blocks|key|997954|text|perl+-p+-i+-e+'s/\R//g;'+filename|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|997955|必须完成这项工作。|unstyled|997956|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>perl -p -i -e 's/\R//g;' filename
</code></pre>

Must do the job.

blocks|key|997851|text|paste+-sd+""+file.txt|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|997852|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>paste -sd "" file.txt
</code></pre>

blocks|key|1212310|text|您可以在vim中编辑该文件：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1212311|$+vim+inputfile
:%25s/\n//g|code-block|syntax|javascript|1212312|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can edit the file in vim:

<pre><code>$ vim inputfile
:%s/\n//g
</code></pre>

blocks|key|1212282|text|使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1212283|head+-n+1+filename+%7C+od+-c+|code-block|syntax|javascript|1212284|找出什么是令人不快的角色。然后使用|1212285|tr+-d+'\n'+<filename|1212286|对于LF|1212287|tr+-d+'\r\n'+<filename|1212288|对于CRLF|1212289|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

use 

<pre><code>head -n 1 filename | od -c 
</code></pre>

to figure WHAT is the offending character.
then use 

<pre><code>tr -d '\n' &lt;filename
</code></pre>

for LF

<pre><code>tr -d '\r\n' &lt;filename
</code></pre>

for CRLF

blocks|key|1212529|text|在previous+answer上扩展，这将删除所有新行并将结果保存到一个新文件中(感谢@tripleee)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1212530|tr+-d+'\n'+<+yourfile.txt+>+yourfile2.txt|code-block|syntax|javascript|1212531|这比“无用的猫”更好(见评论)：|1212532|cat+file.txt+%7C+tr+-d+'\n'+>+file2.txt|1212533|在删除文件末尾的新行时也很有用，例如使用echo+blah+>+file.txt创建。|style|CODE|1212534|请注意，目标文件名是不同的，重要的是，否则您将清除原始内容！|1212535|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/3134827/5362795^0|1|F|0|0|0|0|0|K|K|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|15|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|17|8|@$A|18|B|19|O|P]]|9|@]|C|$]]|$1|Q|3|R|5|6|7|1A|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]]]

Expanding on a <a href="https://stackoverflow.com/a/3134827/5362795">previous answer</a>, this removes all new lines and saves the result to a new file (thanks to @tripleee):
<pre><code>tr -d '\n' &lt; yourfile.txt &gt; yourfile2.txt
</code></pre>
Which is better than a &quot;useless cat&quot; (see comments):
<pre><code>cat file.txt | tr -d '\n' &gt; file2.txt
</code></pre>
Also useful for getting rid of new lines at the end of the file, e.g. created by using <code>echo blah &gt; file.txt</code>.
Note that the destination filename is different, important, otherwise you'll wipe out the original content!

blocks|key|998189|text|将sed与POSIX+classes一起使用|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|998190|这将删除所有只包含空格(空格和制表符)的行|998191|sed+'/%5E[[:space:]]*$/d'|style|CODE|998192|只需将您正在处理的任何内容通过管道传输到该应用程序|998193|示例|998194|cat+filename+%7C+sed+'/%5E[[:space:]]*$/d'|998195|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikibooks.org/wiki/Regular_Expressions/POSIX_Basic_Regular_Expressions^0|5|D|0|0|0|0|N|0|0|0|0|12|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|E|5|6|7|11|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|12|8|@$A|13|B|14|H|I]]|9|@]|C|$]]|$1|J|3|K|5|6|7|15|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|16|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|17|8|@$A|18|B|19|H|I]]|9|@]|C|$]]|$1|P|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|Q|$R|$5|S|T|U|C|$V|W]]]]

<h1>Use sed with <a href="https://en.wikibooks.org/wiki/Regular_Expressions/POSIX_Basic_Regular_Expressions" rel="nofollow noreferrer">POSIX classes</a></h1>

This will remove all lines containing only whitespace (spaces &amp; tabs) 

<h3><code>sed '/^[[:space:]]*$/d'</code></h3>

Just take whatever you are working with and pipe it to that

<h3>Example</h3>

<h3><code>cat filename | sed '/^[[:space:]]*$/d'</code></h3>

blocks|key|997942|text|使用man+1+ed：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|997943|#+cf.+http://wiki.bash-hackers.org/doku.php?id=howto:edit-ed+
ed+-s+file+<<<+$'1,$j\n,p'++#+print+to+stdout+
ed+-s+file+<<<+$'1,$j\nwq'++#+in-place+edit|code-block|syntax|javascript|997944|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using man 1 ed:

<pre><code># cf. http://wiki.bash-hackers.org/doku.php?id=howto:edit-ed 
ed -s file &lt;&lt;&lt; $'1,$j\n,p' # print to stdout 
ed -s file &lt;&lt;&lt; $'1,$j\nwq' # in-place edit
</code></pre>

blocks|key|1212191|text|如果数据为file.txt格式，则：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1212192|echo+$(<file.txt)+%7C+tr+-d+'+'|code-block|syntax|javascript|1212193|'$(<file.txt)‘读取文件，并以一系列单词的形式提供内容，然后'echo’在它们之间回显一个空格。然后，'tr‘命令将删除所有空格：|offset|length|style|CODE|1212194|22791;14336;22821;34653;21491;25522;33238;|1212195|entityMap^0|0|0|1|C|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

If the data is in file.txt, then:

<pre><code>echo $(&lt;file.txt) | tr -d ' '
</code></pre>

The '<code>$(&lt;file.txt)</code>' reads the file and gives the contents as a series of words which 'echo' then echoes with a space between them. The 'tr' command then deletes any spaces:

<pre><code>22791;14336;22821;34653;21491;25522;33238;
</code></pre>

blocks|key|1212253|text|xargs也会使用换行符(但会添加最后一个尾随换行符)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1212254|xargs+<+file.txt+%7C+tr+-d+'+'|code-block|syntax|javascript|1212255|entityMap^0|0|5|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

<code>xargs</code> consumes newlines as well (but adds a final trailing newline):

<pre><code>xargs &lt; file.txt | tr -d ' '
</code></pre>

blocks|key|998107|text|假设您只想保留数字和分号，假设没有主要的编码问题，下面的代码应该可以做到这一点，尽管它也会删除最后一个“换行符”：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|998108|$+tr+-cd+";0-9"|code-block|syntax|javascript|998109|您可以轻松地修改上面的内容以包含其他字符，例如，如果您想保留小数点、逗号等。|998110|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Assuming you only want to keep the digits and the semicolons, the following should do the trick assuming there are no major encoding issues, though it will also remove the very last "newline":

<pre><code>$ tr -cd ";0-9"
</code></pre>

You can easily modify the above to include other characters, e.g. if you want to retain decimal points, commas, etc.

blocks|key|998131|text|书呆子事实:改用ASCII。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|998132|tr+-d+'\012'+<+filename.extension+++|code-block|syntax|javascript|998133|(编辑因为我看不到有相同答案的答案，唯一不同的是我的答案是ASCII)|998134|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Nerd fact: use ASCII instead.

<pre><code>tr -d '\012' &lt; filename.extension 
</code></pre>

(Edited cause i didn't see the friggin' answer that had same solution, only difference was that mine had ASCII)

blocks|key|997888|text|我会用awk来做，例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|997889|awk+'/[0-9]%2B/+{+a+=+a+$0+";"+}+END+{+print+a+}'+file.txt|code-block|syntax|javascript|997890|(缺点是a在内存中“累积”)。|997891|编辑|997892|忘记printf了！所以也是如此|997893|awk+'/[0-9]%2B/+{+printf+"%25s;",+$0+}'+file.txt|997894|或者可能更好，它已经在使用awk的其他ans中提供了。|997895|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I would do it with awk, e.g.

<pre><code>awk '/[0-9]+/ { a = a $0 ";" } END { print a }' file.txt
</code></pre>

(a disadvantage is that a is "accumulated" in memory).

EDIT

Forgot about printf! So also

<pre><code>awk '/[0-9]+/ { printf "%s;", $0 }' file.txt
</code></pre>

or likely better, what it was already given in the other ans using awk.

blocks|key|1212475|text|同时删除文件末尾的尾随换行符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1212476|python+-c+"s=open('filename','r').read();open('filename',+'w').write(s.replace('\n',''))"|code-block|syntax|javascript|1212477|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To also remove the trailing newline at the end of the file

<pre><code>python -c "s=open('filename','r').read();open('filename', 'w').write(s.replace('\n',''))"
</code></pre>

I have the following data, and I need to put it all into one line.
I have this:
<pre><code>22791

;

14336

;

22821

;

34653

;

21491

;

25522

;

33238

;
</code></pre>
I need this:
<pre><code>22791;14336;22821;34653;21491;25522;33238;
</code></pre>
<hr />
<h1>EDIT</h1>
None of these commands is working perfectly.
Most of them let the data look like this:
<pre><code>22791

;14336

;22821

;34653

;21491

;25522
</code></pre>

How do I remove newlines from a text file?

我有以下数据，我需要将所有数据放在一行中。我有这个：22791;14336;22821;34653;21491;25522;33238;我需要这个：22791;14336;22821;34653;21491;25522;33238;编辑这些命令都不能完美地工作。它们中的大多数让数据看起来像这样：22791;14336;22821;34653;21491;25522

问如何从文本文件中删除换行符？
EN

回答 13

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问如何从文本文件中删除换行符？EN

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问如何从文本文件中删除换行符？
EN