我有以下HTML/JS/jQuery代码。此代码表示以模态方式呈现给用户以允许用户登录的登录表单。问题是,当我按回车键时,表单似乎没有执行"onsubmit“事件。当我单击作为表单底部的按钮(实际上与onsubmit事件具有相同的代码)时,它可以完美地工作。我想知道有没有人能告诉我为什么这个表格没有提交..?任何帮助都将不胜感激。
显示登录模式的jQuery代码:
showDivAndFocus('loginModal','loginaccount');
function showDivAndFocus(v,t){
if (api)
if (api.isOpened)
api.close();
api = $('#'+v).overlay({
mask: {color: '#000000'},
top:'0px',
api: true,
autoScrollToActive: false,
autoScrollOffset: 0
}).load();
document.getElementById(t).focus();
}
HTML代码
<div class="modal" id="loginModal">
<h2>User Login</h2>
<br />
<form action="javascript:void(0);" onsubmit="return(doLogin());" name="loginForm" id="loginForm">
<table width="95%" cellpadding="4" cellspacing="4">
<tr>
<td class="regw" align="left"><b>Account Number:</b></td>
<td class="regw" align="left"><input type="text" maxlength="10" size="10" name="loginaccount" id="loginaccount" /></td>
</tr>
<tr>
<td class="regw" align="left"><b>Username:</b></td>
<td class="regw" align="left"><input type="text" maxlength="20" size="20" name="loginusername" id="loginusername" /></td>
</tr>
<tr>
<td class="regw" align="left"><b>Password:</b></td>
<td class="regw" align="left"><input type="password" maxlength="20" size="20" name="loginpassword" id="loginpassword" /></td>
</tr>
<tr>
<td class="regw" align="left"><b>Remember Me:</b></td>
<td class="regw" align="left"><input type="checkbox" name="loginremember" id="loginremember" /></td>
</tr>
<tr><td colspan="2">
<div>
<center>
<table><tr><td width="50" valign="middle">
<div id="loginLoading" style="height:24px;width:24px;"></div>
</td><td>
<button onclick="doLogin();" type="button" class="ok">Submit</button>
</td><td>
<button onclick="api.close();" type="button" class="cancel">Cancel</button>
</td><td width="50"> </td></tr></table>
</center>
</div>
</td></tr>
</table>
</form>
</div>
AJAX调用
function doLogin(){
var ajax = getXmlObject();
var f = getFormVariables();
var url= '/login.php?f=' + encodeURIComponent(f);
if (ajax.readyState == 4 || ajax.readyState == 0) {
ajax.open("POST", url, true);
ajax.onreadystatechange = function () {
if (ajax.readyState == 4) {
var a = ajax.responseText;
if (a=="OK"){...} else {...}
}
};
ajax.send(null);
}
return false;
}
https://stackoverflow.com/questions/4196681
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