blocks|key|276970|text|是的，用石膏：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|276971|((Activity)+ctx).finish();|code-block|syntax|javascript|276972|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

yes, with a cast:

<pre><code>((Activity) ctx).finish();
</code></pre>

blocks|key|3193684|text|在我的案例中，下面的工作是有效的，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3193685|我需要在AsyncTask+onPostExcute()中完成我的活动。|3193686|其中我的AsyncTask类是单独的公共类，它有一个带上下文参数的构造函数。|3193687|((Activity)(mContext)).finish();|code-block|syntax|javascript|3193688|只有上面的方法对我有效。不管怎样，我是从@2red13和@lucy+answers得到这个想法的。感谢所有人..。|3193689|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Q|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|R|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

In my Case following worked,

I need to finish my activity in a AsyncTask onPostExcute().

Where my AsyncTask class is separate public class , which has a constructor with param of Context.

<pre><code>((Activity)(mContext)).finish();
</code></pre>

Only the above worked for me... Anyway I got this idea from @2red13 and @lucy answers... Thanks to all...

blocks|key|3193761|text|我知道这是一个古老的帖子，但也许这样命名可能是个好主意：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3193762|if(context+instanceof+Activity){
++++++++++++++++((Activity)context).finish();+}|code-block|syntax|javascript|3193763|这样可以确保我们不会得到任何不必要的ClassCastExceptions|3193764|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I know it's an old post but, perhaps it could be a good idea to call it this way: 

<pre><code>if(context instanceof Activity){
 ((Activity)context).finish(); }
</code></pre>

This way we make sure we don't get any unnecesary ClassCastExceptions

blocks|key|273363|text|如果您有权访问要完成的活动的running视图(例如，您在单击监听程序中)，则可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273364|((Activity)getContext()).finish();|code-block|syntax|javascript|273365|(感谢2red13让我来到这里)。|273366|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you have access to the running view of the Activity you want to finish (for example, you are in a click listener), you could do:

<pre><code>((Activity)getContext()).finish();
</code></pre>

(With thanks to 2red13 to get me here).

blocks|key|277050|text|如果您使用以下命令启动活动：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|277051|startActivityForResult(i,+1);|code-block|syntax|javascript|277052|您可以调用finishActivity(1)来完成以该请求代码开始的任何活动，如下所示：|277053|((Activity)getContext()).finishActivity(1);|277054|在我的例子中，我需要在处理程序postDelayed中使用一个。使用这一点，你可以确定你正在完成的是哪项活动。希望它能帮上忙！|277055|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you start the activity using:

<pre><code>startActivityForResult(i, 1);
</code></pre>

you can call finishActivity(1) to finish any activities started with that request code, like this:

<pre><code>((Activity)getContext()).finishActivity(1);
</code></pre>

In my case I need to use one in a handler postDelayed. Using this you can be sure of which activity you are finishing. Hope it helps!

blocks|key|3193809|text|我在关闭偏好活动时也遇到了同样的问题。下面是我所做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3193810|public+class+T2DPreferenceActivity+extends+PreferenceActivity+{

++++@Override
++++public+void+onCreate(Bundle+savedInstanceState)+{
++++++++super.onCreate(savedInstanceState);
++++++++++getFragmentManager().beginTransaction().replace(android.R.id.content,
++++++++++++++++new+T2DPreferenceFragment()).commit();
++++}

++++public+static+class+T2DPreferenceFragment+extends+PreferenceFragment+{
++++++++@Override
++++++++public+void+onCreate(final+Bundle+savedInstanceState)+{
++++++++++++super.onCreate(savedInstanceState);
++++++++++++addPreferencesFromResource(R.xml.server_screen_preference);
++++++++++++Preference+testServicePreference+=+getPreferenceScreen().findPreference("PREFERRED+SERVER");
++++++++++++testServicePreference.setOnPreferenceChangeListener(new+Preference.OnPreferenceChangeListener()+{
++++++++++++++++@Override
++++++++++++++++public+boolean+onPreferenceChange(Preference+preference,+Object+newValue)+{
++++++++++++++++++++T2DPreferenceActivity.closeActivity(getActivity());
++++++++++++++++++++return+true;+//returning+true+still+makes+the+activity+handle+the+change+to+preferences
++++++++++++++++}
++++++++++++});
++++++++}

++++++++public+void+onViewCreated(View+view,+@Nullable+Bundle+savedInstanceState)+{
++++++++++++super.onViewCreated(view,+savedInstanceState);
++++++++++++ListView+lv+=+(ListView)view.findViewById(android.R.id.list);
++++++++++++ViewGroup+parent+=+(ViewGroup)lv.getParent();
++++++++++++parent.setPadding(0,+100,+0,+0);
++++++++}
++++}

++++protected+static+void+closeActivity(Activity+activity)+{
++++++++activity.finish();
++++}
}|code-block|syntax|javascript|3193811|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I had the same problem when closing a preference activity. Here is what I did:

<pre><code>public class T2DPreferenceActivity extends PreferenceActivity {

 @Override
 public void onCreate(Bundle savedInstanceState) {
 super.onCreate(savedInstanceState);
 getFragmentManager().beginTransaction().replace(android.R.id.content,
 new T2DPreferenceFragment()).commit();
 }

 public static class T2DPreferenceFragment extends PreferenceFragment {
 @Override
 public void onCreate(final Bundle savedInstanceState) {
 super.onCreate(savedInstanceState);
 addPreferencesFromResource(R.xml.server_screen_preference);
 Preference testServicePreference = getPreferenceScreen().findPreference("PREFERRED SERVER");
 testServicePreference.setOnPreferenceChangeListener(new Preference.OnPreferenceChangeListener() {
 @Override
 public boolean onPreferenceChange(Preference preference, Object newValue) {
 T2DPreferenceActivity.closeActivity(getActivity());
 return true; //returning true still makes the activity handle the change to preferences
 }
 });
 }

 public void onViewCreated(View view, @Nullable Bundle savedInstanceState) {
 super.onViewCreated(view, savedInstanceState);
 ListView lv = (ListView)view.findViewById(android.R.id.list);
 ViewGroup parent = (ViewGroup)lv.getParent();
 parent.setPadding(0, 100, 0, 0);
 }
 }

 protected static void closeActivity(Activity activity) {
 activity.finish();
 }
}
</code></pre>

blocks|key|277009|text|尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|277010|((Activity)+context.getApplicationContext()).finish();|code-block|syntax|javascript|277011|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try:

<pre><code>((Activity) context.getApplicationContext()).finish();
</code></pre>

If I have a reference to <code>Context</code>, is it possible to finish the current activity? 

I don't have the reference to current activity.

Close the current activity when you only have a reference to Context

如果我引用了Context，是否可以完成当前的活动？我没有对当前活动的引用。

问当您只有上下文引用时，请关闭当前活动
EN

回答 7

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问当您只有上下文引用时，请关闭当前活动EN

回答 7

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问当您只有上下文引用时，请关闭当前活动
EN