Android Java UTF-8 HttpClient问题
Android Java UTF-8 HttpClient问题
提问于 2010-12-19 05:50:49
我有一个从网页抓取的JSON数组的奇怪的字符编码问题。服务器将发回此标头：
Content-Type text/javascript；charset=UTF-8
此外，我还可以在Firefox或任何浏览器中查看JSON输出，并且Unicode字符显示正确。响应有时会包含来自另一种语言的带有重音符号等的单词。然而，当我在Java中把它拉下并放到一个字符串中时，我得到了那些奇怪的问号。下面是我的代码：
HttpParams params = new BasicHttpParams();
HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
HttpProtocolParams.setContentCharset(params, "utf-8");
params.setBooleanParameter("http.protocol.expect-continue", false);
HttpClient httpclient = new DefaultHttpClient(params);
HttpGet httpget = new HttpGet("http://www.example.com/json_array.php");
HttpResponse response;
try {
response = httpclient.execute(httpget);
if(response.getStatusLine().getStatusCode() == 200){
// Connection was established. Get the content.
HttpEntity entity = response.getEntity();
// If the response does not enclose an entity, there is no need
// to worry about connection release
if (entity != null) {
// A Simple JSON Response Read
InputStream instream = entity.getContent();
String jsonText = convertStreamToString(instream);
Toast.makeText(getApplicationContext(), "Response: "+jsonText, Toast.LENGTH_LONG).show();
}
}
} catch (MalformedURLException e) {
Toast.makeText(getApplicationContext(), "ERROR: Malformed URL - "+e.getMessage(), Toast.LENGTH_LONG).show();
e.printStackTrace();
} catch (IOException e) {
Toast.makeText(getApplicationContext(), "ERROR: IO Exception - "+e.getMessage(), Toast.LENGTH_LONG).show();
e.printStackTrace();
} catch (JSONException e) {
Toast.makeText(getApplicationContext(), "ERROR: JSON - "+e.getMessage(), Toast.LENGTH_LONG).show();
e.printStackTrace();
}
private static String convertStreamToString(InputStream is) {
/*
* To convert the InputStream to String we use the BufferedReader.readLine()
* method. We iterate until the BufferedReader return null which means
* there's no more data to read. Each line will appended to a StringBuilder
* and returned as String.
*/
BufferedReader reader;
try {
reader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
StringBuilder sb = new StringBuilder();
String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}正如您所看到的，我在InputStreamReader上指定了UTF-8，但是每次我通过Toast查看返回的JSON文本时，它都有奇怪的问号。我在想，我需要将InputStream发送到byte[]吗？
提前感谢您的帮助。
回答 4
Stack Overflow用户
回答已采纳
发布于 2010-12-19 06:32:28
试试这个：
if (entity != null) {
// A Simple JSON Response Read
// InputStream instream = entity.getContent();
// String jsonText = convertStreamToString(instream);
String jsonText = EntityUtils.toString(entity, HTTP.UTF_8);
// ... toast code here
}Stack Overflow用户
发布于 2014-07-29 01:11:38
这只是因为您的convertStreamToString没有遵守HttpRespnose中设置的编码。如果查看EntityUtils.toString(entity, HTTP.UTF_8)内部，您将看到EntityUtils首先确定HttpResponse中是否设置了编码，如果有，则EntityUtils使用该编码。只有在实体中没有设置编码时，它才会回退到参数中传递的编码(在本例中是HTTP.UTF_8)。
因此，您可以说您的HTTP.UTF_8是在参数中传递的，但它永远不会被使用，因为它是错误的编码。下面是使用EntityUtils中的帮助器方法更新您的代码。
HttpEntity entity = response.getEntity();
String charset = getContentCharSet(entity);
InputStream instream = entity.getContent();
String jsonText = convertStreamToString(instream,charset);
private static String getContentCharSet(final HttpEntity entity) throws ParseException {
if (entity == null) {
throw new IllegalArgumentException("HTTP entity may not be null");
}
String charset = null;
if (entity.getContentType() != null) {
HeaderElement values[] = entity.getContentType().getElements();
if (values.length > 0) {
NameValuePair param = values[0].getParameterByName("charset");
if (param != null) {
charset = param.getValue();
}
}
}
return TextUtils.isEmpty(charset) ? HTTP.UTF_8 : charset;
}
private static String convertStreamToString(InputStream is, String encoding) {
/*
* To convert the InputStream to String we use the
* BufferedReader.readLine() method. We iterate until the BufferedReader
* return null which means there's no more data to read. Each line will
* appended to a StringBuilder and returned as String.
*/
BufferedReader reader;
try {
reader = new BufferedReader(new InputStreamReader(is, encoding));
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
StringBuilder sb = new StringBuilder();
String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}Stack Overflow用户
发布于 2015-12-02 01:53:14
阿基米德的答案是正确的。但是，只需在HTTP请求中提供额外的标头即可：
Accept-charset: utf-8不需要删除任何东西或使用任何其他库。
例如,
GET / HTTP/1.1
Host: www.website.com
Connection: close
Accept: text/html
Upgrade-Insecure-Requests: 1
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.10 Safari/537.36
DNT: 1
Accept-Encoding: gzip, deflate, sdch
Accept-Language: en-US,en;q=0.8
Accept-Charset: utf-8您的请求很可能没有任何Accept-Charset头。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/4480363
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