blocks|key|1229260|text|首先，我强烈建议您使用has_many+:through而不是habtm+(有关此here的更多信息)，这样您最终会得到类似于：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1229261|Employment+belongs_to+:users
Employment+belongs_to+:companies

User+has_many+:employments
User+has_many+:companies,+:through+=>+:employments+

Company+has_many+:employments
Company+has_many+:users,+:through+=> :employments|code-block|syntax|javascript|1229262|在此之后，您将在两端都有has_many关联，并可以在factory_girl中以您所做的方式为它们赋值。|1229263|entityMap|0|LINK|mutability|MUTABLE|url|http://blog.hasmanythrough.com/2006/4/20/many-to-many-dance-off^0|15|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

First of all I strongly encourage you to use has_many :through instead of habtm (more about this <a href="http://blog.hasmanythrough.com/2006/4/20/many-to-many-dance-off" rel="nofollow noreferrer">here</a>), so you'll end up with something like:

<pre><code>Employment belongs_to :users
Employment belongs_to :companies

User has_many :employments
User has_many :companies, :through =&gt; :employments 

Company has_many :employments
Company has_many :users, :through =&gt; :employments
</code></pre>

After this you'll have has_many association on both sides and can assign to them in factory_girl in the way you did it.

blocks|key|1229296|text|Factorygirl已经更新了，现在包括了解决这个问题的回调。有关更多信息，请查看http://robots.thoughtbot.com/post/254496652/aint-no-calla-back-girl。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1229297|entityMap|0|LINK|mutability|MUTABLE|url|http://robots.thoughtbot.com/post/254496652/aint-no-calla-back-girl^0|16|1V|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Factorygirl has since been updated and now includes callbacks to solve this problem. Take a look at <a href="http://robots.thoughtbot.com/post/254496652/aint-no-calla-back-girl" rel="noreferrer">http://robots.thoughtbot.com/post/254496652/aint-no-calla-back-girl</a> for more info.

blocks|key|1229354|text|对我来说起作用的是在使用工厂时设置关联。使用您的示例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1229355|user+=+Factory(:user)
company+=+Factory(:company)

company.users+<<+user+
company.save!+|code-block|syntax|javascript|1229356|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

What worked for me was setting the association when using the factory. 
Using your example:

<pre><code>user = Factory(:user)
company = Factory(:company)

company.users &lt;&lt; user 
company.save! 
</code></pre>

blocks|key|1229391|text|我在提供的网站上找不到上述情况的示例。(只有1:N和多态关联，但没有habtm)。我有一个类似的例子，我的代码看起来像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1229392|Factory.define+:user+do+%7Cuser%7C
+user.name+"Foo+Bar"
+user.after_create+{+%7Cu%7C+Factory(:company,+:users+=>+[u])+}
end

Factory.define+:company+do+%7Cc%7C
+c.name+"Acme"
end|code-block|syntax|javascript|1229393|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I couldn´t find an example for the above mentioned case on the provided website. (Only 1:N and polymorphic assocations, but no habtm). I had a similar case and my code looks like this:

<pre><code>Factory.define :user do |user|
 user.name "Foo Bar"
 user.after_create { |u| Factory(:company, :users =&gt; [u]) }
end

Factory.define :company do |c|
 c.name "Acme"
end
</code></pre>

blocks|key|1444359|text|以下是对我有效的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1444360|FactoryGirl.define+do

++factory+:company+do
++++#company+attributes
++end

++factory+:user+do
+++companies+{[FactoryGirl.create(:company)]}
+++#user+attributes
++end

end|code-block|syntax|javascript|1444361|如果你需要特定的公司，你可以这样使用工厂|1444362|company+=+FactoryGirl.create(:company,+#{company+attributes})
user+=+FactoryGirl.create(:user,+:companies+=>+[company])|1444363|希望这能对某些人有所帮助。|1444364|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Here is the solution that works for me.

<pre><code>FactoryGirl.define do

 factory :company do
 #company attributes
 end

 factory :user do
 companies {[FactoryGirl.create(:company)]}
 #user attributes
 end

end
</code></pre>

if you will need specific company you can use factory this way

<pre><code>company = FactoryGirl.create(:company, #{company attributes})
user = FactoryGirl.create(:user, :companies =&gt; [company])
</code></pre>

Hope this will be helpful for somebody.

blocks|key|1444400|text|我发现这种方式很好，也很冗长：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1444401|FactoryGirl.define+do
++factory+:foo+do
++++name+"Foo"+
++end

++factory+:bar+do
++++name+"Bar"
++++foos+{+%7Ca%7C+[a.association(:foo)]+}
++end
end|code-block|syntax|javascript|1444402|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Found this way nice and verbose:

<pre><code>FactoryGirl.define do
 factory :foo do
 name "Foo" 
 end

 factory :bar do
 name "Bar"
 foos { |a| [a.association(:foo)] }
 end
end
</code></pre>

blocks|key|1229486|text|Rails+5的更新：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1229487|您应该考虑：has_many+:through关联，而不是使用has_and_belongs_to_many关联。|offset|length|style|CODE|1229488|此关联的用户工厂如下所示：|1229489|FactoryBot.define+do
++factory+:user+do
++++#+user+attributes

++++factory+:user_with_companies+do
++++++transient+do
++++++++companies_count+10+#+default+number
++++++end

++++++after(:create)+do+%7Cuser,+evaluator%7C
+++++++++create_list(:companies,+evaluator.companies_count,+user:+user)
++++++end
++++end
++end
end|code-block|syntax|javascript|1229490|您可以用类似的方式创建公司工厂。|1229491|一旦设置了两个工厂，您就可以使用companies_count+option创建user_with_companies工厂。您可以在此处指定用户所属的公司数量：create(:user_with_companies,+companies_count:+15)|1229492|您可以找到有关factory+girl+associations+here的详细说明。|1229493|entityMap|0|LINK|mutability|MUTABLE|url|https://kolosek.com/factory-girl-associations^0|0|6|H|V|N|0|0|0|0|G|M|14|J|28|1D|0|7|U|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@$D|14|E|15|F|G]|$D|16|E|17|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|18|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|19|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@$D|1C|E|1D|F|G]|$D|1E|E|1F|F|G]|$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1I|8|@]|9|@$D|1J|E|1K|1|1L]]|A|$]]|$1|U|3|-4|5|6|7|1M|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

Update for Rails 5:

Instead of using <code>has_and_belongs_to_many</code> association, you should consider: <code>has_many :through</code> association.

The user factory for this association looks like this:

<pre><code>FactoryBot.define do
 factory :user do
 # user attributes

 factory :user_with_companies do
 transient do
 companies_count 10 # default number
 end

 after(:create) do |user, evaluator|
 create_list(:companies, evaluator.companies_count, user: user)
 end
 end
 end
end
</code></pre>

You can create the company factory in a similar way.

Once both factories are set, you can create <code>user_with_companies</code> factory with <code>companies_count option</code>. Here you can specify how many companies the user belongs to: <code>create(:user_with_companies, companies_count: 15)</code>

You can find detailed explanation about <a href="https://kolosek.com/factory-girl-associations" rel="nofollow noreferrer">factory girl associations here</a>.

blocks|key|1444465|text|您可以定义新工厂并使用after(:+create+)回调来创建关联列表。让我们在这个例子中看看如何做到这一点：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1444466|FactoryBot.define+do

++#+user+factory+without+associated+companies
++factory+:user+do
++++#+user+attributes

++++factory+:user_with_companies+do
++++++transient+do
++++++++companies_count+10
++++++end

++++++after(:create)+do+%7Cuser,+evaluator%7C
++++++++create_list(:companies,+evaluator.companies_count,+user:+user)
++++++end
++++end
++end
end|code-block|syntax|javascript|1444467|属性companies_count是暂时的，在工厂的属性和通过赋值器的回调中可用。现在，您可以创建一个包含公司的用户，该用户可以选择指定所需的公司数量：|1444468|create(:user_with_companies).companies.length+#+10
create(:user_with_companies,+companies_count:+15).companies.length+#+15|1444469|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can define new factory and use after(:create) callback to create a list of associations. Let's see how to do it in this example:

<pre><code>FactoryBot.define do

 # user factory without associated companies
 factory :user do
 # user attributes

 factory :user_with_companies do
 transient do
 companies_count 10
 end

 after(:create) do |user, evaluator|
 create_list(:companies, evaluator.companies_count, user: user)
 end
 end
 end
end
</code></pre>

Attribute companies_count is a transient and available in attributes of the factory and in the callback via the evaluator. Now, you can create a user with companies with the option to specify how many companies you want:

<pre><code>create(:user_with_companies).companies.length # 10
create(:user_with_companies, companies_count: 15).companies.length # 15
</code></pre>

Given the following

<pre><code>class User &lt; ActiveRecord::Base
 has_and_belongs_to_many :companies
end

class Company &lt; ActiveRecord::Base
 has_and_belongs_to_many :users
end
</code></pre>

how do you define factories for companies and users including the bidirectional association? Here's my attempt

<pre><code>Factory.define :company do |f|
 f.users{ |users| [users.association :company]}
end

Factory.define :user do |f|
 f.companies{ |companies| [companies.association :user]}
end
</code></pre>

now I try 

<pre><code>Factory :user
</code></pre>

Perhaps unsurprisingly this results in an infinite loop as the factories recursively use each other to define themselves.

More surprisingly I haven't found a mention of how to do this anywhere, is there a pattern for defining the necessary factories or I am doing something fundamentally wrong?

How to create has_and_belongs_to_many associations in Factory girl

考虑到以下情况class User < ActiveRecord::Base has_and_belongs_to_many :companiesendclass Company < ActiveRecord::Base has_and_belongs_to_many :usersend您如何为公司和用户定义工厂，...

问如何在工厂女孩中创建has_and_belongs_to_many关联
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