我真的很难尝试将JSON文件读取到Swift中,这样我就可以使用它了。我已经花了2天的大部分时间重新搜索和尝试不同的方法,但到目前为止还没有运气,所以我注册了StackOverFlow,看看是否有人能给我指明正确的方向……
我的JSON文件名为test.json,其中包含以下内容:
{
"person":[
{
"name": "Bob",
"age": "16",
"employed": "No"
},
{
"name": "Vinny",
"age": "56",
"employed": "Yes"
}
]
}
该文件直接存储在文档中,我使用以下代码访问它:
let file = "test.json"
let dirs : String[] = NSSearchPathForDirectoriesInDomains(
NSSearchpathDirectory.DocumentDirectory,
NSSearchPathDomainMask.AllDomainMask,
true) as String[]
if (dirs != nil) {
let directories: String[] = dirs
let dir = directories[0]
let path = dir.stringByAppendingPathComponent(file)
}
var jsonData = NSData(contentsOfFile:path, options: nil, error: nil)
println("jsonData \(jsonData)" // This prints what looks to be JSON encoded data.
var jsonDict = NSJSONSerialization.JSONObjectWithData(jsonData, options: nil, error: nil) as? NSDictionary
println("jsonDict \(jsonDict)") - This prints nil.....
如果有人能给我一个正确的方向,告诉我如何反序列化JSON文件并将其放在一个可访问的Swift对象中,我将永远感激不尽!
致以亲切的问候,
克里夫文兹。
发布于 2014-06-25 22:10:37
遵循以下代码:
if let path = NSBundle.mainBundle().pathForResource("test", ofType: "json")
{
if let jsonData = NSData(contentsOfFile: path, options: .DataReadingMappedIfSafe, error: nil)
{
if let jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers, error: nil) as? NSDictionary
{
if let persons : NSArray = jsonResult["person"] as? NSArray
{
// Do stuff
}
}
}
}
“person”数组将包含关键人员的所有数据。遍历s以获取它。
Swift 4.0:
if let path = Bundle.main.path(forResource: "test", ofType: "json") {
do {
let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .mappedIfSafe)
let jsonResult = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
if let jsonResult = jsonResult as? Dictionary<String, AnyObject>, let person = jsonResult["person"] as? [Any] {
// do stuff
}
} catch {
// handle error
}
}
发布于 2020-05-12 11:15:55
Swift 5.1,Xcode 11
您可以使用以下命令:
struct Person : Codable {
let name: String
let lastName: String
let age: Int
}
func loadJson(fileName: String) -> Person? {
let decoder = JSONDecoder()
guard
let url = Bundle.main.url(forResource: fileName, withExtension: "json"),
let data = try? Data(contentsOf: url),
let person = try? decoder.decode(Person.self, from: data)
else {
return nil
}
return person
}
发布于 2019-02-24 03:28:38
简化Peter Kreinz提供的示例。适用于Swift 4.2。
扩展函数:
extension Decodable {
static func parse(jsonFile: String) -> Self? {
guard let url = Bundle.main.url(forResource: jsonFile, withExtension: "json"),
let data = try? Data(contentsOf: url),
let output = try? JSONDecoder().decode(self, from: data)
else {
return nil
}
return output
}
}
示例模型:
struct Service: Decodable {
let name: String
}
示例用法:
/// service.json
/// { "name": "Home & Garden" }
guard let output = Service.parse(jsonFile: "service") else {
// do something if parsing failed
return
}
// use output if all good
该示例也适用于数组:
/// services.json
/// [ { "name": "Home & Garden" } ]
guard let output = [Service].parse(jsonFile: "services") else {
// do something if parsing failed
return
}
// use output if all good
注意我们没有提供任何不必要的泛型,因此我们不需要转换parse的结果。
https://stackoverflow.com/questions/24410881
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