在JSON中获取webservice的400状态时返回false
在JSON中获取webservice的400状态时返回false
提问于 2015-05-05 22:09:06
在我的代码隐藏文件中，我调用了这个函数：
private void loginAction(object sender, TappedRoutedEventArgs e)
{
Webservice webservice = new Webservice();
webservice.getUser(txtLogin.Text, txtPass.Text);
}然后在webservice中，我这样做：
public void getUser(String user, String password)
{
String strUrl = String.Format("http://*******/nl/webservice/abc123/members/login?email={0}&password={1}",user,password);
startWebRequest(strUrl, loginCallback);
}
private async void loginCallback(IAsyncResult asyncResult)
{
try
{
ReceiveContext received = GetReceiveContextFromAsyncResult(asyncResult, "User");
if (received != null && received.Status == 200)
{
await UserDataSource.AddUser(received.Data);
}
else
{
throw new Exception("failedddd");
}
}
catch (Exception e)
{
}
}我现在想做的是当一个异常被抛出时，显示一个消息框。当我得到一个200的状态时，我导航到代码隐藏文件中的下一页。
我现在的问题是，我如何在我的代码隐藏文件中知道这一点？
首先要感谢大家！
编辑我也有这些助手方法：
#region HELPERS
private void startWebRequest(string url, AsyncCallback callback)
{
// HttpWebRequest.RegisterPrefix("http://",WebRequestCreator.ClientHttp);
HttpWebRequest httpWebRequest = (HttpWebRequest)HttpWebRequest.Create(new Uri(url));
// start the stream immediately
httpWebRequest.AllowReadStreamBuffering = false;
// asynchronously get a response
httpWebRequest.BeginGetResponse(callback, httpWebRequest);
}
private ReceiveContext GetReceiveContextFromAsyncResult(IAsyncResult asyncResult, string context)
{
// Request afleiding van de AsyncState uit het ontvangen AsyncResult
HttpWebRequest httpWebRequest = (HttpWebRequest)asyncResult.AsyncState;
HttpWebResponse httpWebResponse = null;
try
{
// Response afleiden uit de Resuest via de methode EndGetResponse();
httpWebResponse = (HttpWebResponse)httpWebRequest.EndGetResponse(asyncResult);
string responseString;
// using == IDisposable (automatische GC)
using (StreamReader readStream = new StreamReader(httpWebResponse.GetResponseStream()))
{ //Stream van de response gebruiken om een readstream te maken.
responseString = readStream.ReadToEnd();
}
// Release the HttpWebResponse
//httpWebResponse.Dispose();
return new ReceiveContext(int.Parse(responseString.Substring(10, 3)), responseString);
}
catch (WebException wex)
{
Debug.WriteLine(String.Format("{0} kon niet opgehaald worden: {1}", context, wex.Message));
}
catch (JsonReaderException jrex)
{
Debug.WriteLine(String.Format("{0} opgehaald van server, maar de json kon niet geparsed worden: {1}", context, jrex.Message));
}
catch (FormatException fex)
{
Debug.WriteLine(String.Format("{0} opgehaald van server, maar de gegevens kloppen niet: {1}", context, fex.Message));
}
catch (ArgumentOutOfRangeException arex)
{
Debug.WriteLine(String.Format("{0} opgehaald van server, maar de context is leeg: {1}", context, arex.Message));
}
return null;
}
public sealed class ReceiveContext
{
public ReceiveContext(int status, string data)
{
this.Status = status;
this.Data = data;
}
public int Status { get; private set; }
public string Data { get; private set; }
}
#endregion 回答 2
Stack Overflow用户
回答已采纳
发布于 2015-05-08 03:47:09
以下代码使用Windows.Web.Http.HttpClient接口(微软推荐使用此接口连接REST服务)
public class Result
{
public HttpStatusCode Status { get; set; }
public string Data { get; set; }
}
public async Task<Result> LoginAsync(string user, string password)
{
var http = new HttpClient();
var request = new HttpRequestMessage(HttpMethod.Get, new Uri("http://*******/nl/webservice/abc123/members/login?email="+ user + "&password="+ password));
var result = await http.SendRequestAsync(request);
var data = new Result {Status = result.StatusCode};
if (result.StatusCode== HttpStatusCode.Ok && result.Content!=null)
{
data.Data = await result.Content.ReadAsStringAsync();
}
return data;
}在你的代码中：
var result2 = await LoginAsync("", "");
if (result2.Status == HttpStatusCode.Ok)
{
//Status code 200
//navigate to other page
}
else if(result2.Status == HttpStatusCode.BadRequest)
{
//Status code 400
//your code
}Stack Overflow用户
发布于 2015-05-11 19:37:55
由于您得到了Json响应，因此建议您首先将Newtonsoft nuget包添加到您的项目中。
现在，我们以前常常添加一个服务引用，但是现在我们可以很容易地使用
var client = new HttpClient();
var response = await client.GetAsync(new Uri("http://*******/nl/webservice/abc123/members/login?email="+ user + "&password="+ password));
var resultlogin = await response.Content.ReadAsStringAsync(); //this is usually string type
var obj = JsonConvert.DeserializeObject<UserLogin.RootObject>(resultbrand);
//I usually define my own custom C# class using json2csharp.com or you can use Json.Deserialize also.
class UserLogin
{
public class User
{
public string UserName { get; set; }
public string Email { get; set; }
}
public class RootObject
{
public string tag { get; set; }
public int success { get; set; }
public int error { get; set; }
public string uid { get; set; }
public User User { get; set; }
}
} 现在，对于所使用的命名空间来说，最重要的应该是
using System.Net.Http;而不是
using Windows.Web.Http;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/30055363
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