blocks|key|3173600|text|您不必自己序列化正文。只管去做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3173601|request.RequestFormat+=+DataFormat.Json;
request.AddJsonBody(new+{+A+=+"foo",+B+=+"bar"+});+//+Anonymous+type+object+is+converted+to+Json+body|code-block|syntax|javascript|3173602|如果你只是想要POST参数(它仍然会映射到你的模型，而且效率更高，因为没有序列化到JSON)，那么这样做：|3173603|request.AddParameter("A",+"foo");
request.AddParameter("B",+"bar");|3173604|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You don't have to serialize the body yourself. Just do
<pre><code>request.RequestFormat = DataFormat.Json;
request.AddJsonBody(new { A = &quot;foo&quot;, B = &quot;bar&quot; }); // Anonymous type object is converted to Json body
</code></pre>
If you just want POST params instead (which would still map to your model and is a lot more efficient since there's no serialization to JSON) do this:
<pre><code>request.AddParameter(&quot;A&quot;, &quot;foo&quot;);
request.AddParameter(&quot;B&quot;, &quot;bar&quot;);
</code></pre>

blocks|key|3173615|text|这就是对我有效的方法，对于我的情况，这是一个登录请求的post：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3173616|var+client+=+new+RestClient("http://www.example.com/1/2");
var+request+=+new+RestRequest();

request.Method+=+Method.POST;
request.AddHeader("Accept",+"application/json");
request.Parameters.Clear();
request.AddParameter("application/json",+body+,+ParameterType.RequestBody);

var+response+=+client.Execute(request);
var+content+=+response.Content;+//+raw+content+as+string++|code-block|syntax|javascript|3173617|正文：|3173618|{
++"userId":"sam@company.com"+,
++"password":"welcome"+
}|3173619|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is what worked for me, for my case it was a post for login request : 

<pre><code>var client = new RestClient("http://www.example.com/1/2");
var request = new RestRequest();

request.Method = Method.POST;
request.AddHeader("Accept", "application/json");
request.Parameters.Clear();
request.AddParameter("application/json", body , ParameterType.RequestBody);

var response = client.Execute(request);
var content = response.Content; // raw content as string 
</code></pre>

body :

<pre><code>{
 "userId":"sam@company.com" ,
 "password":"welcome" 
}
</code></pre>

blocks|key|265344|text|在当前版本的RestSharp+(105.2.3.0)中，您可以通过以下方式将JSON对象添加到请求体：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|265345|request.AddJsonBody(new+{+A+=+"foo",+B+=+"bar"+});|code-block|syntax|javascript|265346|此方法将内容类型设置为application/json，并将对象序列化为JSON字符串。|265347|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In the current version of RestSharp (105.2.3.0) you can add a JSON object to the request body with:

<pre><code>request.AddJsonBody(new { A = "foo", B = "bar" });
</code></pre>

This method sets content type to application/json and serializes the object to a JSON string.

blocks|key|268555|text|如果您有一个对象的List，您可以将它们序列化为JSON，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|268556|List<MyObjectClass>+listOfObjects+=+new+List<MyObjectClass>();|code-block|syntax|javascript|268557|然后使用addParameter|268558|requestREST.AddParameter("myAssocKey",+JsonConvert.SerializeObject(listOfObjects));|268559|，并且需要将请求格式设置为JSON。|268560|requestREST.RequestFormat+=+DataFormat.Json;|268561|entityMap^0|9|4|0|0|4|C|0|0|D|4|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|T|$]]

If you have a <code>List</code> of objects, you can serialize them to JSON as follow:

<pre><code>List&lt;MyObjectClass&gt; listOfObjects = new List&lt;MyObjectClass&gt;();
</code></pre>

And then use <code>addParameter</code>:

<pre><code>requestREST.AddParameter("myAssocKey", JsonConvert.SerializeObject(listOfObjects));
</code></pre>

And you wil need to set the request format to <code>JSON</code>:

<pre><code>requestREST.RequestFormat = DataFormat.Json;
</code></pre>

blocks|key|2959859|text|希望这能帮助到一些人。对我来说很管用-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2959860|RestClient+client+=+new+RestClient("http://www.example.com/");
RestRequest+request+=+new+RestRequest("login",+Method.POST);
request.AddHeader("Accept",+"application/json");
var+body+=+new
{
++++Host+=+"host_environment",
++++Username+=+"UserID",
++++Password+=+"Password"
};
request.AddJsonBody(body);

var+response+=+client.Execute(request).Content;|code-block|syntax|javascript|2959861|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Hope this will help someone. It worked for me -

<pre><code>RestClient client = new RestClient("http://www.example.com/");
RestRequest request = new RestRequest("login", Method.POST);
request.AddHeader("Accept", "application/json");
var body = new
{
 Host = "host_environment",
 Username = "UserID",
 Password = "Password"
};
request.AddJsonBody(body);

var response = client.Execute(request).Content;
</code></pre>

blocks|key|3173697|text|下面是完整的控制台工作应用程序代码。请安装RestSharp包。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3173698|using+RestSharp;
using+System;

namespace+RESTSharpClient
{
++++class+Program
++++{
++++++++static+void+Main(string[]+args)
++++++++{
++++++++string+url+=+"https://abc.example.com/";
++++++++string+jsonString+=+"{"+%2B
++++++++++++++++"\"auth\":+{"+%2B
++++++++++++++++++++"\"type\"+:+\"basic\","+%2B
++++++++++++++++++++"\"password\":+\"@P&p@y_10364\","+%2B
++++++++++++++++++++"\"username\":+\"prop_apiuser\""+%2B
++++++++++++++++"},"+%2B
++++++++++++++++"\"requestId\"+:+15,"+%2B
++++++++++++++++"\"method\":+{"+%2B
++++++++++++++++++++"\"name\":+\"getProperties\","+%2B
++++++++++++++++++++"\"params\":+{"+%2B
++++++++++++++++++++++++"\"showAllStatus\"+:+\"0\""+%2B
++++++++++++++++++++"}"+%2B
++++++++++++++++"}"+%2B
++++++++++++"}";

++++++++IRestClient+client+=+new+RestClient(url);
++++++++IRestRequest+request+=+new+RestRequest("api/properties",+Method.POST,+DataFormat.Json);
++++++++request.AddHeader("Content-Type",+"application/json;+CHARSET=UTF-8");
++++++++request.AddJsonBody(jsonString);

++++++++var+response+=+client.Execute(request);
++++++++Console.WriteLine(response.Content);
++++++++//TODO:+do+what+you+want+to+do+with+response.
++++}
++}
}|code-block|syntax|javascript|3173699|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is complete console working application code. Please install RestSharp package.
<pre><code>using RestSharp;
using System;

namespace RESTSharpClient
{
 class Program
 {
 static void Main(string[] args)
 {
 string url = &quot;https://abc.example.com/&quot;;
 string jsonString = &quot;{&quot; +
 &quot;\&quot;auth\&quot;: {&quot; +
 &quot;\&quot;type\&quot; : \&quot;basic\&quot;,&quot; +
 &quot;\&quot;password\&quot;: \&quot;@P&amp;p@y_10364\&quot;,&quot; +
 &quot;\&quot;username\&quot;: \&quot;prop_apiuser\&quot;&quot; +
 &quot;},&quot; +
 &quot;\&quot;requestId\&quot; : 15,&quot; +
 &quot;\&quot;method\&quot;: {&quot; +
 &quot;\&quot;name\&quot;: \&quot;getProperties\&quot;,&quot; +
 &quot;\&quot;params\&quot;: {&quot; +
 &quot;\&quot;showAllStatus\&quot; : \&quot;0\&quot;&quot; +
 &quot;}&quot; +
 &quot;}&quot; +
 &quot;}&quot;;

 IRestClient client = new RestClient(url);
 IRestRequest request = new RestRequest(&quot;api/properties&quot;, Method.POST, DataFormat.Json);
 request.AddHeader(&quot;Content-Type&quot;, &quot;application/json; CHARSET=UTF-8&quot;);
 request.AddJsonBody(jsonString);

 var response = client.Execute(request);
 Console.WriteLine(response.Content);
 //TODO: do what you want to do with response.
 }
 }
}
</code></pre>

blocks|key|3173743|text|您可能需要从请求体反序列化匿名JSON类型。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3173744|var+jsonBody+=+HttpContext.Request.Content.ReadAsStringAsync().Result;
ScoreInputModel+myDeserializedClass+=+JsonConvert.DeserializeObject<ScoreInputModel>(jsonBody);|code-block|syntax|javascript|3173745|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You might need to Deserialize your anonymous JSON type from the request body.
<pre><code>var jsonBody = HttpContext.Request.Content.ReadAsStringAsync().Result;
ScoreInputModel myDeserializedClass = JsonConvert.DeserializeObject&lt;ScoreInputModel&gt;(jsonBody);
</code></pre>

I am trying to make a very basic REST call to my MVC 3 API and the parameters I pass in are not binding to the action method.

Client

<pre><code>var request = new RestRequest(Method.POST);

request.Resource = "Api/Score";
request.RequestFormat = DataFormat.Json;

request.AddBody(request.JsonSerializer.Serialize(new { A = "foo", B = "bar" }));

RestResponse response = client.Execute(request);
Console.WriteLine(response.Content);
</code></pre>

Server

<pre><code>public class ScoreInputModel
{
 public string A { get; set; }
 public string B { get; set; }
}

// Api/Score
public JsonResult Score(ScoreInputModel input)
{
 // input.A and input.B are empty when called with RestSharp
}
</code></pre>

Am I missing something here?

RestSharp JSON Parameter Posting

服务器

JSON

我试图对我的MVC3API进行一个非常基本的REST调用，而我传入的参数并没有绑定到action方法。客户端var request = new RestRequest(Method.POST);request.Resource = "Api/Score";request.RequestFormat = DataForm...

问RestSharp JSON参数发布
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