blocks|key|641412|text|(date2.year+*+12+%2B+date2.month)+-+(date1.year+*+12+%2B+date1.month)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|641413|欲了解更多信息，请访问http://www.ruby-forum.com/topic/72120|unstyled|offset|length|641414|entityMap|0|LINK|mutability|MUTABLE|url|http://www.ruby-forum.com/topic/72120^0|0|B|11|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>(date2.year * 12 + date2.month) - (date1.year * 12 + date1.month)
</code></pre>

more info at <a href="http://www.ruby-forum.com/topic/72120" rel="noreferrer">http://www.ruby-forum.com/topic/72120</a>

blocks|key|641469|text|一个更准确的答案是考虑距离的日子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|641470|例如，如果您认为28/4/2000和1/5/2000之间的月份距离是0而不是1，则可以使用：|offset|length|style|CODE|641471|(date2.year+-+date1.year)+*+12+%2B+date2.month+-+date1.month+-+(date2.day+>=+date1.day+?+0+:+1)|code-block|syntax|javascript|641472|entityMap^0|0|8|9|I|8|Y|1|12|1|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]|$D|S|E|T|F|G]|$D|U|E|V|F|G]|$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|N|$]]

A more accurate answer would consider days in the distance. 

For example, if you consider that the month-distance from <code>28/4/2000</code> and <code>1/5/2000</code> is <code>0</code> rather than <code>1</code>, then you can use:

<pre><code>(date2.year - date1.year) * 12 + date2.month - date1.month - (date2.day &gt;= date1.day ? 0 : 1)
</code></pre>

blocks|key|427050|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|427051|((date2.to_time+-+date1.to_time)/1.month.second).to_i|code-block|syntax|javascript|427052|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Give a try to

<pre><code>((date2.to_time - date1.to_time)/1.month.second).to_i
</code></pre>

blocks|key|427298|text|假设两者都是日期：((date2+-+date1).to_f+/+365+*+12).round+simple。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|427299|entityMap^0|9|13|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Assuming both are dates:
<code>((date2 - date1).to_f / 365 * 12).round</code>
simple.

blocks|key|641609|text|您可以将问题重新表述为“日期的月份开始之间有多少第1天”，然后使用函数式数据转换：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|641610|(date1.beginning_of_month...date2.beginning_of_month).select+{+%7Cdate%7C+date.day+==+1+}.size|code-block|syntax|javascript|641611|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can rephrase the question as "how many 1st days is there between the beginnings of months of the dates", and then use functional-style data transformations:

<pre><code>(date1.beginning_of_month...date2.beginning_of_month).select { |date| date.day == 1 }.size
</code></pre>

blocks|key|427171|text|start_date+=+Date.today
end_date+++=+Date.today%2B90
months+=+(end_date.month%2Bend_date.year*12)+-+(start_date.month%2Bstart_date.year*12)

//months+=+3|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|427172|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>start_date = Date.today
end_date = Date.today+90
months = (end_date.month+end_date.year*12) - (start_date.month+start_date.year*12)

//months = 3
</code></pre>

blocks|key|427249|text|我需要两个日期之间的确切月数(包括小数)，并为此编写了以下方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|427250|def+months_difference(period_start,+period_end)
++period_end+=+period_end+%2B+1.day
++months+=+(period_end.year+-+period_start.year)+*+12+%2B+period_end.month+-+period_start.month+-+(period_end.day+>=+period_start.day+?+0+:+1)
++remains+=+period_end+-+(period_start+%2B+months.month)

++(months+%2B+remains/period_end.end_of_month.day).to_f.round(2)
end|code-block|syntax|javascript|427251|如果将9月26日与9月26日(同一天)进行比较，我会将其计算为1天。如果不需要，可以删除方法中的第一行：period_end+=+period_end+%2B+1.day|offset|length|style|CODE|427252|它通过了以下规范：|427253|expect(months_difference(Date.new(2017,+8,+1),+Date.new(2017,+8,+31))).to+eq+1.0
expect(months_difference(Date.new(2017,+8,+1),+Date.new(2017,+8,+30))).to+eq+0.97
expect(months_difference(Date.new(2017,+8,+1),+Date.new(2017,+10,+31))).to+eq+3.0
#+Overlapping+february+(28+days)+still+counts+Feb+as+a+full+month
expect(months_difference(Date.new(2017,+1,+1),+Date.new(2017,+3,+31))).to+eq+3.0
expect(months_difference(Date.new(2017,+2,+10),+Date.new(2017,+3,+9))).to+eq+1.0
#+Leap+year
expect(months_difference(Date.new(2016,+2,+1),+Date.new(2016,+2,+29))).to+eq+1.0|427254|entityMap^0|0|0|1G|V|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I needed the exact number of months (including decimals) between two dates and wrote the following method for it.

<pre><code>def months_difference(period_start, period_end)
 period_end = period_end + 1.day
 months = (period_end.year - period_start.year) * 12 + period_end.month - period_start.month - (period_end.day &gt;= period_start.day ? 0 : 1)
 remains = period_end - (period_start + months.month)

 (months + remains/period_end.end_of_month.day).to_f.round(2)
end
</code></pre>

If comparing let's say September 26th to September 26th (same day) I calculate it as 1 day. If you don't need that you can remove the first line in the method: <code>period_end = period_end + 1.day</code>

It passes the following specs:

<pre><code>expect(months_difference(Date.new(2017, 8, 1), Date.new(2017, 8, 31))).to eq 1.0
expect(months_difference(Date.new(2017, 8, 1), Date.new(2017, 8, 30))).to eq 0.97
expect(months_difference(Date.new(2017, 8, 1), Date.new(2017, 10, 31))).to eq 3.0
# Overlapping february (28 days) still counts Feb as a full month
expect(months_difference(Date.new(2017, 1, 1), Date.new(2017, 3, 31))).to eq 3.0
expect(months_difference(Date.new(2017, 2, 10), Date.new(2017, 3, 9))).to eq 1.0
# Leap year
expect(months_difference(Date.new(2016, 2, 1), Date.new(2016, 2, 29))).to eq 1.0
</code></pre>

blocks|key|641577|text|我找到的另一个解决方案(已经在这里发布了一个解决方案)是用于如果您希望结果包含一个月的分数。例如，距离为1.2+months。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|641578|((date2.to_time+-+date1.to_time)/1.month.second).round(1)+#Tenth+of+a+month+Ex:+1.2
((date2.to_time+-+date1.to_time)/1.month.second).round(2)+#Hundreth,+ex:+1.23+months
etc...|code-block|syntax|javascript|641579|entityMap^0|1G|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Another solution that I found (built off a solution posted here already) is for if you want the result to include fractions of a month. For example the distance is <code>1.2 months</code>.

<pre><code>((date2.to_time - date1.to_time)/1.month.second).round(1) #Tenth of a month Ex: 1.2
((date2.to_time - date1.to_time)/1.month.second).round(2) #Hundreth, ex: 1.23 months
etc...
</code></pre>

blocks|key|641649|text|def+difference_in_months(date1,+date2)
++month_count+=+(date2.year+==+date1.year)+?+(date2.month+-+date1.month)+:+(12+-+date1.month+%2B+date2.month)
++month_count+=+(date2.year+==+date1.year)+?+(month_count+%2B+1)+:+(((date2.year+-+date1.year+-+1+)+*+12)+%2B+(month_count+%2B+1))
++month_count
end|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|641650|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def difference_in_months(date1, date2)
 month_count = (date2.year == date1.year) ? (date2.month - date1.month) : (12 - date1.month + date2.month)
 month_count = (date2.year == date1.year) ? (month_count + 1) : (((date2.year - date1.year - 1 ) * 12) + (month_count + 1))
 month_count
end
</code></pre>

blocks|key|427332|text|这是一个蛮力强迫的变种：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|427333|date1+=+'2016-01-05'.to_date
date2+=+'2017-02-27'.to_date
months+=+0

months+%2B=+1+while+(date2+<<+(count%2B1))+>=+date1
puts+months+#+=>+13|code-block|syntax|javascript|427334|date2必须始终大于date1|offset|length|style|CODE|427335|entityMap^0|0|0|0|5|B|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Here's a brute forcing variant:

<pre><code>date1 = '2016-01-05'.to_date
date2 = '2017-02-27'.to_date
months = 0

months += 1 while (date2 &lt;&lt; (count+1)) &gt;= date1
puts months # =&gt; 13
</code></pre>

<code>date2</code> must be always greater than <code>date1</code>

blocks|key|641797|text|这是另一种方法。这将有助于计算两个日期之间的整月数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|641798|def+months_difference(date_time_start,+date_time_end)
++curr_months+=+0
++while+(date_time_start+%2B+curr_months.months)+<+date_time_end
++++curr_months+%2B=+1
++end
++curr_months+-=+1+if+(date_time_start+%2B+curr_months.months)+>+date_time_end
++curr_months.negative?+?+0+:+curr_months
end|code-block|syntax|javascript|641799|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is another method. This will help to calculate number of whole months between two dates

<pre><code>def months_difference(date_time_start, date_time_end)
 curr_months = 0
 while (date_time_start + curr_months.months) &lt; date_time_end
 curr_months += 1
 end
 curr_months -= 1 if (date_time_start + curr_months.months) &gt; date_time_end
 curr_months.negative? ? 0 : curr_months
end
</code></pre>

blocks|key|641821|text|任何情况下的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|641822|(date1..date2).map+{+%7Cdate%7C+date.strftime('%25m.%25Y')+}.uniq.size|code-block|syntax|javascript|641823|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Solution for any cases
<pre><code>(date1..date2).map { |date| date.strftime('%m.%Y') }.uniq.size
</code></pre>

blocks|key|641843|text|这个怎么样？我发现它很干净|type|unstyled|depth|inlineStyleRanges|entityRanges|data|641844|((date2+-+date1)+/+1.month).round|code-block|syntax|javascript|641845|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about this? I've found it pretty clean
<pre><code>((date2 - date1) / 1.month).round
</code></pre>

I have two Ruby on Rails DateTime objects. How to find the number of months between them? (Keeping in mind they might belong to different years)

Find number of months between two Dates in Ruby on Rails

数据转换

我有两个Ruby on Rails DateTime对象。如何找出它们之间的月数？(请记住，它们可能属于不同的年份)

问在Ruby on Rails中查找两个日期之间的月数
EN

回答 13

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问在Ruby on Rails中查找两个日期之间的月数EN

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问在Ruby on Rails中查找两个日期之间的月数
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