blocks|key|1098167|text|只需添加一些引号来转义通配符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098168|unzip+"*.zip"|code-block|syntax|javascript|1098169|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just put in some quotes to escape the wildcard:

<pre><code>unzip "*.zip"
</code></pre>

blocks|key|1313115|text|解压缩*.zip，或者如果它们在子文件夹中，则类似于|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1313116|find+.+-name+"*.zip"+-exec+unzip+{}+\;|code-block|syntax|javascript|1313117|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

unzip *.zip, or if they are in subfolders, then something like 

<pre><code>find . -name "*.zip" -exec unzip {} \;
</code></pre>

blocks|key|1313288|text|for+i+in+*.zip;+do
++newdir="${i:0:-4}"+&&+mkdir+"$newdir"
++unzip+"$i"+-d++"$newdir"
done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1313289|这会将所有zip归档文件解压到以zip归档文件名命名的新文件夹中。|unstyled|1313290|a.zip+b.zip+c.zip将分别解压缩到a+b+c文件夹中。|offset|length|style|CODE|1313291|entityMap^0|0|0|0|5|6|5|C|5|O|1|Q|1|S|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]|$I|Z|J|10|K|L]|$I|11|J|12|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|F|7|13|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>for i in *.zip; do
 newdir="${i:0:-4}" &amp;&amp; mkdir "$newdir"
 unzip "$i" -d "$newdir"
done
</code></pre>

This will unzip all the zip archives into new folders named with the filenames of the zip archives.

<code>a.zip</code> <code>b.zip</code> <code>c.zip</code> will be unzipped into <code>a</code> <code>b</code> <code>c</code> folders respectively.

blocks|key|1098344|text|在任何POSIX+shell中，这将解压到每个zip文件的不同目录中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098345|for+file+in+*.zip
do
++++directory="${file%25.zip}"
++++unzip+"$file"+-d+"$directory"
done|code-block|syntax|javascript|1098346|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In any POSIX shell, this will unzip into a different directory for each zip file:

<pre><code>for file in *.zip
do
 directory="${file%.zip}"
 unzip "$file" -d "$directory"
done
</code></pre>

blocks|key|1313224|text|安装了atool的aunpack+-e+*.zip。它的优点是智能地处理错误，并且总是解压到子目录中，除非zip只包含一个文件。因此，不存在用大量文件污染当前目录的危险，就像在没有目录结构的压缩包上使用unzip一样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1313225|entityMap^0|3|5|9|G|2T|5|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

<code>aunpack -e *.zip</code>, with <code>atool</code> installed.
Has the advantage that it deals intelligently with errors, and always unpacks into subdirectories unless the zip contains only one file . Thus, there is no danger of polluting the current directory with masses of files, as there is with <code>unzip</code> on a zip with no directory structure.

blocks|key|1098257|text|使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098258|for+file+in+`ls+*.Zip`;+do
unzip+${file}+-d+${unzip_dir_loc}
done|code-block|syntax|javascript|1098259|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use this:

<pre><code>for file in `ls *.Zip`; do
unzip ${file} -d ${unzip_dir_loc}
done
</code></pre>

blocks|key|1313303|text|for+file+in+'ls+*.zip';+do+unzip+"${file}"+-d+"${file:0:-4}";+done|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1313304|entityMap^0|0|1U|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>for file in 'ls *.zip'; do unzip "${file}" -d "${file:0:-4}"; done</code>

blocks|key|1098365|text|如果文件是gzip'd。然后只需使用：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1098366|gunzip+-rfk+.|code-block|syntax|javascript|1098367|从根目录中通过保留原始文件来递归地提取各个目录中的文件(或移除-k以删除它们)|1098368|entityMap^0|5|6|0|0|V|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

If the files are <code>gzip'd</code>. Then just use:

<pre><code>gunzip -rfk .
</code></pre>

from the root directory to recursively extract files in respective directories by keeping the original ones (or remove <code>-k</code> to delete them)

blocks|key|1098328|text|这是使用How+to+loop+through+a+directory+recursively+to+delete+files+with+certain+extensions教学的Pedro+Lobito+answer的变体：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1098329|shopt+-s+globstar
root_directory="."

for+zip_file_name+in+**/*.{zip,sublime\-package};+do
++++directory_name=`echo+$zip_file_name+%7C+sed+'s/\.$zip\%7Csublime\-package$$//'`
++++printf+"Unpacking+zip+file+\`$root_directory/$zip_file_name\`...\n"

++++if+[+-f+"$root_directory/$zip_file_name"+];+then
++++++++mkdir+-p+"$root_directory/$directory_name"
++++++++unzip+-o+-q+"$root_directory/$zip_file_name"+-d+"$directory_name"

++++++++#+Some+files+have+the+executable+flag+and+were+not+being+deleted+because+of+it.
++++++++#+chmod+-x+"$root_directory/$zip_file_name"
++++++++#+rm+-f+"$root_directory/$zip_file_name"
++++fi
done|code-block|syntax|javascript|1098330|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/4638874/how-to-loop-through-a-directory-recursively-to-delete-files-with-certain-extensi|1|https://stackoverflow.com/users/797495|2|https://stackoverflow.com/a/29248777/4934640^0|4|2B|0|2I|C|1|2V|6|2|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]|$A|Y|B|Z|1|10]|$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]|S|$5|L|M|N|C|$O|T]]]]

This is a variant of <a href="https://stackoverflow.com/users/797495">Pedro Lobito</a> <a href="https://stackoverflow.com/a/29248777/4934640">answer</a> using <a href="https://stackoverflow.com/questions/4638874/how-to-loop-through-a-directory-recursively-to-delete-files-with-certain-extensi">How to loop through a directory recursively to delete files with certain extensions</a> teachings:

<pre><code>shopt -s globstar
root_directory="."

for zip_file_name in **/*.{zip,sublime\-package}; do
 directory_name=`echo $zip_file_name | sed 's/\.$zip\|sublime\-package$$//'`
 printf "Unpacking zip file \`$root_directory/$zip_file_name\`...\n"

 if [ -f "$root_directory/$zip_file_name" ]; then
 mkdir -p "$root_directory/$directory_name"
 unzip -o -q "$root_directory/$zip_file_name" -d "$directory_name"

 # Some files have the executable flag and were not being deleted because of it.
 # chmod -x "$root_directory/$zip_file_name"
 # rm -f "$root_directory/$zip_file_name"
 fi
done
</code></pre>

blocks|key|1313255|text|使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1313256|sudo+apt-get+install+unzip+

unzip+file.zip+-d+path_to_destination_folder|code-block|syntax|javascript|1313257|在linux中解压文件夹|1313258|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use

<pre><code>sudo apt-get install unzip 

unzip file.zip -d path_to_destination_folder
</code></pre>

to unzip a folder in linux

blocks|key|1313081|text|for+i+in+`ls+*.zip`;+do+unzip+$i;+done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1313082|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for i in `ls *.zip`; do unzip $i; done
</code></pre>

blocks|key|1098337|text|要解压缩某个目录中的所有文件，只需在终端中键入以下cmd：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098338|unzip+'*.zip'|code-block|syntax|javascript|1098339|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To unzip all files in a directory just type this cmd in terminal:

<pre><code>unzip '*.zip'
</code></pre>

I have a directory of ZIP files (created on a Windows machine). I can manually unzip them using <code>unzip filename</code>, but how can I unzip all the ZIP files in the current folder via the shell?

Using Ubuntu Linux Server.

Unzip All Files In A Directory

服务器

Windows

Ubuntu

Linux

我有一个ZIP文件的目录(在Windows机器上创建)。我可以使用unzip filename手动解压它们，但是如何通过shell解压当前文件夹中的所有ZIP文件？使用Ubuntu Linux服务器。

问解压缩目录中的所有文件
EN

回答 12

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问解压缩目录中的所有文件EN

回答 12

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问解压缩目录中的所有文件
EN