Castle Active Record: SQL Express不工作。SQL Developer可以做到
Castle Active Record: SQL Express不工作。SQL Developer可以做到
提问于 2009-05-11 09:59:08
几天来，我一直在尝试排除城堡ActiveRecord异常的故障。每当我尝试访问数据库时，都会得到一个异常，其InnerException值为"An attempt to attach an auto-named database for file database.mdf failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share."
我正在尝试连接到SQL Server Express 2005数据库。我没有任何其他的数据库选项，因为学校的计算机上只有SQL Express。
我的连接设置
hibernate.connection.driver_class
NHibernate.Driver.SqlClientDriver
hibernate.dialect
NHibernate.Dialect.MsSql2005Dialect
hibernate.connection.provider
NHibernate.Connection.DriverConnectionProvider
hibernate.connection.connection_string
Data Source=.\SQLExpress;Integrated Security=True;User Instance=True;AttachDBFilename=database.mdf即使我将AttachDBFilename设置为绝对路径，这也无法工作。用户实例不起作用。数据库文件当前位于项目的根目录中，与我的WinForms类混合在一起。
在使用时
hibernate.connection.connection_string
Data Source=localhost;Initial Catalog=FinalApp;Integrated Security=True;Pooling=False在我的笔记本电脑上执行此操作没有问题，但我不能在学校计算机上使用SQL Server2005 Developer Edition。
请求的完整堆栈跟踪
Castle.ActiveRecord.Framework.ActiveRecordException was unhandled
Message="Could not perform FindAll for Book"
Source="Castle.ActiveRecord"
StackTrace:
at Castle.ActiveRecord.ActiveRecordBase.FindAll(Type targetType, Order[] orders, ICriterion[] criteria) in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.cs:line 1022
at Castle.ActiveRecord.ActiveRecordBase.FindAll(Type targetType) in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.cs:line 982
at Castle.ActiveRecord.ActiveRecordBase`1.FindAll() in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.Generic.cs:line 333
at CSharpFinal.InventoryMain.InventoryMain_Load(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\InventoryMain.cs:line 36
at System.Windows.Forms.Form.OnLoad(EventArgs e)
at System.Windows.Forms.Form.OnCreateControl()
at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible)
at System.Windows.Forms.Control.CreateControl()
at System.Windows.Forms.Control.WmShowWindow(Message& m)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ContainerControl.WndProc(Message& m)
at System.Windows.Forms.Form.WmShowWindow(Message& m)
at System.Windows.Forms.Form.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.SafeNativeMethods.ShowWindow(HandleRef hWnd, Int32 nCmdShow)
at System.Windows.Forms.Control.SetVisibleCore(Boolean value)
at System.Windows.Forms.Form.SetVisibleCore(Boolean value)
at System.Windows.Forms.Control.Show()
at CSharpFinal.Form1.inventoryToolStripMenuItem_Click(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Form1.cs:line 51
at System.Windows.Forms.ToolStripItem.RaiseEvent(Object key, EventArgs e)
at System.Windows.Forms.ToolStripMenuItem.OnClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleMouseUp(MouseEventArgs e)
at System.Windows.Forms.ToolStripItem.FireEventInteractive(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStripItem.FireEvent(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStrip.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.ToolStripDropDown.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ToolStrip.WndProc(Message& m)
at System.Windows.Forms.ToolStripDropDown.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(Int32 dwComponentID, Int32 reason, Int32 pvLoopData)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.Run(Form mainForm)
at CSharpFinal.Program.Main() in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Program.cs:line 17
at System.AppDomain.nExecuteAssembly(Assembly assembly, String[] args)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()
Castle.ActiveRecord.Framework.ActiveRecordException was unhandled
Message="Could not create the schema"
Source="Castle.ActiveRecord"
StackTrace:
at Castle.ActiveRecord.ActiveRecordStarter.CreateSchema() in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordStarter.cs:line 212
at CSharpFinal.Form1.reInitializeDatabaseToolStripMenuItem_Click(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Form1.cs:line 65
at System.Windows.Forms.ToolStripItem.RaiseEvent(Object key, EventArgs e)
at System.Windows.Forms.ToolStripMenuItem.OnClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleMouseUp(MouseEventArgs e)
at System.Windows.Forms.ToolStripItem.FireEventInteractive(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStripItem.FireEvent(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStrip.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.ToolStripDropDown.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ToolStrip.WndProc(Message& m)
at System.Windows.Forms.ToolStripDropDown.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(Int32 dwComponentID, Int32 reason, Int32 pvLoopData)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.Run(Form mainForm)
at CSharpFinal.Program.Main() in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Program.cs:line 17
at System.AppDomain.nExecuteAssembly(Assembly assembly, String[] args)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()InnerException.Message为"An attempt to attach an auto-named database for file database.mdf failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share."
回答 2
Stack Overflow用户
发布于 2009-05-11 11:01:35
可能是因为您SQL Express连接字符串正在关闭用户实例。如果您保持打开用户实例，那么SQL将在需要时附加数据库，如果没有，它将直接打开它。如果您将其关闭，则附加将永久存在。任何再次使用相同连接字符串的尝试都将导致错误，因为数据库已存在。
由于您尚未使用该连接字符串附加数据库，因此需要先分离数据库，然后才能使用正确的连接字符串。我建议您下载SQL management studio express，如果您还没有安装它的话。这将允许您查看已附加的数据库，并轻松地将其分离。
好的，如果这不是问题所在，那么SQL server可以访问数据库文件吗？它是否拥有该文件夹的权限？它通常作为网络服务运行，您可以像任何其他用户一样授予对文件的访问权限。您可以通过将完全控制权限授予每个人来消除文件权限问题，如果这解决了问题，那么您可以将权限调整为所需的权限。我猜测SQL server服务帐户将需要对.mdf文件的修改权限。我不知道它在哪里为用户实例数据库创建.ldf。它可能需要与.mdf位于同一文件夹中的create file权限。
Stack Overflow用户
发布于 2009-05-11 12:26:14
嗯，这只是一种猜测，但您需要指定数据库名称吗？( conn字符串中的初始目录)
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/849272
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