如何将十六进制RGB颜色代码转换为UIColor？
如何将十六进制RGB颜色代码转换为UIColor？
提问于 2010-09-27 23:12:52
我有一个像#ffffff这样的RGB十六进制代码作为NSString，并希望将其转换为UIColor。有没有简单的方法可以做到这一点？
回答 16
Stack Overflow用户
回答已采纳
发布于 2010-09-27 23:32:14
In some code of mine，我使用了两个不同的函数：
void SKScanHexColor(NSString * hexString, float * red, float * green, float * blue, float * alpha) {
NSString *cleanString = [hexString stringByReplacingOccurrencesOfString:@"#" withString:@""];
if([cleanString length] == 3) {
cleanString = [NSString stringWithFormat:@"%@%@%@%@%@%@",
[cleanString substringWithRange:NSMakeRange(0, 1)],[cleanString substringWithRange:NSMakeRange(0, 1)],
[cleanString substringWithRange:NSMakeRange(1, 1)],[cleanString substringWithRange:NSMakeRange(1, 1)],
[cleanString substringWithRange:NSMakeRange(2, 1)],[cleanString substringWithRange:NSMakeRange(2, 1)]];
}
if([cleanString length] == 6) {
cleanString = [cleanString stringByAppendingString:@"ff"];
}
unsigned int baseValue;
[[NSScanner scannerWithString:cleanString] scanHexInt:&baseValue];
if (red) { *red = ((baseValue >> 24) & 0xFF)/255.0f; }
if (green) { *green = ((baseValue >> 16) & 0xFF)/255.0f; }
if (blue) { *blue = ((baseValue >> 8) & 0xFF)/255.0f; }
if (alpha) { *alpha = ((baseValue >> 0) & 0xFF)/255.0f; }
}然后我像这样使用它：
UIColor * SKColorFromHexString(NSString * hexString) {
float red, green, blue, alpha;
SKScanHexColor(hexString, &red, &green, &blue, &alpha);
return [UIColor colorWithRed:red green:green blue:blue alpha:alpha];
}如果您更喜欢将其用作UIColor类别，那么只需更改几行代码：
+ (UIColor *) colorFromHexString:(NSString *)hexString {
NSString *cleanString = [hexString stringByReplacingOccurrencesOfString:@"#" withString:@""];
if([cleanString length] == 3) {
cleanString = [NSString stringWithFormat:@"%@%@%@%@%@%@",
[cleanString substringWithRange:NSMakeRange(0, 1)],[cleanString substringWithRange:NSMakeRange(0, 1)],
[cleanString substringWithRange:NSMakeRange(1, 1)],[cleanString substringWithRange:NSMakeRange(1, 1)],
[cleanString substringWithRange:NSMakeRange(2, 1)],[cleanString substringWithRange:NSMakeRange(2, 1)]];
}
if([cleanString length] == 6) {
cleanString = [cleanString stringByAppendingString:@"ff"];
}
unsigned int baseValue;
[[NSScanner scannerWithString:cleanString] scanHexInt:&baseValue];
float red = ((baseValue >> 24) & 0xFF)/255.0f;
float green = ((baseValue >> 16) & 0xFF)/255.0f;
float blue = ((baseValue >> 8) & 0xFF)/255.0f;
float alpha = ((baseValue >> 0) & 0xFF)/255.0f;
return [UIColor colorWithRed:red green:green blue:blue alpha:alpha];
}这将处理"#abc“、"#abcdef31”等字符串。
Stack Overflow用户
发布于 2010-09-27 23:27:34
如果您使用十六进制值..
#define UIColorFromRGB(rgbValue) [UIColor \
colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \
green:((float)((rgbValue & 0xFF00) >> 8))/255.0 \
blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]
//Then use any Hex value
self.view.backgroundColor = UIColorFromRGB(0xD2691E); Stack Overflow用户
发布于 2013-03-06 16:50:48
我正在寻找一个简单的解决方案，并想出了这个(不完全是Objective-C，但工作起来很棒)：
NSString *stringColor = @"#AABBCC";
NSUInteger red, green, blue;
sscanf([stringColor UTF8String], "#%02X%02X%02X", &red, &green, &blue);
UIColor *color = [UIColor colorWithRed:red/255.0 green:green/255.0 blue:blue/255.0 alpha:1];页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/3805177
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