了获取当月当前日期(date('j'))和一年中当前日期(date('z'))的方法。有没有办法获取本季度当天的数字？现在，8月5日，是第三季度的36天。如果没有标准的计算方法，有没有现成的(最好是基于PHP的)算法？

问获取当前季度天数的简单方法？
EN

回答 9

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问获取当前季度天数的简单方法？
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