blocks|key|450082|text|也许这能行得通？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|450083|grep+A1+file+%7C+tail+-1+%7C+awk+'{print+$NF}'|code-block|syntax|javascript|450084|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

maybe this works?

<pre><code>grep A1 file | tail -1 | awk '{print $NF}'
</code></pre>

blocks|key|450123|text|您可以在没有awk的情况下使用一些管道来完成此操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|450124|tac+file+%7C+grep+-m1+A1+%7C+rev+%7C+cut+-d'+'+-f1+%7C+rev|code-block|syntax|javascript|450125|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do this without awk with just some pipes.

<pre><code>tac file | grep -m1 A1 | rev | cut -d' ' -f1 | rev
</code></pre>

blocks|key|232181|text|使用awk的一种方式|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|232182|tail+-f+file.txt+%7C+awk+'/A1/+{+print+$NF+}'|code-block|syntax|javascript|232183|entityMap^0|2|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

One way using <code>awk</code>:

<pre><code>tail -f file.txt | awk '/A1/ { print $NF }'
</code></pre>

blocks|key|450163|text|您可以在awk中完成所有这些工作|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|450164|<file+awk+'$1+~+/A1/+{m=$NF}+END+{print+m}'|code-block|syntax|javascript|450165|entityMap^0|4|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can do all of it in <code>awk</code>:

<pre><code>&lt;file awk '$1 ~ /A1/ {m=$NF} END {print m}'
</code></pre>

blocks|key|450194|text|对文件执行以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|450195|awk+'ORS=NR%253?"+":"\n"'+filename|code-block|syntax|javascript|450196|你就会得到你想要的。|450197|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Execute this on the file:

<pre><code>awk 'ORS=NR%3?" ":"\n"' filename
</code></pre>

and you'll get what you're looking for.

blocks|key|232242|text|ls+-l+%7C+awk+'{print+$9}'+%7C+tail+-n1|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|232243|entityMap^0|0|Z|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>ls -l | awk '{print $9}' | tail -n1</code>

blocks|key|232266|text|要打印一行的最后一列，只需使用$(NF)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|232267|awk+'{print+$(NF)}'+|code-block|syntax|javascript|232268|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To print the last column of a line just use $(NF): 

<pre><code>awk '{print $(NF)}' 
</code></pre>

blocks|key|450238|text|使用Perl|type|unstyled|depth|inlineStyleRanges|entityRanges|data|450239|$+cat+rayne.txt
A1+123+456
B1+234+567
C1+345+678
A1+098+766
B1+987+6545
C1+876+5434


$+perl+-lane+'+/A1/+and+$x=$F[2]+;+END+{+print+"$x"+}+'+rayne.txt
766

$|code-block|syntax|javascript|450240|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using Perl

<pre><code>$ cat rayne.txt
A1 123 456
B1 234 567
C1 345 678
A1 098 766
B1 987 6545
C1 876 5434


$ perl -lane ' /A1/ and $x=$F[2] ; END { print "$x" } ' rayne.txt
766

$
</code></pre>

blocks|key|450247|text|这里不是真正的问题，但可能会对某些人有所帮助:我正在做awk+"{print+$NF}"，注意错误的引号。应该为awk+'{print+$NF}'，这样外壳程序就不会展开$NF。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|450248|entityMap^0|R|H|1K|H|2D|3|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

Not the actual issue here, but might help some one: I was doing <code>awk "{print $NF}"</code>, note the wrong quotes. Should be <code>awk '{print $NF}'</code>, so that the shell doesn't expand <code>$NF</code>.

I have a file that is constantly being written to/updated. I want to find the last line containing a particular word, then print the last column of that line.

The file looks something like this. More A1/B1/C1 lines will be appended to it over time.

<pre><code>A1 123 456
B1 234 567
C1 345 678
A1 098 766
B1 987 6545
C1 876 5434
</code></pre>

I tried to use

<pre><code>tail -f file | grep A1 | awk '{print $NF}'
</code></pre>

to print the value 766, but nothing is output.

Is there a way to do this?

Printing the last column of a line in a file

Perl

我有一个不断写入/更新的文件。我想找到包含特定单词的最后一行，然后打印该行的最后一列。这个文件看起来像这样。随着时间的推移，将向其追加更多的A1/B1/C1行。A1 123 456B1 234 567C1 345 678A1 098 766B1 987 6545C1 876 5434我试着用tail -f file |...

问打印文件中一行的最后一列
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