blocks|key|864972|text|如果Lua脚本是由标准命令行解释器运行的，那么可以尝试使用arg[0]。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|864973|entityMap^0|T|6|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

If the Lua script is being run by the standard command line interpreter, then try <code>arg[0]</code>.

blocks|key|647985|text|这是一种更优雅的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|647986|function+script_path()
+++local+str+=+debug.getinfo(2,+"S").source:sub(2)
+++return+str:match("(.*/)")
end

print(script_path())|code-block|syntax|javascript|647987|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is a more elegant way:

<pre><code>function script_path()
 local str = debug.getinfo(2, "S").source:sub(2)
 return str:match("(.*/)")
end

print(script_path())
</code></pre>

blocks|key|865014|text|正如lhf所说：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|865015|~+e$+echo+"print(arg[0])"+>+test.lua
~+e$+lua+test.lua
test.lua
~+e$+cd+/
/+e$+lua+~/test.lua
/Users/e/test.lua
/+e$+|code-block|syntax|javascript|865016|下面是使用debug.getinfo机制的相同信息|865017|~+e$+echo+"function+foo+()+print(debug.getinfo(1).source)+end;+foo()"+>+test.lua
~+e$+lua+test.lua
@test.lua
~+e$+cd+/
/+e$+lua+~/test.lua
@/Users/e/test.lua
/+e$+|865018|这可以从C应用编程接口lua_getinfo获得|offset|length|865019|entityMap|0|LINK|mutability|MUTABLE|url|http://www.lua.org/manual/5.1/manual.html#lua_getinfo^0|0|0|0|0|B|B|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

As lhf says:

<pre><code>~ e$ echo "print(arg[0])" &gt; test.lua
~ e$ lua test.lua
test.lua
~ e$ cd /
/ e$ lua ~/test.lua
/Users/e/test.lua
/ e$ 
</code></pre>

Here's the same info using the debug.getinfo mechanism

<pre><code>~ e$ echo "function foo () print(debug.getinfo(1).source) end; foo()" &gt; test.lua
~ e$ lua test.lua
@test.lua
~ e$ cd /
/ e$ lua ~/test.lua
@/Users/e/test.lua
/ e$ 
</code></pre>

This is available from the C API <a href="http://www.lua.org/manual/5.1/manual.html#lua_getinfo" rel="noreferrer">lua_getinfo</a>

blocks|key|648044|text|我找到的最短的形式如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|648045|debug.getinfo(1).source:match("@?(.*/)")|code-block|syntax|javascript|648046|索引1，2-其他-取决于您想要查询的调用堆栈中的哪个函数。1是最后调用的函数(您所在的位置)。如果你是在全局环境中运行，那么2可能更合适(我还没有测试过)|648047|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Shortest form which I have found looks like this:

<pre><code>debug.getinfo(1).source:match("@?(.*/)")
</code></pre>

Index 1, 2- other - depends on which function in call stack you want to query. 1 is last called function (where you're in). If you're running in global context, then probably 2 is more appropriate (haven't tested by myself)

blocks|key|865167|text|得到你想要的东西的唯一可靠的方法是用你自己的这个函数版本替换dofile。即使是debug.getinfo方法也无法工作，因为它只返回传递给dofile的字符串。如果这是一个相对路径，它不知道它是如何转换成绝对路径的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|865168|重写的代码看起来像这样：|865169|local+function+CreateDoFile()
++++local+orgDoFile+=+dofile;

++++return+function(filename)
++++++++if(filename)+then+--can+be+called+with+nil.
++++++++++++local+pathToFile+=+extractFilePath(filename);
++++++++++++if(isRelativePath(pathToFile))+then
++++++++++++++++pathToFile+=+currentDir()+..+"/"+..+pathToFile;
++++++++++++end

++++++++++++--Store+the+path+in+a+global,+overwriting+the+previous+value.
++++++++++++path+=+pathToFile;+
++++++++end
++++++++return+orgDoFile(filename);+--proper+tail+call.
++++end
end

dofile+=+CreateDoFile();+//Override+the+old.|code-block|syntax|javascript|865170|函数extractFilePath、isRelativePath和currentDir不是Lua函数；您必须自己编写它们。extractFilePath函数从文件名中提取路径字符串。isRelativePath接受路径并返回给定路径是否为相对路径名。currentDir只是返回当前目录。此外，在Windows计算机上，您需要使用"\“而不是"/”。|865171|此函数将路径存储在名为path的全局变量中。您可以将其更改为您喜欢的任何内容。|865172|entityMap^0|U|6|14|D|1Y|6|0|0|0|2|F|I|E|X|A|1P|F|2J|E|3H|A|0|B|4|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1E|8|@$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|R|$]]

The only reliable way to get what you want is to replace <code>dofile</code> with your own version of this function. Even the <code>debug.getinfo</code> method won't work, because it will only return the string passed to <code>dofile</code>. If that was a relative path, it has no idea how it was converted to an absolute path.

The overriding code would look something like this:

<pre><code>local function CreateDoFile()
 local orgDoFile = dofile;

 return function(filename)
 if(filename) then --can be called with nil.
 local pathToFile = extractFilePath(filename);
 if(isRelativePath(pathToFile)) then
 pathToFile = currentDir() .. "/" .. pathToFile;
 end

 --Store the path in a global, overwriting the previous value.
 path = pathToFile; 
 end
 return orgDoFile(filename); --proper tail call.
 end
end

dofile = CreateDoFile(); //Override the old.
</code></pre>

The functions <code>extractFilePath</code>, <code>isRelativePath</code>, and <code>currentDir</code> are not Lua functions; you will have to write them yourself. The <code>extractFilePath</code> function pulls a path string out of a filename. <code>isRelativePath</code> takes a path and returns whether the given path is a relative pathname. <code>currentDir</code> simply returns the current directory. Also, you will need to use "\" instead of "/" on Windows machines.

This function stores the path in a global called <code>path</code>. You can change that to whatever you like.

blocks|key|865073|text|看看Lua调试库，它是标准Lua发行版的一部分。您可以使用debug.getinfo查找当前文件，或在调用堆栈上查找最多N帧的文件：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|865074|http://www.lua.org/manual/5.1/manual.html#5.9|offset|length|865075|请注意，这可能相当慢，所以如果您担心这样的事情，那么您不想在快速路径上执行此操作。|865076|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|19|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@$D|Q|E|R|1|S]]|A|$]]|$1|F|3|G|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|C]]]]

Have a look at the Lua debug library, which is part of the standard Lua distribution. You can use debug.getinfo to find the current file, or the file up N frames on the call stack:

<a href="http://www.lua.org/manual/5.1/manual.html#5.9" rel="nofollow">http://www.lua.org/manual/5.1/manual.html#5.9</a>

Note that this is probably fairly slow, so it is not something you want to do on the fast path if you are worried about such things.

blocks|key|865400|text|如果您想要实际路径：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|865401|path.dirname(path.abspath(debug.getinfo(1).short_src))|code-block|syntax|javascript|865402|否则，请使用下面的完整文件路径：|865403|path.abspath(debug.getinfo(1).short_src)|865404|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

if you want the actual path :

<pre><code>path.dirname(path.abspath(debug.getinfo(1).short_src))
</code></pre>

else use this for full file path :

<pre><code>path.abspath(debug.getinfo(1).short_src)
</code></pre>

blocks|key|648105|text|arg[0]:match('.*\\')|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|648106|如果返回nil，请尝试使用.*/更改.\*\\\，并使用debug.getinfo(1).short_src更改arg[0]。|unstyled|offset|length|style|CODE|648107|但我发现这是获取当前目录的最好和最短的方法。|648108|当然，您可以使用..操作符附加您正在查找的文件。它看起来像这样：|648109|arg[0]:match('.*\\')..'file.lua'|648110|entityMap^0|0|D|3|I|6|S|Q|1K|6|0|0|8|2|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@$G|U|H|V|I|J]|$G|W|H|X|I|J]|$G|Y|H|Z|I|J]|$G|10|H|11|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|13|8|@$G|14|H|15|I|J]]|9|@]|A|$]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$B|C]]|$1|Q|3|-4|5|F|7|17|8|@]|9|@]|A|$]]]|R|$]]

<pre><code>arg[0]:match('.*\\')
</code></pre>

If it returns nil try changing the <code>.\*\\\</code> with <code>.*/</code> and <code>arg[0]</code> with <code>debug.getinfo(1).short_src</code>.

But I find this to be the best and shortest way to get the current directory.

You can of course append the file you are looking for with the <code>..</code> operator. It will look something like this:

<pre><code>arg[0]:match('.*\\')..'file.lua'
</code></pre>

I am wondering if there is a way of getting the path to the currently executing lua script file? 

This is specifically not the current working directory, which could be entirely different. I know <a href="http://keplerproject.github.com/luafilesystem/index.html" rel="noreferrer">luafilesystem</a> will let me get the current working directory, but it doesn't seem to be able to tell the current executing script file.

Thanks

EDIT:
I'm not running from the standard command line interpreter, I am executing the scripts from a C++ binary via <a href="http://www.rasterbar.com/products/luabind.html" rel="noreferrer">luabind</a>.

Get containing path of lua file

我想知道是否有一种方法可以获得当前执行的lua脚本文件的路径？这特别不是当前的工作目录，它可能是完全不同的。我知道会让我得到当前的工作目录，但它似乎不能告诉我当前正在执行的脚本文件。谢谢编辑:我不是从标准的命令行解释器运行，而是通过从C++二进制文件执行脚本。

问Get包含lua文件的路径
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