移除集合中的模型并触发移除事件- backbone.js
移除集合中的模型并触发移除事件- backbone.js
提问于 2013-02-25 21:24:49
如何移除集合中的模型并激发移除事件。我试过people.remove([{ name: "joe3" }]);，但它不起作用。
var Person = Backbone.Model.extend({
initialize: function () {
console.log(" person is initialized");
},
defaults: {
name: "underfined",
age:"underfined"
}
});
var People = Backbone.Collection.extend({
initialize: function () {
console.log("people collection is initialized");
this.bind('add', this.onModelAdded, this);
this.bind('remove', this.onModelRemoved, this);
},
model: Person,
onModelAdded: function(model, collection, options) {
console.log("options = ", options);
alert("added");
},
onModelRemoved: function (model, collection, options) {
console.log("options = ", options);
alert("removed");
},
});
//var person = new Person({ name: "joe1" });
var people = new People();
//people.add([{ name: "joe2" }]);
people.add([{ name: "joe1" }]);
people.add([{ name: "joe2" }]);
people.add([{ name: "joe3" }]);
people.add([{ name: "joe4" }]);
people.add([{ name: "joe5" }]);
people.remove([{ name: "joe3" }]);
console.log(people.toJSON());回答 4
Stack Overflow用户
回答已采纳
发布于 2013-02-25 21:56:16
通过执行以下操作：
people.remove([{ name: "joe3" }]);您不能删除模型，因为您只传递了一个没有连接到people集合的普通对象。相反，您可以这样做：
people.remove(people.at(2));或者：
var model = new Person({name: "joe3"});
people.add(model);
...
people.remove(model);同样也会起作用。
因此，您需要引用集合中的实际模型对象；
Stack Overflow用户
发布于 2014-10-01 14:04:43
对于其他正在寻找remove where的人，只需使用collection.where调用将其链接即可。如下所示，删除与搜索匹配的所有项目：
people.remove(people.where({name: "joe3"}));Stack Overflow用户
发布于 2013-02-25 22:11:15
var Person = Backbone.Model.extend({
defaults: {
name: "underfined",
age:"underfined"
}
});
var People = Backbone.Collection.extend({
initialize: function () {
this.bind('remove', this.onModelRemoved, this);
},
model: Person,
onModelRemoved: function (model, collection, options) {
alert("removed");
},
getByName: function(name){
return this.filter(function(val) {
return val.get("name") === name;
})
}
});
var people = new People();
people.add(new Person({name:"joe1"}));
people.add(new Person({name:"joe2"}));
people.remove(people.getByName("joe1"));
console.info(people.toJSON());页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/15068036
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