blocks|key|1690374|text|通常，当我处理剥离\r或\n时，我会通过执行以下操作来查找这两种情况|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1690375|lines.gsub(/\r\n?/,+"\n");|code-block|syntax|javascript|1690376|我发现，根据数据的保存方式(使用的操作系统、使用的编辑器、当时Jupiter与Io的关系)，回车后可能会有换行符，也可能没有。在十六进制模式下同时看到两个字符看起来确实很奇怪。希望这能有所帮助。|1690377|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Generally when I deal with stripping \r or \n, I'll look for both by doing something like

<pre><code>lines.gsub(/\r\n?/, "\n");
</code></pre>

I've found that depending on how the data was saved (the OS used, editor used, Jupiter's relation to Io at the time) there may or may not be the newline after the carriage return. It does seem weird that you see both characters in hex mode. Hope this helps.

blocks|key|1690507|text|如果您使用的是Rails，则有一个squish方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1690508|"\tgoodbye\r\n".squish+=>+"goodbye"|1690509|"\tgood++++\t\r\nbye\r\n".squish+=>+"good+bye"|1690510|entityMap^0|H|6|0|0|Z|0|0|1A|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|K|$]]

If you are using Rails, there is a <code>squish</code> method

<code>"\tgoodbye\r\n".squish =&gt; "goodbye"</code>

<code>"\tgood \t\r\nbye\r\n".squish =&gt; "good bye"</code>

blocks|key|1690461|text|modified_string+=+string.gsub(/\s%2B/,+'+').strip|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1690462|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>modified_string = string.gsub(/\s+/, ' ').strip
</code></pre>

blocks|key|1690251|text|lines2+=+lines.split.join("\n")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1690252|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>lines2 = lines.split.join("\n")
</code></pre>

blocks|key|1475308|text|"still+the+same\n".chomp|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1475309|或|1475310|"still+the+same\n".chomp!|1475311|http://www.ruby-doc.org/core-1.9.3/String.html#method-i-chomp|1475312|entityMap|0|LINK|mutability|MUTABLE|url^0|0|O|0|0|0|P|0|0|1P|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|Z|8|@]|D|@$9|10|A|11|1|12]]|E|$]]|$1|L|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|M|$N|$5|O|P|Q|E|$R|K]]]]

<code>"still the same\n".chomp</code> 
or 
<code>"still the same\n".chomp!</code>

<a href="http://www.ruby-doc.org/core-1.9.3/String.html#method-i-chomp">http://www.ruby-doc.org/core-1.9.3/String.html#method-i-chomp</a>

blocks|key|1475218|text|下面的内容如何？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1475219|irb(main):003:0>+my_string+=+"Some+text+with+a+carriage+return+\r"
=>+"Some+text+with+a+carriage+return+\r"
irb(main):004:0>+my_string.gsub(/\r/,"")
=>+"Some+text+with+a+carriage+return+"
irb(main):005:0>|code-block|syntax|javascript|1475220|或者..。|1475221|irb(main):007:0>+my_string+=+"Some+text+with+a+carriage+return+\r\n"
=>+"Some+text+with+a+carriage+return+\r\n"
irb(main):008:0>+my_string.gsub(/\r\n/,"\n")
=>+"Some+text+with+a+carriage+return+\n"
irb(main):009:0>|1475222|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

How about the following?

<pre><code>irb(main):003:0&gt; my_string = "Some text with a carriage return \r"
=&gt; "Some text with a carriage return \r"
irb(main):004:0&gt; my_string.gsub(/\r/,"")
=&gt; "Some text with a carriage return "
irb(main):005:0&gt;
</code></pre>

Or...

<pre><code>irb(main):007:0&gt; my_string = "Some text with a carriage return \r\n"
=&gt; "Some text with a carriage return \r\n"
irb(main):008:0&gt; my_string.gsub(/\r\n/,"\n")
=&gt; "Some text with a carriage return \n"
irb(main):009:0&gt;
</code></pre>

blocks|key|1690618|text|我认为你的正则表达式已经差不多完成了--这就是我要做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1690619|lines2+=+lines.gsub(/[\r\n]%2B/m,+"\n")|code-block|syntax|javascript|1690620|在上面的代码中，我将\r和\n放入一个类中(这样，它们出现的顺序就不重要了)，并添加了"%2B“限定符(这样"\r\n\r\n\r\n”也会匹配一次，整个过程都替换为"\n")|1690621|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I think your regex is almost complete - here's what I would do:

<pre><code>lines2 = lines.gsub(/[\r\n]+/m, "\n")
</code></pre>

In the above, I've put \r and \n into a class (that way it doesn't matter in which order they might appear) and added the "+" qualifier (so that "\r\n\r\n\r\n" would also match once, and the whole thing replaced with "\n")

blocks|key|1475519|text|这只是另一个变体：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1475520|lines.delete("+\n")|code-block|syntax|javascript|1475521|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just another variant:

<pre><code>lines.delete(" \n")
</code></pre>

blocks|key|1690430|text|为什么不在文本模式下读取文件，而不是二进制模式？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1690431|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Why not read the file in text mode, rather than binary mode?

blocks|key|1475407|text|lines.map(&:strip).join("+")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1475408|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>lines.map(&amp;:strip).join(" ")
</code></pre>

blocks|key|1475339|text|您可以使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1475340|my_string.strip.gsub(/\s%2B/,+'+')|code-block|syntax|javascript|1475341|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this :

<pre><code>my_string.strip.gsub(/\s+/, ' ')
</code></pre>

blocks|key|1475523|text|def+dos2unix(input)
++input.each_byte.map+{+%7Cc%7C+c.chr+unless+c+==+13+}.join
end

remove_all_the_carriage_returns+=+dos2unix(some_blob)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1475524|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def dos2unix(input)
 input.each_byte.map { |c| c.chr unless c == 13 }.join
end

remove_all_the_carriage_returns = dos2unix(some_blob)
</code></pre>

I thought this code would work, but the regular expression doesn't ever match the \r\n. I have viewed the data I am reading in a hex editor and verified there really is a hex D and hex A pattern in the file.

I have also tried the regular expressions /\xD\xA/m and /\x0D\x0A/m but they also didn't match.

This is my code right now:

<pre><code> lines2 = lines.gsub( /\r\n/m, "\n" )
 if ( lines == lines2 )
 print "still the same\n"
 else
 print "made the change\n"
 end
</code></pre>

In addition to alternatives, it would be nice to know what I'm doing wrong (to facilitate some learning on my part). :)

How do I remove carriage returns with Ruby?

我认为这段代码可以工作，但正则表达式永远不会匹配\r\n。我在十六进制编辑器中查看了正在读取的数据，并验证了文件中是否真的存在十六进制D和十六进制A模式。我还尝试了正则表达式/\xD\xA/m和/\x0D\x0A/m，但它们也不匹配。这是我现在的代码：   lines2 = lines.gsub( /\r\n/m, "\n" )   if ( lines == lines2 )       pri

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