在C#中的JSON格式化程序?

内容来源于 Stack Overflow,并遵循CC BY-SA 3.0许可协议进行翻译与使用

  • 回答 (2)
  • 关注 (0)
  • 查看 (61)

寻找一个函数,该函数需要一个string将JSON作为输入,并将其格式化为断行和缩进。验证将是一个额外的好处,但这并不是必要的,我也不需要将它解析为一个对象或任何东西。

有人知道这样的库吗?


样本输入:

{"status":"OK", "results":[ {"types":[ "locality", "political"], "formatted_address":"New York, NY, USA", "address_components":[ {"long_name":"New York", "short_name":"New York", "types":[ "locality", "political"]}, {"long_name":"New York", "short_name":"New York", "types":[ "administrative_area_level_2", "political"]}, {"long_name":"New York", "short_name":"NY", "types":[ "administrative_area_level_1", "political"]}, {"long_name":"United States", "short_name":"US", "types":[ "country", "political"]}], "geometry":{"location":{"lat":40.7143528, "lng":-74.0059731}, "location_type":"APPROXIMATE", "viewport":{"southwest":{"lat":40.5788964, "lng":-74.2620919}, "northeast":{"lat":40.8495342, "lng":-73.7498543}}, "bounds":{"southwest":{"lat":40.4773990, "lng":-74.2590900}, "northeast":{"lat":40.9175770, "lng":-73.7002720}}}}]} 
提问于
用户回答回答于

只需要一个扩展方法。最重要的是:修复了一些bug。

class JsonHelper
{
    private const string INDENT_STRING = "    ";
    public static string FormatJson(string str)
    {
        var indent = 0;
        var quoted = false;
        var sb = new StringBuilder();
        for (var i = 0; i < str.Length; i++)
        {
            var ch = str[i];
            switch (ch)
            {
                case '{':
                case '[':
                    sb.Append(ch);
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, ++indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    break;
                case '}':
                case ']':
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, --indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    sb.Append(ch);
                    break;
                case '"':
                    sb.Append(ch);
                    bool escaped = false;
                    var index = i;
                    while (index > 0 && str[--index] == '\\')
                        escaped = !escaped;
                    if (!escaped)
                        quoted = !quoted;
                    break;
                case ',':
                    sb.Append(ch);
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    break;
                case ':':
                    sb.Append(ch);
                    if (!quoted)
                        sb.Append(" ");
                    break;
                default:
                    sb.Append(ch);
                    break;
            }
        }
        return sb.ToString();
    }
}

static class Extensions
{
    public static void ForEach<T>(this IEnumerable<T> ie, Action<T> action)
    {
        foreach (var i in ie)
        {
            action(i);
        }
    }
}
用户回答回答于

您也可以使用Newtonsoft.Json库,并使用Formatting调用SerializeObject。

var x = JsonConvert.SerializeObject(jsonString, Formatting.Indented);

文件:序列化对象

void Main()
{
    //Example 1
    var t = "{\"x\":57,\"y\":57.0,\"z\":\"Yes\"}";
    var obj = Newtonsoft.Json.JsonConvert.DeserializeObject(t); 
    var f = Newtonsoft.Json.JsonConvert.SerializeObject(obj, Newtonsoft.Json.Formatting.Indented);
    Console.WriteLine(f);

    //Example 2
    JToken jt = JToken.Parse(t);
    string formatted = jt.ToString(Newtonsoft.Json.Formatting.Indented);
    Console.WriteLine(formatted);

    //Example 2 in one line -
    Console.WriteLine(JToken.Parse(t).ToString(Newtonsoft.Json.Formatting.Indented));
}

扫码关注云+社区