blocks|key|68228|text|Express+API参考涵盖了这种情况。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|68229|参见status和send。|offset|length|68230|简而言之，您只需在调用json或send之前调用status方法|style|CODE|68231|res.status(500).send({+error:+"boo:("+});|code-block|syntax|javascript|68232|entityMap|0|LINK|mutability|MUTABLE|url|http://expressjs.com/en/4x/api.html#res.status|1|http://expressjs.com/en/4x/api.html#res.send^0|0|2|6|0|9|4|1|0|B|4|G|4|O|6|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@$D|10|E|11|1|12]|$D|13|E|14|1|15]]|A|$]]|$1|F|3|G|5|6|7|16|8|@$D|17|E|18|H|I]|$D|19|E|1A|H|I]|$D|1B|E|1C|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|1D|8|@]|9|@]|A|$M|N]]|$1|O|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

Express API reference covers this case.

See <a href="http://expressjs.com/en/4x/api.html#res.status" rel="noreferrer">status</a> and <a href="http://expressjs.com/en/4x/api.html#res.send" rel="noreferrer">send</a>.

In short, you just have to call the <code>status</code> method before calling <code>json</code> or <code>send</code>:

<pre><code>res.status(500).send({ error: "boo:(" });
</code></pre>

blocks|key|4574744|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4574745|res.status(400).json(json_response);|code-block|syntax|javascript|4574746|这会将HTTP状态码设置为400，即使在express+4中也可以使用。|4574747|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could do it this way:

<pre><code>res.status(400).json(json_response);
</code></pre>

This will set the HTTP status code to 400, it works even in express 4.

blocks|key|68296|text|res.status(500).jsonp(dataRes);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|68297|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>res.status(500).jsonp(dataRes);
</code></pre>

blocks|key|68312|text|我在我的Express.js应用程序中使用了以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|68313|app.get('/',+function+(req,+res)+{
++++res.status(200).json({
++++++++message:+'Welcome+to+the+project-name+api'
++++});
});|code-block|syntax|javascript|68314|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I am using this in my Express.js application:

<pre><code>app.get('/', function (req, res) {
 res.status(200).json({
 message: 'Welcome to the project-name api'
 });
});
</code></pre>

blocks|key|4574821|text|try+{
++var+data+=+{foo:+"bar"};
++res.json(JSON.stringify(data));
}
catch+(e)+{
++res.status(500).json(JSON.stringify(e));
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4574822|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>try {
 var data = {foo: "bar"};
 res.json(JSON.stringify(data));
}
catch (e) {
 res.status(500).json(JSON.stringify(e));
}
</code></pre>

blocks|key|4574859|text|你可以这样做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4574860|++++++++++++return+res.status(201).json({
++++++++++++++++statusCode:+req.statusCode,
++++++++++++++++method:+req.method,
++++++++++++++++message:+'Question+has+been+added'
++++++++++++});|code-block|syntax|javascript|4574861|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could do this

<pre><code> return res.status(201).json({
 statusCode: req.statusCode,
 method: req.method,
 message: 'Question has been added'
 });
</code></pre>

blocks|key|4574883|text|发送错误响应的最佳方式是return+res.status(400).send({+message:+'An+error+has+occurred'+})。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4574884|然后，在你的前端，你可以使用类似这样的东西来捕捉它：|4574885|++++++++url:+your_url,
++++++++method:+'POST',
++++++++headers:+headers,
++++++++data:+JSON.stringify(body),
++++})
++++++++.then((res)+=>+{
++++++++++++console.log('success',+res);
++++++++})
++++++++.catch((err)+=>+{
++++++++++++err.response+&&+err.response.data+&&+this.setState({+apiResponse:+err.response.data+})
++++++++})|code-block|syntax|javascript|4574886|由于您的已发送消息对象驻留在err.response.data中，因此只记录err是行不通的。|4574887|希望这能有所帮助！|4574888|entityMap^0|C|1T|0|0|0|E|H|12|3|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

The best way of sending an error response would be <code>return res.status(400).send({ message: 'An error has occurred' })</code>.

Then, in your frontend you can catch it using something like this:

<pre><code> url: your_url,
 method: 'POST',
 headers: headers,
 data: JSON.stringify(body),
 })
 .then((res) =&gt; {
 console.log('success', res);
 })
 .catch((err) =&gt; {
 err.response &amp;&amp; err.response.data &amp;&amp; this.setState({ apiResponse: err.response.data })
 })
</code></pre>

Just logging <code>err</code> won't work, as your sent message object resides in <code>err.response.data</code>.

Hope that helps!

blocks|key|68446|text|从版本4.9.0开始添加了res.sendStatus(status)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|68447|您可以使用以下res.sendStatus()+%7C%7C+res.status()方法之一|68448|下面是res.sendStatus()+%7C%7C+res.status()之间的区别|68449|res.sendStatus(200)+//+equivalent+to+res.status(200).send('OK')
res.sendStatus(403)+//+equivalent+to+res.status(403).send('Forbidden')
res.sendStatus(404)+//+equivalent+to+res.status(404).send('Not+Found')
res.sendStatus(500)+//+equivalent+to+res.status(500).send('Internal+Server+Error')|code-block|syntax|javascript|68450|我希望有人觉得这对我有帮助，谢谢|68451|entityMap^0|D|M|0|7|G|R|C|0|3|G|N|C|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|15|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|R|$]]

<code>res.sendStatus(status)</code> has been added as of version 4.9.0
you can use one of these <code>res.sendStatus()</code> || <code>res.status()</code> methods
below is difference in between <code>res.sendStatus()</code> || <code>res.status()</code>
<pre><code>
res.sendStatus(200) // equivalent to res.status(200).send('OK')
res.sendStatus(403) // equivalent to res.status(403).send('Forbidden')
res.sendStatus(404) // equivalent to res.status(404).send('Not Found')
res.sendStatus(500) // equivalent to res.status(500).send('Internal Server Error')

</code></pre>
I hope someone finds this helpful
thanks

blocks|key|68469|text|我没有看到有人提到res对象上方法调用的顺序很重要这一事实。我刚接触nodejs，一开始并没有意识到res.json()不仅仅是设置响应的正文。它实际上也会尝试推断响应状态。所以，如果这样做的话：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|68470|res.json({"message":+"Bad+parameters"})
res.status(400)|code-block|syntax|javascript|68471|第二行没有用，因为基于正确构建的json，express/nodejs已经推断出成功状态(200)。|68472|entityMap^0|9|3|Y|6|0|0|L|E|19|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

I don't see anyone mentioned the fact that the order of method calls on <code>res</code> object is important.
I'm new to <code>nodejs</code> and didn't realize at first that res.json() does more than just setting the body of the response. It actually tries to infer the response status as well. So, if done like so:
<pre><code>res.json({&quot;message&quot;: &quot;Bad parameters&quot;})
res.status(400)
</code></pre>
The second line would be of no use, because based on the correctly built json <code>express/nodejs</code> will already infer the success status(<code>200</code>).

I am playing around with Nodejs and express by building a small rest API. My question is, what is the good practice/best way to set the code status, as well as the response data?

Let me explain with a little bit of code (I will not put the node and express code necessary to start the server, just the router methods that are concerned):

<pre><code>router.get('/users/:id', function(req, res, next) {
 var user = users.getUserById(req.params.id);
 res.json(user);
});


exports.getUserById = function(id) {
 for (var i = 0; i &lt; users.length; i++) {
 if (users[i].id == id) return users[i];
 }
};
</code></pre>

The code below works perfectly, and when sending a request with Postman, I get the following result:
<img src="https://i.stack.imgur.com/0EMs8.png" alt="enter image description here">

As you can see, the status shows 200, which is OK. But is this the best way to do this? Is there a case where I should have to set the status myself, as well as the returned JSON? Or is that always handled by express?

For example, I just made a quick test and slightly modified the get method above:

<pre><code>router.get('/users/:id', function(req, res, next) {
 var user = users.getUserById(req.params.id);
 if (user == null || user == 'undefined') {
 res.status(404);
 }
 res.json(user);
});
</code></pre>

As you can see, if the user is not found in the array, I will just set a status of 404.

Resources/advices to learn more about this topic are more than welcome.

Proper way to set response status and JSON content in a REST API made with nodejs and express

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我通过构建一个小的rest API来尝试Nodejs和express。我的问题是，设置代码状态和响应数据的最佳实践/最佳方法是什么？让我用一些代码来解释(我不会放入启动服务器所需的节点和快速代码，只放入相关的路由器方法)：router.get('/users/:id', function(req, res, next)...

问在使用nodejs和express制作的REST API中设置响应状态和JSON内容的正确方法
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