以编程方式请求对联系人的访问?

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需要以编程方式启动“访问联系人请求”对话框?怎么做到的?

提问于
用户回答回答于

可以尝试下:

  #import <AddressBookUI/AddressBookUI.h>

  // Request authorization to Address Book
  ABAddressBookRef addressBookRef = ABAddressBookCreateWithOptions(NULL, NULL);

  if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusNotDetermined) {
    ABAddressBookRequestAccessWithCompletion(addressBookRef, ^(bool granted, CFErrorRef error) {
      if (granted) {
          // First time access has been granted, add the contact
          [self _addContactToAddressBook];
      } else {
          // User denied access
          // Display an alert telling user the contact could not be added
      }
    });
  }
  else if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusAuthorized) {
    // The user has previously given access, add the contact
    [self _addContactToAddressBook];
  }
  else {
    // The user has previously denied access
    // Send an alert telling user to change privacy setting in settings app
  }

用户回答回答于

在iOS 5或之前,我们总是可以打电话给

ABAddressBookRef addressBook = ABAddressBookCreate();

这就是为什么我们需要更改方法以获得ABAddressBookRef。

__block BOOL accessGranted = NO;
if (ABAddressBookRequestAccessWithCompletion != NULL) { // we're on iOS 6
    dispatch_semaphore_t sema = dispatch_semaphore_create(0);
    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
        accessGranted = granted;
        dispatch_semaphore_signal(sema);
    });
    dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
    dispatch_release(sema);   
}
else { // we're on iOS 5 or older
    accessGranted = YES;
}

if (accessGranted) {
    // Do whatever you want here.
}

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