blocks|key|106635|text|'date‘命令不是更简单吗？不需要awk、stat等。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|106636|date+-r+<filename>|code-block|syntax|javascript|106637|此外，请考虑查看man+page中的日期格式；例如，使用常见的日期和时间格式：|offset|length|106638|date+-r+<filename>+"%2B%25m-%25d-%25Y+%25H:%25M:%25S"|106639|entityMap|0|LINK|mutability|MUTABLE|url|https://linux.die.net/man/1/date^0|0|0|8|8|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Isn't the 'date' command much simpler? No need for awk, stat, etc.

<pre><code>date -r &lt;filename&gt;
</code></pre>

Also, consider looking at the <a href="https://linux.die.net/man/1/date" rel="noreferrer">man page</a> for date formatting; for example with common date and time format:

<pre><code>date -r &lt;filename&gt; "+%m-%d-%Y %H:%M:%S"
</code></pre>

blocks|key|323736|text|或者，您也可以尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|323737|date+-r+filename+%2B"%25Y-%25m-%25d+%25H:%25M:%25S"|code-block|syntax|javascript|323738|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Alternatively, you may try also :
<pre><code>date -r filename +&quot;%Y-%m-%d %H:%M:%S&quot;
</code></pre>

blocks|key|106457|text|除了@StevePenny+answer，你可能想要删掉不那么人类可读的部分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|106458|stat+-c%25y+Localizable.strings+%7C+cut+-d'.'+-f1|code-block|syntax|javascript|106459|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Adding to @StevePenny answer, you might want to cut the not-so-human-readable part:

<pre><code>stat -c%y Localizable.strings | cut -d'.' -f1
</code></pre>

blocks|key|106576|text|编辑:结果是我忘记了$entry所需的引号，以便正确打印，并且没有给出“没有这样的文件或目录”错误。非常感谢你们对我的帮助！|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|106577|下面是我的最终代码：|106578|++++echo+"Please+type+in+the+directory+you+want+all+the+files+to+be+listed+with+last+modified+dates"+#bash+can't+find+file+creation+dates

read+directory

for+entry+in+"$directory"/*

do
modDate=$(stat+-c+%25y+"$entry")+#%25y+=+last+modified.+Qoutes+are+needed+otherwise+spaces+in+file+name+with+give+error+of+"no+such+file"
modDate=${modDate%25%25+*}+#%25%25+takes+off+everything+off+the+string+after+the+date+to+make+it+look+pretty
echo+$entry:$modDate|code-block|syntax|javascript|106579|打印结果如下：|106580|/home/joanne/Dropbox/cheat+sheet.docx:2012-03-14
/home/joanne/Dropbox/Comp:2013-05-05
/home/joanne/Dropbox/Comp+150+java.zip:2013-02-11
/home/joanne/Dropbox/Comp+151+Java+2.zip:2013-02-11
/home/joanne/Dropbox/Comp+162+Assembly+Language.zip:2013-02-11
/home/joanne/Dropbox/Comp+262+Comp+Architecture.zip:2012-12-12
/home/joanne/Dropbox/Comp+345+Image+Processing.zip:2013-02-11
/home/joanne/Dropbox/Comp+362+Operating+Systems:2013-05-05
/home/joanne/Dropbox/Comp+447+Societal+Issues.zip:2013-02-11|106581|entityMap^0|A|6|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

EDITED: turns out that I had forgotten the quotes needed for <code>$entry</code> in order to print correctly and not give the "no such file or directory" error. Thank you all so much for helping me!

Here is my final code:

<pre><code> echo "Please type in the directory you want all the files to be listed with last modified dates" #bash can't find file creation dates

read directory

for entry in "$directory"/*

do
modDate=$(stat -c %y "$entry") #%y = last modified. Qoutes are needed otherwise spaces in file name with give error of "no such file"
modDate=${modDate%% *} #%% takes off everything off the string after the date to make it look pretty
echo $entry:$modDate
</code></pre>

Prints out like this: 

<pre><code>/home/joanne/Dropbox/cheat sheet.docx:2012-03-14
/home/joanne/Dropbox/Comp:2013-05-05
/home/joanne/Dropbox/Comp 150 java.zip:2013-02-11
/home/joanne/Dropbox/Comp 151 Java 2.zip:2013-02-11
/home/joanne/Dropbox/Comp 162 Assembly Language.zip:2013-02-11
/home/joanne/Dropbox/Comp 262 Comp Architecture.zip:2012-12-12
/home/joanne/Dropbox/Comp 345 Image Processing.zip:2013-02-11
/home/joanne/Dropbox/Comp 362 Operating Systems:2013-05-05
/home/joanne/Dropbox/Comp 447 Societal Issues.zip:2013-02-11
</code></pre>

blocks|key|106656|text|对于换行符，我编辑了您的代码，以获得不带换行符的内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|106657|#!/bin/bash
for+i+in+/Users/anthonykiggundu/Sites/rku-it/*;+do
+++t=$(stat+-f+"%25Sm"++-t+"%25Y-%25m-%25d+%25H:%25M"+"$i")
+++echo+$t+:+"${i##*/}"++#+t+only+contains+date+last+modified,+then+only+filename+'grokked'-+else+$i+alone+is+abs.+path+++++++++++
done|code-block|syntax|javascript|106658|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For the line breaks i edited your code to get something with no line breaks. 

<pre><code>#!/bin/bash
for i in /Users/anthonykiggundu/Sites/rku-it/*; do
 t=$(stat -f "%Sm" -t "%Y-%m-%d %H:%M" "$i")
 echo $t : "${i##*/}" # t only contains date last modified, then only filename 'grokked'- else $i alone is abs. path 
done
</code></pre>

blocks|key|323549|text|如果文件名没有空格：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|323550|ls+-l+<dir>+%7C+awk+'{print+$6,+"+",+$7,+"+",+$8,+"+",+$9+}'|code-block|syntax|javascript|323551|这将以以下格式打印：|323552|+Dec+++21+++20:03+++a1.out
+Dec+++21+++20:04+++a.cpp|323553|如果文件名有空格(你也可以对没有空格的文件名使用下面的命令，只是它看起来比前者复杂/丑陋)：|323554|+ls+-l+<dir>+%7C+awk+'{printf+("%25s+%25s+%25s+",++$6,++$7,+$8);+for+(i=9;+++i<=NF;+i%2B%2B){+printf+("%25s+",+$i)};+printf+("\n")}'|323555|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

If file name has no spaces:

<pre><code>ls -l &lt;dir&gt; | awk '{print $6, " ", $7, " ", $8, " ", $9 }'
</code></pre>

This prints as the following format:

<pre><code> Dec 21 20:03 a1.out
 Dec 21 20:04 a.cpp
</code></pre>

If file names have space (you can use the following command for file names with no spaces too, just it looks complicated/ugly than the former):

<pre><code> ls -l &lt;dir&gt; | awk '{printf ("%s %s %s ", $6, $7, $8); for (i=9; i&lt;=NF; i++){ printf ("%s ", $i)}; printf ("\n")}'
</code></pre>

I can't seem to find how to print out the date of a file. I'm so far able to print out all the files in a directory, but I need to print out the dates with it. 

I know I need to attach a date format with the echo of the entry, but all I can't find the correct format.

<pre><code>echo "Please type in the directory you want all the files to be listed"

read directory 

for entry in "$directory"/*
do
 echo "$entry"
done
</code></pre>

Print a file's last modified date in Bash

Java

我似乎找不到如何打印文件日期的方法。到目前为止，我可以打印出一个目录中的所有文件，但我需要用它打印出日期。我知道我需要附加一个带有条目回显的日期格式，但我找不到正确的格式。echo "Please type in the directory you want all the files to be listed"read directory for entry in "$directory"/*d

问在Bash中打印文件的上次修改日期
EN

回答 6

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