blocks|key|2916188|text|这是针对“正常年份”的。我认为你可以调整这个样本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2916189|string.Format("Q{0}",+(date.Month+%2B+2)/3);|code-block|syntax|javascript|2916190|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is for the "normal year". I think you can adapt the sample:

<pre><code>string.Format("Q{0}", (date.Month + 2)/3);
</code></pre>

blocks|key|244883|text|您可以简单地将扩展方法编写为DateTime|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244884|public+static+int+GetQuarter(this+DateTime+date)
{
++++if+(date.Month+>=+4+&&+date.Month+<=+6)
++++++++return+1;
++++else+if+(date.Month+>=+7+&&+date.Month+<=+9)
++++++++return+2;
++++else+if+(date.Month+>=+10+&&+date.Month+<=+12)
++++++++return+3;
++++else+
++++++++return+4;
}|code-block|syntax|javascript|244885|并将其用作|244886|DateTime+dt+=+DateTime.Now;
dt.GetQuarter();|244887|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can simply write an extension method to DateTime

<pre><code>public static int GetQuarter(this DateTime date)
{
 if (date.Month &gt;= 4 &amp;&amp; date.Month &lt;= 6)
 return 1;
 else if (date.Month &gt;= 7 &amp;&amp; date.Month &lt;= 9)
 return 2;
 else if (date.Month &gt;= 10 &amp;&amp; date.Month &lt;= 12)
 return 3;
 else 
 return 4;
}
</code></pre>

and use it as 

<pre><code>DateTime dt = DateTime.Now;
dt.GetQuarter();
</code></pre>

blocks|key|2916215|text|在sql中，它很简单|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2916216|((((month(@mydate)-1)/3)%2B3)+%25+4)+%2B+1|code-block|syntax|javascript|2916217|使用以下命令进行检查：|2916218|declare+@mydate+datetime
set+@mydate+=+'2011-01-01'
while+@mydate+<=+'2011-12-31'
++++begin
++++print+((((month(@mydate)-1)/3)%2B3)+%25+4)+%2B+1
++++set+@mydate+=+dateadd(month,+1,+@mydate)
++++end|2916219|或者，如果你想在.net中这样做，就像这样|2916220|String.Format("Q{0}",+((((date.Month-1)/3)%2B3)+%25+4)+%2B+1);|2916221|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

in sql, it's simply

<pre><code>((((month(@mydate)-1)/3)+3) % 4) + 1
</code></pre>

check it with this:

<pre><code>declare @mydate datetime
set @mydate = '2011-01-01'
while @mydate &lt;= '2011-12-31'
 begin
 print ((((month(@mydate)-1)/3)+3) % 4) + 1
 set @mydate = dateadd(month, 1, @mydate)
 end
</code></pre>

Or if you want to do it in .net, it's like 

<pre><code>String.Format("Q{0}", ((((date.Month-1)/3)+3) % 4) + 1);
</code></pre>

blocks|key|2916223|text|int+CurrentQuarter+=+(int)Math.Floor(((decimal)DateTime.Today.Month+%2B+2)+/+3);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2916224|或者将DateTime.Today更改为required+date。|unstyled|2916225|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>int CurrentQuarter = (int)Math.Floor(((decimal)DateTime.Today.Month + 2) / 3);
</code></pre>

or change the DateTime.Today to required date.

blocks|key|244889|text|扩展方法和更少的比较：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244890|public+static+class+DateTimeExtension
{
++++public+static+int+GetQuarter(this+DateTime+dateTime)
++++{
++++++++if+(dateTime.Month+<=+3)
++++++++++++return+1;

++++++++if+(dateTime.Month+<=+6)
++++++++++++return+2;

++++++++if+(dateTime.Month+<=+9)
++++++++++++return+3;

++++++++return+4;
++++}
}|code-block|syntax|javascript|244891|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Extension method and less comparisons:

<pre><code>public static class DateTimeExtension
{
 public static int GetQuarter(this DateTime dateTime)
 {
 if (dateTime.Month &lt;= 3)
 return 1;

 if (dateTime.Month &lt;= 6)
 return 2;

 if (dateTime.Month &lt;= 9)
 return 3;

 return 4;
 }
}
</code></pre>

blocks|key|241268|text|public+static+int+GetQuarter(DateTime+date)
{
++++int[]+quarters+=+new+int[]+{+4,4,4,1,1,1,2,2,2,3,3,3+};
++++return+quarters[date.Month-1];
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|241269|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public static int GetQuarter(DateTime date)
{
 int[] quarters = new int[] { 4,4,4,1,1,1,2,2,2,3,3,3 };
 return quarters[date.Month-1];
}
</code></pre>

blocks|key|3130579|text|如果你喜欢没有分支和数组的简短的解决方案，这里是我的首选解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3130580|正常季度：|3130581|public+static+int+GetQuarter(this+DateTime+date)
{
++++return+(date.Month+%2B+2)/3;
}|code-block|syntax|javascript|3130582|财政年度季度：|3130583|public+static+int+GetFinancialQuarter(this+DateTime+date)
{
++++return+(date.AddMonths(-3).Month+%2B+2)/3;
}|3130584|整数除法将截断小数，得到一个整数结果。将方法放入静态类中，您将拥有一个扩展方法，如下所示：|3130585|date.GetQuarter()
date.GetFinancialQuarter()|3130586|请参阅dotnetfiddle|offset|length|3130587|entityMap|0|LINK|mutability|MUTABLE|url|https://dotnetfiddle.net/LhJ9re^0|0|0|0|0|0|0|0|3|C|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|15|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|17|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|18|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|19|8|@]|9|@$S|1A|T|1B|1|1C]]|A|$]]|$1|U|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

If you prefer short and concise solutions without branching and arrays, here is my preferred solution.

Normal Quarter: 

<pre><code>public static int GetQuarter(this DateTime date)
{
 return (date.Month + 2)/3;
}
</code></pre>

Financial Year Quarter:

<pre><code>public static int GetFinancialQuarter(this DateTime date)
{
 return (date.AddMonths(-3).Month + 2)/3;
}
</code></pre>

Integer division will truncate decimals, giving you an integer result. Place methods into a static class and you will have an extension method to be used as follows:

<pre><code>date.GetQuarter()
date.GetFinancialQuarter()
</code></pre>

See <a href="https://dotnetfiddle.net/LhJ9re" rel="noreferrer">dotnetfiddle</a>

blocks|key|244921|text|您可以简单地执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244922|for+(int+i+=+1;+i+<=+12;+i%2B%2B)+{+
++++Console.WriteLine("Month+{0}+-+Q{1}",+i,+Math.Ceiling((i+<=+3+?+12+-+i+%2B+1+:+i+-+3)+/+3M));
}|code-block|syntax|javascript|244923|输出将为：|244924|📷|atomic|offset|length|244925|​|244926|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/83ac63592f5ebb4ce2d12ac9ce1091fb.png|imageAlt^0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|11|8|@]|9|@$L|12|M|13|1|14]]|A|$]]|$1|N|3|O|5|6|7|15|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W|X|-4]]]]

You can simply do this:

<pre><code>for (int i = 1; i &lt;= 12; i++) { 
 Console.WriteLine("Month {0} - Q{1}", i, Math.Ceiling((i &lt;= 3 ? 12 - i + 1 : i - 3) / 3M));
}
</code></pre>

The output will be:
<a href="https://i.stack.imgur.com/gI8cG.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/gI8cG.png" alt="enter image description here"></a>

blocks|key|2916359|text|实现这一点的最简单和一致的方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2916360|2916361|常规|offset|length|style|BOLD|2916362|Math.Ceiling(date.Month+/+3.0)|code-block|syntax|javascript|2916363|2916364|财务部(+2%2B1+quarters刚刚升级了一个模块)|2916365|Math.Ceiling(date.Month+/+3.0+%2B+2)+%25+4+%2B+1|2916366|2916367|01.01.2016+00:00:00+->+Q1+->+FQ4
01.02.2016+00:00:00+->+Q1+->+FQ4
01.03.2016+00:00:00+->+Q1+->+FQ4
01.04.2016+00:00:00+->+Q2+->+FQ1
01.05.2016+00:00:00+->+Q2+->+FQ1
01.06.2016+00:00:00+->+Q2+->+FQ1
01.07.2016+00:00:00+->+Q3+->+FQ2
01.08.2016+00:00:00+->+Q3+->+FQ2
01.09.2016+00:00:00+->+Q3+->+FQ2
01.10.2016+00:00:00+->+Q4+->+FQ3
01.11.2016+00:00:00+->+Q4+->+FQ3
01.12.2016+00:00:00+->+Q4+->+FQ3|2916368|Result是一个介于1和4之间的值。几乎任何环境都有CEIL函数，所以这也应该适用于任何语言。|2916369|entityMap^0|0|0|0|2|0|0|0|0|R|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|10|8|@]|9|@]|A|$]]|$1|C|3|D|5|6|7|11|8|@$E|12|F|13|G|H]]|9|@]|A|$]]|$1|I|3|J|5|K|7|14|8|@]|9|@]|A|$L|M]]|$1|N|3|-4|5|6|7|15|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|16|8|@$E|17|F|18|G|H]]|9|@]|A|$]]|$1|Q|3|R|5|K|7|19|8|@]|9|@]|A|$L|M]]|$1|S|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|T|3|U|5|K|7|1B|8|@]|9|@]|A|$L|M]]|$1|V|3|W|5|6|7|1C|8|@]|9|@]|A|$]]|$1|X|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|Y|$]]

The most simple and consistent way of achieving this:

<hr>

Regular

<pre><code>Math.Ceiling(date.Month / 3.0)
</code></pre>

<hr>

Fiscal (just shifted up with a mod by 2+1 quarters)

<pre><code>Math.Ceiling(date.Month / 3.0 + 2) % 4 + 1
</code></pre>

<hr>

<pre><code>01.01.2016 00:00:00 -&gt; Q1 -&gt; FQ4
01.02.2016 00:00:00 -&gt; Q1 -&gt; FQ4
01.03.2016 00:00:00 -&gt; Q1 -&gt; FQ4
01.04.2016 00:00:00 -&gt; Q2 -&gt; FQ1
01.05.2016 00:00:00 -&gt; Q2 -&gt; FQ1
01.06.2016 00:00:00 -&gt; Q2 -&gt; FQ1
01.07.2016 00:00:00 -&gt; Q3 -&gt; FQ2
01.08.2016 00:00:00 -&gt; Q3 -&gt; FQ2
01.09.2016 00:00:00 -&gt; Q3 -&gt; FQ2
01.10.2016 00:00:00 -&gt; Q4 -&gt; FQ3
01.11.2016 00:00:00 -&gt; Q4 -&gt; FQ3
01.12.2016 00:00:00 -&gt; Q4 -&gt; FQ3
</code></pre>

Result is a value between 1 and 4. Nearly any environment has a CEIL function, so this should work on any language as well.

blocks|key|2916383|text|此方法允许您指定季度的开始月份，并提供整个期间的年份。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2916384|++++public+string+GetQuarterPeriod(DateTime+date,+int+quarterStartMonth)
++++{
++++++++var+quarterDateOffset+=+date.AddMonths(1+-+quarterStartMonth);
++++++++return+$"Q{Math.Ceiling((decimal)quarterDateOffset.Month+/+3)}+{quarterDateOffset.Year}"+
+++++++++++++++%2B+(quarterStartMonth+==+1+?+""+:+$"/{quarterDateOffset.Year+%2B+1}");
++++}|code-block|syntax|javascript|2916385|给予：|2916386|GetQuarterPeriod(new+DateTime(2018,+4,+1),+4)+->+"Q1+2018/2019"
GetQuarterPeriod(new+DateTime(2018,+1,+1),+1)+->+"Q1+2018"|2916387|函数说明了这样一个事实:如果月份是1月(1)，则它仅限于一年。|2916388|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This method allows you to specify the start month of the quarter and also provides the year(s) for the period as a whole. 

<pre><code> public string GetQuarterPeriod(DateTime date, int quarterStartMonth)
 {
 var quarterDateOffset = date.AddMonths(1 - quarterStartMonth);
 return $"Q{Math.Ceiling((decimal)quarterDateOffset.Month / 3)} {quarterDateOffset.Year}" 
 + (quarterStartMonth == 1 ? "" : $"/{quarterDateOffset.Year + 1}");
 }
</code></pre>

Giving:

<pre><code>GetQuarterPeriod(new DateTime(2018, 4, 1), 4) -&gt; "Q1 2018/2019"
GetQuarterPeriod(new DateTime(2018, 1, 1), 1) -&gt; "Q1 2018"
</code></pre>

Function accounts for the fact that if the month is January (1) it is constrained to a single year.

blocks|key|243746|text|我来到这里，希望为给定的季度和年份的第一天创建一个DateTime+(可以理解，这与上面的问题相反，但却是相关的)，并采用了上面@wezzix的答案来创建：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|243747|public+DateTime+GetFirstDayOfQuarterFromYearAndQuarter(int+year,+int+quarter)
{
++++var+month+=+3+*+quarter+-+2;

++++return+new+DateTime(year,+month,+1);
}|code-block|syntax|javascript|243748|entityMap^0|P|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I came here looking to create a <code>DateTime</code> for the first day of a given a quarter and year (which is understandably the opposite of the question above, but related) and adopted @wezzix's answer above to create:

<pre class="lang-cs prettyprint-override"><code>public DateTime GetFirstDayOfQuarterFromYearAndQuarter(int year, int quarter)
{
 var month = 3 * quarter - 2;

 return new DateTime(year, month, 1);
}
</code></pre>

blocks|key|2916459|text|“数据结构或算法”(即Nicolaus+Wirth的“算法和数据结构”)。因此，我会避免任何计算，而只是查找它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2916460|private+static+readonly+Dictionary<int,+string>+FiscalQuarters+=+new+Dictionary<int,+string>
{
++++++++{1,+"Q4"},+{2,+"Q4"},+{3,+"Q4"},+
++++++++{4,+"Q1"},+{5,+"Q1"},+{6,+"Q1"},+
++++++++{7,+"Q2"},+{8,+"Q2"},+{9,+"Q2"},+
++++++++{10,+"Q3"},+{11,+"Q3"},+{12,+"Q3"}
};

public+static+void+Main()
{
++++var+a+=+new+DateTime(2020,+1,+26);++++++
++++Console.WriteLine(FiscalQuarters[a.Month]);
}|code-block|syntax|javascript|2916461|要进一步阅读，只需搜索“时间维度表”...|2916462|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

&quot;Data structures OR Algorithms&quot; (i.e. Nicolaus Wirth's &quot;Algorithms and Data Structures&quot; done right). I thus would avoid any calculation and instead would just look it up.
<pre><code>private static readonly Dictionary&lt;int, string&gt; FiscalQuarters = new Dictionary&lt;int, string&gt;
{
 {1, &quot;Q4&quot;}, {2, &quot;Q4&quot;}, {3, &quot;Q4&quot;}, 
 {4, &quot;Q1&quot;}, {5, &quot;Q1&quot;}, {6, &quot;Q1&quot;}, 
 {7, &quot;Q2&quot;}, {8, &quot;Q2&quot;}, {9, &quot;Q2&quot;}, 
 {10, &quot;Q3&quot;}, {11, &quot;Q3&quot;}, {12, &quot;Q3&quot;}
};

public static void Main()
{
 var a = new DateTime(2020, 1, 26); 
 Console.WriteLine(FiscalQuarters[a.Month]);
}
</code></pre>
For further reading just google &quot;time dimension table&quot;...

blocks|key|3130721|text|既然在C#中已经有了关系模式，就可以很容易地用一个switch表达式来编写它|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3130722|public+static+string+FiscalQuarter(this+DateTime+date)
{
++++var+qtr+=+date.Month+switch
++++{
++++++++<+4+=>+4,
++++++++<+7+=>+1,
++++++++<+10+=>+2,
++++++++_+=>+3
++++};
++++return+$"Q{qtr}";
}|code-block|syntax|javascript|3130723|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Now that you have relational patterns in C# it can easily be written in a single switch expression
<pre class="lang-cs prettyprint-override"><code>public static string FiscalQuarter(this DateTime date)
{
 var qtr = date.Month switch
 {
 &lt; 4 =&gt; 4,
 &lt; 7 =&gt; 1,
 &lt; 10 =&gt; 2,
 _ =&gt; 3
 };
 return $&quot;Q{qtr}&quot;;
}
</code></pre>

blocks|key|3130732|text|一年中我们有以下几个季度|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3130733|1=+(0或1或2)/3+%2B1|3130734|2=+(3、4或5)/3+%2B1|3130735|3=+(6、7或8)/3+%2B1|3130736|4=+(9、10或11)/3+%2B1|3130737|public+static+int+GetQuarter(this+DateTime+source)
{
+++return+(source.Month+-+1)+/+3+%2B+1;
}|code-block|syntax|javascript|3130738|entityMap^0|0|C|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@]|D|@]|E|$]]|$1|J|3|K|5|6|7|Z|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|10|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|11|8|@]|D|@]|E|$Q|R]]|$1|S|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|T|$]]

We have the following quarters in a year
1 = (0 or 1 or 2)/3 + 1
2 = (3 or 4 or 5)/3 + 1
3 = (6 or 7 or 8)/3 + 1
4 = (9 or 10 or 11)/3 + 1
<pre><code>public static int GetQuarter(this DateTime source)
{
 return (source.Month - 1) / 3 + 1;
}
</code></pre>

blocks|key|3130740|text|为什么不简单地使用Math.Ceiling来获取季度，然后决定你想要的特定季度是什么，看看这个：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3130741|var+quarter+=+(int)System.Math.Ceiling((decimal)DateTime.Now.Month/3);
var+arrayPosition+=+new+int[]+{+4,+1,+2,+3+};
var+result+=+arrayPosition[quarter+-+1];|code-block|syntax|javascript|3130742|entityMap^0|9|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

why not simply use <code>Math.Ceiling</code> to get quarter and then decide what you want for a particular quarter, see this:
<pre><code>var quarter = (int)System.Math.Ceiling((decimal)DateTime.Now.Month/3);
var arrayPosition = new int[] { 4, 1, 2, 3 };
var result = arrayPosition[quarter - 1];
</code></pre>

The following are the Quarters for a financial year 

<pre><code>April to June - Q1
July to Sep - Q2
Oct to Dec - Q3
Jan to March - Q4
</code></pre>

If the month of an input date lies as above I need the output for in terms of Quarter number.

For Example,

If I give an input date (say january 2nd) , I need the output as <code>Q4</code>.

If I give input as (Jun 5), output should give <code>Q1</code>.

Based on input date I need the Quarter number.

How do I discover the quarter of a given date

以下是一个财政年度的季度情况April to June          - Q1July to Sep            - Q2Oct to Dec             - Q3Jan to March           - Q4如果输入日期的月份如上所述，我需要在季度数字方面的输出。例如,如果我给出一个...

问如何查找给定日期的季度
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