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社区首页 >问答首页 >发送SOAP请求和接收响应的客户端

发送SOAP请求和接收响应的客户端
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Stack Overflow用户
提问于 2011-01-25 17:32:23
回答 6查看 667.6K关注 0票数 173

尝试创建一个C#客户端(将作为Windows服务开发),将SOAP请求发送到web服务(并获取结果)。

通过这个question,我看到了下面的代码:

代码语言:javascript
复制
protected virtual WebRequest CreateRequest(ISoapMessage soapMessage)
{
    var wr = WebRequest.Create(soapMessage.Uri);
    wr.ContentType = "text/xml;charset=utf-8";
    wr.ContentLength = soapMessage.ContentXml.Length;

    wr.Headers.Add("SOAPAction", soapMessage.SoapAction);
    wr.Credentials = soapMessage.Credentials;
    wr.Method = "POST";
    wr.GetRequestStream().Write(Encoding.UTF8.GetBytes(soapMessage.ContentXml), 0, soapMessage.ContentXml.Length);

    return wr;
}

public interface ISoapMessage
{
    string Uri { get; }
    string ContentXml { get; }
    string SoapAction { get; }
    ICredentials Credentials { get; }
}

看起来不错,有人知道如何使用它吗?这是不是最好的做法?

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回答 6

Stack Overflow用户

回答已采纳

发布于 2011-01-25 17:45:47

我通常用另一种方法来做同样的事情。

代码语言:javascript
复制
using System.Xml;
using System.Net;
using System.IO;

public static void CallWebService()
{
    var _url = "http://xxxxxxxxx/Service1.asmx";
    var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";

    XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
    HttpWebRequest webRequest = CreateWebRequest(_url, _action);
    InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);

    // begin async call to web request.
    IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);

    // suspend this thread until call is complete. You might want to
    // do something usefull here like update your UI.
    asyncResult.AsyncWaitHandle.WaitOne();

    // get the response from the completed web request.
    string soapResult;
    using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
    {
        using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
        {
            soapResult = rd.ReadToEnd();
        }
        Console.Write(soapResult);        
    }
}

private static HttpWebRequest CreateWebRequest(string url, string action)
{
    HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
    webRequest.Headers.Add("SOAPAction", action);
    webRequest.ContentType = "text/xml;charset=\"utf-8\"";
    webRequest.Accept = "text/xml";
    webRequest.Method = "POST";
    return webRequest;
}

private static XmlDocument CreateSoapEnvelope()
{
    XmlDocument soapEnvelopeDocument = new XmlDocument();
    soapEnvelopeDocument.LoadXml(
    @"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/"" 
               xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance"" 
               xmlns:xsd=""http://www.w3.org/1999/XMLSchema"">
        <SOAP-ENV:Body>
            <HelloWorld xmlns=""http://tempuri.org/"" 
                SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/"">
                <int1 xsi:type=""xsd:integer"">12</int1>
                <int2 xsi:type=""xsd:integer"">32</int2>
            </HelloWorld>
        </SOAP-ENV:Body>
    </SOAP-ENV:Envelope>");
    return soapEnvelopeDocument;
}

private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
    using (Stream stream = webRequest.GetRequestStream())
    {
        soapEnvelopeXml.Save(stream);
    }
}
票数 245
EN

Stack Overflow用户

发布于 2017-05-26 20:17:49

我认为有一种更简单的方法:

代码语言:javascript
复制
 public async Task<string> CreateSoapEnvelope()
 {
      string soapString = @"<?xml version=""1.0"" encoding=""utf-8""?>
          <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
              <soap:Body>
                  <HelloWorld xmlns=""http://tempuri.org/"" />
              </soap:Body>
          </soap:Envelope>";

          HttpResponseMessage response = await PostXmlRequest("your_url_here", soapString);
          string content = await response.Content.ReadAsStringAsync();

      return content;
 }

 public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
 {
      using (var httpClient = new HttpClient())
      {
          var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
          httpContent.Headers.Add("SOAPAction", "http://tempuri.org/HelloWorld");

          return await httpClient.PostAsync(baseUrl, httpContent);
       }
 }
票数 26
EN

Stack Overflow用户

发布于 2012-10-01 22:21:56

最佳实践是引用WSDL并将其用作web服务引用。它更简单,效果也更好,但是如果您没有WSDL,XSD定义就是一段很好的代码。

票数 19
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/4791794

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